Examples of the Carathéodory extension theorem

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What are examples of the Carathéodory Extension Theorem that is not Lebesgue measure or Hausdorff measure?







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    What are examples of the Carathéodory Extension Theorem that is not Lebesgue measure or Hausdorff measure?







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      What are examples of the Carathéodory Extension Theorem that is not Lebesgue measure or Hausdorff measure?







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      What are examples of the Carathéodory Extension Theorem that is not Lebesgue measure or Hausdorff measure?









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      edited Aug 2 at 18:31
























      asked Aug 2 at 18:23









      user109871

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          One very important example is the construction of product measures. Given measures $mu$ and $nu$ on measurable spaces $X$ and $Y$, we seek to define a product measure $mutimes nu$ on $Xtimes Y$. Now, it is easy to define what this product measure should be on rectangles: if $Asubseteq X$ and $Bsubseteq Y$ are measurable, then $(mutimesnu)(Atimes B)$ should be $mu(A)nu(B)$ (just like the usual formula for the area of a rectangle in the plane). This can then be extended to finite unions of rectangles, and then the Caratheodory extension theorem can be used to extend it to a measure defined on the entire $sigma$-algebra generated by such rectangles.






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          • Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
            – user109871
            Aug 2 at 18:47






          • 1




            Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
            – Eric Wofsey
            Aug 2 at 18:53

















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          The concept of a cumulative distribution functions (cdf) is closely related to Carathéodory Extension Theorem. The construction is fairly similar to the Lebesgue measure though.



          Let $P$ be a probability measure on $(mathbbR, mathcalBmathbbR)$. The cdf of $P$ is the function $$F: mathbbR rightarrow [0,1], x mapsto P((-infty, x]).$$ Given the measure $P$, one can obviously construct $F$, but $F$ can also be used to reconstruct $P$:



          Given a cdf $F$. The according probability measure $P$ is the unique measure on $(mathbbR, mathcalBmathbbR)$, such that $P((a,b]) = F(b)-F(a)$. One can prove that $P$ exists and that it is unique, using the Carathéodory Extension Theorem.






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            2 Answers
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            2 Answers
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            up vote
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            One very important example is the construction of product measures. Given measures $mu$ and $nu$ on measurable spaces $X$ and $Y$, we seek to define a product measure $mutimes nu$ on $Xtimes Y$. Now, it is easy to define what this product measure should be on rectangles: if $Asubseteq X$ and $Bsubseteq Y$ are measurable, then $(mutimesnu)(Atimes B)$ should be $mu(A)nu(B)$ (just like the usual formula for the area of a rectangle in the plane). This can then be extended to finite unions of rectangles, and then the Caratheodory extension theorem can be used to extend it to a measure defined on the entire $sigma$-algebra generated by such rectangles.






            share|cite|improve this answer





















            • Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
              – user109871
              Aug 2 at 18:47






            • 1




              Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
              – Eric Wofsey
              Aug 2 at 18:53














            up vote
            3
            down vote













            One very important example is the construction of product measures. Given measures $mu$ and $nu$ on measurable spaces $X$ and $Y$, we seek to define a product measure $mutimes nu$ on $Xtimes Y$. Now, it is easy to define what this product measure should be on rectangles: if $Asubseteq X$ and $Bsubseteq Y$ are measurable, then $(mutimesnu)(Atimes B)$ should be $mu(A)nu(B)$ (just like the usual formula for the area of a rectangle in the plane). This can then be extended to finite unions of rectangles, and then the Caratheodory extension theorem can be used to extend it to a measure defined on the entire $sigma$-algebra generated by such rectangles.






            share|cite|improve this answer





















            • Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
              – user109871
              Aug 2 at 18:47






            • 1




              Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
              – Eric Wofsey
              Aug 2 at 18:53












            up vote
            3
            down vote










            up vote
            3
            down vote









            One very important example is the construction of product measures. Given measures $mu$ and $nu$ on measurable spaces $X$ and $Y$, we seek to define a product measure $mutimes nu$ on $Xtimes Y$. Now, it is easy to define what this product measure should be on rectangles: if $Asubseteq X$ and $Bsubseteq Y$ are measurable, then $(mutimesnu)(Atimes B)$ should be $mu(A)nu(B)$ (just like the usual formula for the area of a rectangle in the plane). This can then be extended to finite unions of rectangles, and then the Caratheodory extension theorem can be used to extend it to a measure defined on the entire $sigma$-algebra generated by such rectangles.






            share|cite|improve this answer













            One very important example is the construction of product measures. Given measures $mu$ and $nu$ on measurable spaces $X$ and $Y$, we seek to define a product measure $mutimes nu$ on $Xtimes Y$. Now, it is easy to define what this product measure should be on rectangles: if $Asubseteq X$ and $Bsubseteq Y$ are measurable, then $(mutimesnu)(Atimes B)$ should be $mu(A)nu(B)$ (just like the usual formula for the area of a rectangle in the plane). This can then be extended to finite unions of rectangles, and then the Caratheodory extension theorem can be used to extend it to a measure defined on the entire $sigma$-algebra generated by such rectangles.







            share|cite|improve this answer













            share|cite|improve this answer



            share|cite|improve this answer











            answered Aug 2 at 18:41









            Eric Wofsey

            161k12188297




            161k12188297











            • Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
              – user109871
              Aug 2 at 18:47






            • 1




              Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
              – Eric Wofsey
              Aug 2 at 18:53
















            • Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
              – user109871
              Aug 2 at 18:47






            • 1




              Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
              – Eric Wofsey
              Aug 2 at 18:53















            Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
            – user109871
            Aug 2 at 18:47




            Do you know of a useful product of measure spaces that are not euclidean spaces, where the product measure is used?
            – user109871
            Aug 2 at 18:47




            1




            1




            Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
            – Eric Wofsey
            Aug 2 at 18:53




            Sure, it's used all the time in probability theory. Product measures are how you rigorously model something like "independent samples": you take a product of copies of your probability space, one for each sample.
            – Eric Wofsey
            Aug 2 at 18:53










            up vote
            2
            down vote













            The concept of a cumulative distribution functions (cdf) is closely related to Carathéodory Extension Theorem. The construction is fairly similar to the Lebesgue measure though.



            Let $P$ be a probability measure on $(mathbbR, mathcalBmathbbR)$. The cdf of $P$ is the function $$F: mathbbR rightarrow [0,1], x mapsto P((-infty, x]).$$ Given the measure $P$, one can obviously construct $F$, but $F$ can also be used to reconstruct $P$:



            Given a cdf $F$. The according probability measure $P$ is the unique measure on $(mathbbR, mathcalBmathbbR)$, such that $P((a,b]) = F(b)-F(a)$. One can prove that $P$ exists and that it is unique, using the Carathéodory Extension Theorem.






            share|cite|improve this answer

























              up vote
              2
              down vote













              The concept of a cumulative distribution functions (cdf) is closely related to Carathéodory Extension Theorem. The construction is fairly similar to the Lebesgue measure though.



              Let $P$ be a probability measure on $(mathbbR, mathcalBmathbbR)$. The cdf of $P$ is the function $$F: mathbbR rightarrow [0,1], x mapsto P((-infty, x]).$$ Given the measure $P$, one can obviously construct $F$, but $F$ can also be used to reconstruct $P$:



              Given a cdf $F$. The according probability measure $P$ is the unique measure on $(mathbbR, mathcalBmathbbR)$, such that $P((a,b]) = F(b)-F(a)$. One can prove that $P$ exists and that it is unique, using the Carathéodory Extension Theorem.






              share|cite|improve this answer























                up vote
                2
                down vote










                up vote
                2
                down vote









                The concept of a cumulative distribution functions (cdf) is closely related to Carathéodory Extension Theorem. The construction is fairly similar to the Lebesgue measure though.



                Let $P$ be a probability measure on $(mathbbR, mathcalBmathbbR)$. The cdf of $P$ is the function $$F: mathbbR rightarrow [0,1], x mapsto P((-infty, x]).$$ Given the measure $P$, one can obviously construct $F$, but $F$ can also be used to reconstruct $P$:



                Given a cdf $F$. The according probability measure $P$ is the unique measure on $(mathbbR, mathcalBmathbbR)$, such that $P((a,b]) = F(b)-F(a)$. One can prove that $P$ exists and that it is unique, using the Carathéodory Extension Theorem.






                share|cite|improve this answer













                The concept of a cumulative distribution functions (cdf) is closely related to Carathéodory Extension Theorem. The construction is fairly similar to the Lebesgue measure though.



                Let $P$ be a probability measure on $(mathbbR, mathcalBmathbbR)$. The cdf of $P$ is the function $$F: mathbbR rightarrow [0,1], x mapsto P((-infty, x]).$$ Given the measure $P$, one can obviously construct $F$, but $F$ can also be used to reconstruct $P$:



                Given a cdf $F$. The according probability measure $P$ is the unique measure on $(mathbbR, mathcalBmathbbR)$, such that $P((a,b]) = F(b)-F(a)$. One can prove that $P$ exists and that it is unique, using the Carathéodory Extension Theorem.







                share|cite|improve this answer













                share|cite|improve this answer



                share|cite|improve this answer











                answered Aug 2 at 18:44









                Jonas

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