Extract a vector that is in the middle of a matrix equation

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So I have the following problem that is giving me a hard time for some reason:



I have a matrix equation of the form $RA(I-alpha e')$ where



  • $R$ is an $n times n$ matrix

  • $A$ is a triangular $n times n$ matrix

  • $I$ is the $n times n$ identity matrix

  • $alpha$ is a $n times 1$ vector and

  • $e'$ is a $1 times n$ vector of ones.

Clearly this equation is some linear mapping $f(alpha)$. I am now wondering if (and if yes how) it is possible to rewrite this equation into the form.



$f(alpha) = Xalpha$?



I have been thinking and trying and researching but I wasn't able to come up with a good answer.



Thank you!
Rob







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    up vote
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    So I have the following problem that is giving me a hard time for some reason:



    I have a matrix equation of the form $RA(I-alpha e')$ where



    • $R$ is an $n times n$ matrix

    • $A$ is a triangular $n times n$ matrix

    • $I$ is the $n times n$ identity matrix

    • $alpha$ is a $n times 1$ vector and

    • $e'$ is a $1 times n$ vector of ones.

    Clearly this equation is some linear mapping $f(alpha)$. I am now wondering if (and if yes how) it is possible to rewrite this equation into the form.



    $f(alpha) = Xalpha$?



    I have been thinking and trying and researching but I wasn't able to come up with a good answer.



    Thank you!
    Rob







    share|cite|improve this question





















      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      So I have the following problem that is giving me a hard time for some reason:



      I have a matrix equation of the form $RA(I-alpha e')$ where



      • $R$ is an $n times n$ matrix

      • $A$ is a triangular $n times n$ matrix

      • $I$ is the $n times n$ identity matrix

      • $alpha$ is a $n times 1$ vector and

      • $e'$ is a $1 times n$ vector of ones.

      Clearly this equation is some linear mapping $f(alpha)$. I am now wondering if (and if yes how) it is possible to rewrite this equation into the form.



      $f(alpha) = Xalpha$?



      I have been thinking and trying and researching but I wasn't able to come up with a good answer.



      Thank you!
      Rob







      share|cite|improve this question











      So I have the following problem that is giving me a hard time for some reason:



      I have a matrix equation of the form $RA(I-alpha e')$ where



      • $R$ is an $n times n$ matrix

      • $A$ is a triangular $n times n$ matrix

      • $I$ is the $n times n$ identity matrix

      • $alpha$ is a $n times 1$ vector and

      • $e'$ is a $1 times n$ vector of ones.

      Clearly this equation is some linear mapping $f(alpha)$. I am now wondering if (and if yes how) it is possible to rewrite this equation into the form.



      $f(alpha) = Xalpha$?



      I have been thinking and trying and researching but I wasn't able to come up with a good answer.



      Thank you!
      Rob









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      asked Jul 20 at 17:09









      korpuskel91

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          I don't think so, the second equation you're writing should output a vector (if $X$ is a matrix), while the first equation you're writing should output a matrix. Also the first equation is not linear but affine ($f(v+w)neq f(v)+f(w)$ for $v,winmathbbR^ntimes1$).






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            I don't think so, the second equation you're writing should output a vector (if $X$ is a matrix), while the first equation you're writing should output a matrix. Also the first equation is not linear but affine ($f(v+w)neq f(v)+f(w)$ for $v,winmathbbR^ntimes1$).






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              up vote
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              I don't think so, the second equation you're writing should output a vector (if $X$ is a matrix), while the first equation you're writing should output a matrix. Also the first equation is not linear but affine ($f(v+w)neq f(v)+f(w)$ for $v,winmathbbR^ntimes1$).






              share|cite|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                I don't think so, the second equation you're writing should output a vector (if $X$ is a matrix), while the first equation you're writing should output a matrix. Also the first equation is not linear but affine ($f(v+w)neq f(v)+f(w)$ for $v,winmathbbR^ntimes1$).






                share|cite|improve this answer













                I don't think so, the second equation you're writing should output a vector (if $X$ is a matrix), while the first equation you're writing should output a matrix. Also the first equation is not linear but affine ($f(v+w)neq f(v)+f(w)$ for $v,winmathbbR^ntimes1$).







                share|cite|improve this answer













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                share|cite|improve this answer











                answered Jul 20 at 17:34









                Stef

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