What is the right concept for completion of a sub-sigma algebra?

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Let $E$ be a set, $mathcalE$ a $sigma$-algebra on $E$ and $mu : mathcalE to [0, infty]$ a measure on $mathcalE$.



Set $mathcalN^mu := A subseteq E mid exists B in mathcalE, A subseteq B, mu(B) = 0 $ as the collection of subsets of $mu$-null sets. Then $mathcalE^mu := sigma(mathcalE cup mathcalN^mu)$ is the completion of $mathcalE$: it is the smallest $mu$-complete $sigma$-algebra larger than $mathcalE$.



Let $mathcalF subseteq mathcalE$ be a sub-$sigma$-algebra. Then the restriction $mu|_mathcalF : mathcalF to [0, infty]$ is a measure on $mathcalF$. Hence we can consider the $mu|_mathcalF$-completion $mathcalF^mu = sigma(mathcalF cup mathcalN^mu)$ of $mathcalF$.



I often see in books on stochastic processes also the following definition: $mathcalF^mu := sigma(mathcalF cup mathcalN^mu)$.
The difference is that in $mathcalF^mu$ we add in all (subsets of) $mu$-null sets of $mathcalE$ (and not only those of $mathcalF$).



It holds: $mathcalF^mu subseteq mathcalF^mu subseteq mathcalE^mu$ and all the inclusions may be strict. For an extreme case, just consider $mathcalF$ the trivial $sigma$-algebra.



What is the canonical or natural definition of a $mu$-completion of a sub-$sigma$-algebra - especially in the context of stochastic processes and completions of filtrations? (It would also be interesting to have an aswer in categorical terms, explaining the naturality of the construction.)







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    I think, we most often want to take the $sigma$-algebra of measurable sets as big as possible. That aligns with the second definition of completion of $mathcal F$, when an ambient $sigma$-algebra $mathcal E$ with an ambient measure is in our hands.
    – Berci
    Jul 21 at 23:40















up vote
2
down vote

favorite
1












Let $E$ be a set, $mathcalE$ a $sigma$-algebra on $E$ and $mu : mathcalE to [0, infty]$ a measure on $mathcalE$.



Set $mathcalN^mu := A subseteq E mid exists B in mathcalE, A subseteq B, mu(B) = 0 $ as the collection of subsets of $mu$-null sets. Then $mathcalE^mu := sigma(mathcalE cup mathcalN^mu)$ is the completion of $mathcalE$: it is the smallest $mu$-complete $sigma$-algebra larger than $mathcalE$.



Let $mathcalF subseteq mathcalE$ be a sub-$sigma$-algebra. Then the restriction $mu|_mathcalF : mathcalF to [0, infty]$ is a measure on $mathcalF$. Hence we can consider the $mu|_mathcalF$-completion $mathcalF^mu = sigma(mathcalF cup mathcalN^mu)$ of $mathcalF$.



I often see in books on stochastic processes also the following definition: $mathcalF^mu := sigma(mathcalF cup mathcalN^mu)$.
The difference is that in $mathcalF^mu$ we add in all (subsets of) $mu$-null sets of $mathcalE$ (and not only those of $mathcalF$).



It holds: $mathcalF^mu subseteq mathcalF^mu subseteq mathcalE^mu$ and all the inclusions may be strict. For an extreme case, just consider $mathcalF$ the trivial $sigma$-algebra.



What is the canonical or natural definition of a $mu$-completion of a sub-$sigma$-algebra - especially in the context of stochastic processes and completions of filtrations? (It would also be interesting to have an aswer in categorical terms, explaining the naturality of the construction.)







share|cite|improve this question















  • 2




    I think, we most often want to take the $sigma$-algebra of measurable sets as big as possible. That aligns with the second definition of completion of $mathcal F$, when an ambient $sigma$-algebra $mathcal E$ with an ambient measure is in our hands.
    – Berci
    Jul 21 at 23:40













up vote
2
down vote

favorite
1









up vote
2
down vote

favorite
1






1





Let $E$ be a set, $mathcalE$ a $sigma$-algebra on $E$ and $mu : mathcalE to [0, infty]$ a measure on $mathcalE$.



Set $mathcalN^mu := A subseteq E mid exists B in mathcalE, A subseteq B, mu(B) = 0 $ as the collection of subsets of $mu$-null sets. Then $mathcalE^mu := sigma(mathcalE cup mathcalN^mu)$ is the completion of $mathcalE$: it is the smallest $mu$-complete $sigma$-algebra larger than $mathcalE$.



Let $mathcalF subseteq mathcalE$ be a sub-$sigma$-algebra. Then the restriction $mu|_mathcalF : mathcalF to [0, infty]$ is a measure on $mathcalF$. Hence we can consider the $mu|_mathcalF$-completion $mathcalF^mu = sigma(mathcalF cup mathcalN^mu)$ of $mathcalF$.



I often see in books on stochastic processes also the following definition: $mathcalF^mu := sigma(mathcalF cup mathcalN^mu)$.
The difference is that in $mathcalF^mu$ we add in all (subsets of) $mu$-null sets of $mathcalE$ (and not only those of $mathcalF$).



It holds: $mathcalF^mu subseteq mathcalF^mu subseteq mathcalE^mu$ and all the inclusions may be strict. For an extreme case, just consider $mathcalF$ the trivial $sigma$-algebra.



What is the canonical or natural definition of a $mu$-completion of a sub-$sigma$-algebra - especially in the context of stochastic processes and completions of filtrations? (It would also be interesting to have an aswer in categorical terms, explaining the naturality of the construction.)







share|cite|improve this question











Let $E$ be a set, $mathcalE$ a $sigma$-algebra on $E$ and $mu : mathcalE to [0, infty]$ a measure on $mathcalE$.



Set $mathcalN^mu := A subseteq E mid exists B in mathcalE, A subseteq B, mu(B) = 0 $ as the collection of subsets of $mu$-null sets. Then $mathcalE^mu := sigma(mathcalE cup mathcalN^mu)$ is the completion of $mathcalE$: it is the smallest $mu$-complete $sigma$-algebra larger than $mathcalE$.



Let $mathcalF subseteq mathcalE$ be a sub-$sigma$-algebra. Then the restriction $mu|_mathcalF : mathcalF to [0, infty]$ is a measure on $mathcalF$. Hence we can consider the $mu|_mathcalF$-completion $mathcalF^mu = sigma(mathcalF cup mathcalN^mu)$ of $mathcalF$.



I often see in books on stochastic processes also the following definition: $mathcalF^mu := sigma(mathcalF cup mathcalN^mu)$.
The difference is that in $mathcalF^mu$ we add in all (subsets of) $mu$-null sets of $mathcalE$ (and not only those of $mathcalF$).



It holds: $mathcalF^mu subseteq mathcalF^mu subseteq mathcalE^mu$ and all the inclusions may be strict. For an extreme case, just consider $mathcalF$ the trivial $sigma$-algebra.



What is the canonical or natural definition of a $mu$-completion of a sub-$sigma$-algebra - especially in the context of stochastic processes and completions of filtrations? (It would also be interesting to have an aswer in categorical terms, explaining the naturality of the construction.)









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asked Jul 20 at 14:02









yadaddy

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  • 2




    I think, we most often want to take the $sigma$-algebra of measurable sets as big as possible. That aligns with the second definition of completion of $mathcal F$, when an ambient $sigma$-algebra $mathcal E$ with an ambient measure is in our hands.
    – Berci
    Jul 21 at 23:40













  • 2




    I think, we most often want to take the $sigma$-algebra of measurable sets as big as possible. That aligns with the second definition of completion of $mathcal F$, when an ambient $sigma$-algebra $mathcal E$ with an ambient measure is in our hands.
    – Berci
    Jul 21 at 23:40








2




2




I think, we most often want to take the $sigma$-algebra of measurable sets as big as possible. That aligns with the second definition of completion of $mathcal F$, when an ambient $sigma$-algebra $mathcal E$ with an ambient measure is in our hands.
– Berci
Jul 21 at 23:40





I think, we most often want to take the $sigma$-algebra of measurable sets as big as possible. That aligns with the second definition of completion of $mathcal F$, when an ambient $sigma$-algebra $mathcal E$ with an ambient measure is in our hands.
– Berci
Jul 21 at 23:40
















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