Strict stationarity of a process defined as the product of lags of another process
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Here is a problem that just occurred to me and that may be novel or interesting, at least I could find no trace on here. I have a short proof by contradiction in mind but it suffers from a limiting issue.
Assume $X_t$ is a discrete time stochastic process. Define the stochastic process $Y_t$ as $Y_t:=X_tX_t-1$.
1. Question. If $Y_t$ is strictly stationary, can we conclude that $X_t$ must be strictly stationary as well?
2. Follow-on question. How would the answer change if instead $Y_t:=X_tX_t-1X_t-2cdots$?
stochastic-processes stationary-processes
add a comment |Â
up vote
1
down vote
favorite
Here is a problem that just occurred to me and that may be novel or interesting, at least I could find no trace on here. I have a short proof by contradiction in mind but it suffers from a limiting issue.
Assume $X_t$ is a discrete time stochastic process. Define the stochastic process $Y_t$ as $Y_t:=X_tX_t-1$.
1. Question. If $Y_t$ is strictly stationary, can we conclude that $X_t$ must be strictly stationary as well?
2. Follow-on question. How would the answer change if instead $Y_t:=X_tX_t-1X_t-2cdots$?
stochastic-processes stationary-processes
Let $X_t$ alternate between zero and one deterministically.
â spaceisdarkgreen
Jul 20 at 19:30
Omg. Thanks a lot @spaceisdarkgreen.
â Martinigale
Jul 21 at 10:07
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Here is a problem that just occurred to me and that may be novel or interesting, at least I could find no trace on here. I have a short proof by contradiction in mind but it suffers from a limiting issue.
Assume $X_t$ is a discrete time stochastic process. Define the stochastic process $Y_t$ as $Y_t:=X_tX_t-1$.
1. Question. If $Y_t$ is strictly stationary, can we conclude that $X_t$ must be strictly stationary as well?
2. Follow-on question. How would the answer change if instead $Y_t:=X_tX_t-1X_t-2cdots$?
stochastic-processes stationary-processes
Here is a problem that just occurred to me and that may be novel or interesting, at least I could find no trace on here. I have a short proof by contradiction in mind but it suffers from a limiting issue.
Assume $X_t$ is a discrete time stochastic process. Define the stochastic process $Y_t$ as $Y_t:=X_tX_t-1$.
1. Question. If $Y_t$ is strictly stationary, can we conclude that $X_t$ must be strictly stationary as well?
2. Follow-on question. How would the answer change if instead $Y_t:=X_tX_t-1X_t-2cdots$?
stochastic-processes stationary-processes
asked Jul 20 at 18:34
Martinigale
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Let $X_t$ alternate between zero and one deterministically.
â spaceisdarkgreen
Jul 20 at 19:30
Omg. Thanks a lot @spaceisdarkgreen.
â Martinigale
Jul 21 at 10:07
add a comment |Â
Let $X_t$ alternate between zero and one deterministically.
â spaceisdarkgreen
Jul 20 at 19:30
Omg. Thanks a lot @spaceisdarkgreen.
â Martinigale
Jul 21 at 10:07
Let $X_t$ alternate between zero and one deterministically.
â spaceisdarkgreen
Jul 20 at 19:30
Let $X_t$ alternate between zero and one deterministically.
â spaceisdarkgreen
Jul 20 at 19:30
Omg. Thanks a lot @spaceisdarkgreen.
â Martinigale
Jul 21 at 10:07
Omg. Thanks a lot @spaceisdarkgreen.
â Martinigale
Jul 21 at 10:07
add a comment |Â
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Let $X_t$ alternate between zero and one deterministically.
â spaceisdarkgreen
Jul 20 at 19:30
Omg. Thanks a lot @spaceisdarkgreen.
â Martinigale
Jul 21 at 10:07