Find out The values for $a, b$ and $c$ [closed]
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$6a+4b+9c = -1$, $4a+6b+9c= -1$ and $9a+9b+17c= 1$
I want to know about that how we'll find out the values of $a, b$ and $c$ from the above equations. The answers are $a=-3.25, b= -3.5$ and $c= 3.5$.
But I'm not understanding how the answers have been calculated. Will someone help me out with the complete solution?
linear-algebra linear-transformations systems-of-equations
closed as off-topic by Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton Aug 9 at 16:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton
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up vote
-2
down vote
favorite
$6a+4b+9c = -1$, $4a+6b+9c= -1$ and $9a+9b+17c= 1$
I want to know about that how we'll find out the values of $a, b$ and $c$ from the above equations. The answers are $a=-3.25, b= -3.5$ and $c= 3.5$.
But I'm not understanding how the answers have been calculated. Will someone help me out with the complete solution?
linear-algebra linear-transformations systems-of-equations
closed as off-topic by Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton Aug 9 at 16:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton
perhaps you might want to include what do you don't understand about the solution? or you might be given another solution that you do not understand again
– Siong Thye Goh
Aug 6 at 6:41
I just want to see the calculations of finding out the values for a,b and c
– Rizwan ashraf
Aug 6 at 6:42
Have you tried Cramer's rule ?? @Rizwanashraf
– Anik Bhowmick
Aug 6 at 6:43
Thank's Anik for your help
– Rizwan ashraf
Aug 6 at 7:17
add a comment |Â
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
$6a+4b+9c = -1$, $4a+6b+9c= -1$ and $9a+9b+17c= 1$
I want to know about that how we'll find out the values of $a, b$ and $c$ from the above equations. The answers are $a=-3.25, b= -3.5$ and $c= 3.5$.
But I'm not understanding how the answers have been calculated. Will someone help me out with the complete solution?
linear-algebra linear-transformations systems-of-equations
$6a+4b+9c = -1$, $4a+6b+9c= -1$ and $9a+9b+17c= 1$
I want to know about that how we'll find out the values of $a, b$ and $c$ from the above equations. The answers are $a=-3.25, b= -3.5$ and $c= 3.5$.
But I'm not understanding how the answers have been calculated. Will someone help me out with the complete solution?
linear-algebra linear-transformations systems-of-equations
edited Aug 6 at 12:10
Harry Peter
5,47311438
5,47311438
asked Aug 6 at 6:38


Rizwan ashraf
11
11
closed as off-topic by Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton Aug 9 at 16:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton
closed as off-topic by Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton Aug 9 at 16:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Carl Mummert, Jendrik Stelzner, Claude Leibovici, TheSimpliFire, Clayton
perhaps you might want to include what do you don't understand about the solution? or you might be given another solution that you do not understand again
– Siong Thye Goh
Aug 6 at 6:41
I just want to see the calculations of finding out the values for a,b and c
– Rizwan ashraf
Aug 6 at 6:42
Have you tried Cramer's rule ?? @Rizwanashraf
– Anik Bhowmick
Aug 6 at 6:43
Thank's Anik for your help
– Rizwan ashraf
Aug 6 at 7:17
add a comment |Â
perhaps you might want to include what do you don't understand about the solution? or you might be given another solution that you do not understand again
– Siong Thye Goh
Aug 6 at 6:41
I just want to see the calculations of finding out the values for a,b and c
– Rizwan ashraf
Aug 6 at 6:42
Have you tried Cramer's rule ?? @Rizwanashraf
– Anik Bhowmick
Aug 6 at 6:43
Thank's Anik for your help
– Rizwan ashraf
Aug 6 at 7:17
perhaps you might want to include what do you don't understand about the solution? or you might be given another solution that you do not understand again
– Siong Thye Goh
Aug 6 at 6:41
perhaps you might want to include what do you don't understand about the solution? or you might be given another solution that you do not understand again
– Siong Thye Goh
Aug 6 at 6:41
I just want to see the calculations of finding out the values for a,b and c
– Rizwan ashraf
Aug 6 at 6:42
I just want to see the calculations of finding out the values for a,b and c
– Rizwan ashraf
Aug 6 at 6:42
Have you tried Cramer's rule ?? @Rizwanashraf
– Anik Bhowmick
Aug 6 at 6:43
Have you tried Cramer's rule ?? @Rizwanashraf
– Anik Bhowmick
Aug 6 at 6:43
Thank's Anik for your help
– Rizwan ashraf
Aug 6 at 7:17
Thank's Anik for your help
– Rizwan ashraf
Aug 6 at 7:17
add a comment |Â
1 Answer
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From the first and the second equations we'll get $a=b$, which gives
$$10a+9c=-1$$ and $$18a+17c=1.$$
Can you end it now?
I think the Cramer's rule it's very ugly here.
After summing of last two equations we obtain:
$$28a+26c=0$$ or
$$a=-frac13c14.$$
Thus,
$$10left(-frac13c14right)+9c=-1$$ or
$$left(-frac657+9right)c=-1$$ or
$$-frac27c=-1$$ or
$$c=3.5$$ and from here
$$a=-frac1314cdot3.5=-3.25,$$ which gives the answer:
$$(a,b,c)=(-3.25,-3.25,3.5).$$
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
 |Â
show 11 more comments
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
From the first and the second equations we'll get $a=b$, which gives
$$10a+9c=-1$$ and $$18a+17c=1.$$
Can you end it now?
I think the Cramer's rule it's very ugly here.
After summing of last two equations we obtain:
$$28a+26c=0$$ or
$$a=-frac13c14.$$
Thus,
$$10left(-frac13c14right)+9c=-1$$ or
$$left(-frac657+9right)c=-1$$ or
$$-frac27c=-1$$ or
$$c=3.5$$ and from here
$$a=-frac1314cdot3.5=-3.25,$$ which gives the answer:
$$(a,b,c)=(-3.25,-3.25,3.5).$$
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
 |Â
show 11 more comments
up vote
1
down vote
From the first and the second equations we'll get $a=b$, which gives
$$10a+9c=-1$$ and $$18a+17c=1.$$
Can you end it now?
I think the Cramer's rule it's very ugly here.
After summing of last two equations we obtain:
$$28a+26c=0$$ or
$$a=-frac13c14.$$
Thus,
$$10left(-frac13c14right)+9c=-1$$ or
$$left(-frac657+9right)c=-1$$ or
$$-frac27c=-1$$ or
$$c=3.5$$ and from here
$$a=-frac1314cdot3.5=-3.25,$$ which gives the answer:
$$(a,b,c)=(-3.25,-3.25,3.5).$$
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
 |Â
show 11 more comments
up vote
1
down vote
up vote
1
down vote
From the first and the second equations we'll get $a=b$, which gives
$$10a+9c=-1$$ and $$18a+17c=1.$$
Can you end it now?
I think the Cramer's rule it's very ugly here.
After summing of last two equations we obtain:
$$28a+26c=0$$ or
$$a=-frac13c14.$$
Thus,
$$10left(-frac13c14right)+9c=-1$$ or
$$left(-frac657+9right)c=-1$$ or
$$-frac27c=-1$$ or
$$c=3.5$$ and from here
$$a=-frac1314cdot3.5=-3.25,$$ which gives the answer:
$$(a,b,c)=(-3.25,-3.25,3.5).$$
From the first and the second equations we'll get $a=b$, which gives
$$10a+9c=-1$$ and $$18a+17c=1.$$
Can you end it now?
I think the Cramer's rule it's very ugly here.
After summing of last two equations we obtain:
$$28a+26c=0$$ or
$$a=-frac13c14.$$
Thus,
$$10left(-frac13c14right)+9c=-1$$ or
$$left(-frac657+9right)c=-1$$ or
$$-frac27c=-1$$ or
$$c=3.5$$ and from here
$$a=-frac1314cdot3.5=-3.25,$$ which gives the answer:
$$(a,b,c)=(-3.25,-3.25,3.5).$$
edited Aug 6 at 7:25
answered Aug 6 at 6:42
Michael Rozenberg
88.2k1579180
88.2k1579180
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
 |Â
show 11 more comments
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
How we get a=b?
– Rizwan ashraf
Aug 6 at 6:44
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
Because $(6a+4b+9c)-(4a+6b+9c)=0.$
– Michael Rozenberg
Aug 6 at 6:45
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
If I follow this procedure I am getting the answer a=1 or I am doing something wrong.
– Rizwan ashraf
Aug 6 at 6:52
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
Yes, of course!
– Michael Rozenberg
Aug 6 at 6:53
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
But the actual answer of a is -3.25
– Rizwan ashraf
Aug 6 at 6:54
 |Â
show 11 more comments
perhaps you might want to include what do you don't understand about the solution? or you might be given another solution that you do not understand again
– Siong Thye Goh
Aug 6 at 6:41
I just want to see the calculations of finding out the values for a,b and c
– Rizwan ashraf
Aug 6 at 6:42
Have you tried Cramer's rule ?? @Rizwanashraf
– Anik Bhowmick
Aug 6 at 6:43
Thank's Anik for your help
– Rizwan ashraf
Aug 6 at 7:17