For what values of a is this process a well defined Ito integral
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So the question is
For what values of a$in$ $mathbbR$ is the process
$$Y_a(t)=int_0^t(t-s)^adB(s) $$
Well defined as an Ito integral.
By well defined does it mean finite a.s? would it help to look at its expectoration or variance.
probability stochastic-calculus brownian-motion
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up vote
0
down vote
favorite
So the question is
For what values of a$in$ $mathbbR$ is the process
$$Y_a(t)=int_0^t(t-s)^adB(s) $$
Well defined as an Ito integral.
By well defined does it mean finite a.s? would it help to look at its expectoration or variance.
probability stochastic-calculus brownian-motion
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
So the question is
For what values of a$in$ $mathbbR$ is the process
$$Y_a(t)=int_0^t(t-s)^adB(s) $$
Well defined as an Ito integral.
By well defined does it mean finite a.s? would it help to look at its expectoration or variance.
probability stochastic-calculus brownian-motion
So the question is
For what values of a$in$ $mathbbR$ is the process
$$Y_a(t)=int_0^t(t-s)^adB(s) $$
Well defined as an Ito integral.
By well defined does it mean finite a.s? would it help to look at its expectoration or variance.
probability stochastic-calculus brownian-motion
asked yesterday


Monty
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