Geometry section formula [on hold]
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If one end of the line segment is (1, 2) and the point which divides internally in the ratio 1 : 2 is origin, find the other externally.
plane-geometry
put on hold as off-topic by Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants Aug 3 at 14:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants
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If one end of the line segment is (1, 2) and the point which divides internally in the ratio 1 : 2 is origin, find the other externally.
plane-geometry
put on hold as off-topic by Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants Aug 3 at 14:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants
You will find you get better help if you can show what your thoughts are, or what you've already attempted (by editing your question) :)
– postmortes
Aug 3 at 5:56
I am unable to get the answer
– user581382
Aug 3 at 5:57
Welcome to math.SE. If you describe the thoughts you've into this problem/the work you've done, we can offer help with the specific problem you're having. If you don't be prepared that the question will get closed for lack of context quite fast.
– Henrik
Aug 3 at 6:04
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If one end of the line segment is (1, 2) and the point which divides internally in the ratio 1 : 2 is origin, find the other externally.
plane-geometry
If one end of the line segment is (1, 2) and the point which divides internally in the ratio 1 : 2 is origin, find the other externally.
plane-geometry
asked Aug 3 at 5:54
user581382
1
1
put on hold as off-topic by Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants Aug 3 at 14:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants
put on hold as off-topic by Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants Aug 3 at 14:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Henrik, Claude Leibovici, José Carlos Santos, Micah, Strants
You will find you get better help if you can show what your thoughts are, or what you've already attempted (by editing your question) :)
– postmortes
Aug 3 at 5:56
I am unable to get the answer
– user581382
Aug 3 at 5:57
Welcome to math.SE. If you describe the thoughts you've into this problem/the work you've done, we can offer help with the specific problem you're having. If you don't be prepared that the question will get closed for lack of context quite fast.
– Henrik
Aug 3 at 6:04
add a comment |Â
You will find you get better help if you can show what your thoughts are, or what you've already attempted (by editing your question) :)
– postmortes
Aug 3 at 5:56
I am unable to get the answer
– user581382
Aug 3 at 5:57
Welcome to math.SE. If you describe the thoughts you've into this problem/the work you've done, we can offer help with the specific problem you're having. If you don't be prepared that the question will get closed for lack of context quite fast.
– Henrik
Aug 3 at 6:04
You will find you get better help if you can show what your thoughts are, or what you've already attempted (by editing your question) :)
– postmortes
Aug 3 at 5:56
You will find you get better help if you can show what your thoughts are, or what you've already attempted (by editing your question) :)
– postmortes
Aug 3 at 5:56
I am unable to get the answer
– user581382
Aug 3 at 5:57
I am unable to get the answer
– user581382
Aug 3 at 5:57
Welcome to math.SE. If you describe the thoughts you've into this problem/the work you've done, we can offer help with the specific problem you're having. If you don't be prepared that the question will get closed for lack of context quite fast.
– Henrik
Aug 3 at 6:04
Welcome to math.SE. If you describe the thoughts you've into this problem/the work you've done, we can offer help with the specific problem you're having. If you don't be prepared that the question will get closed for lack of context quite fast.
– Henrik
Aug 3 at 6:04
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2 Answers
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Refer to the graph:
$hspace6cm$
Note that the triangles $Delta ADO$ and $Delta ABC$ are similar. Hence:
$$fracAOAB=fracADAC=fracDOBC iff frac13=frac2AC=frac1BC iff AC=6; BC=3.$$
Can you figure out the coordinates of the point $B$?
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Notice that $C$ is a definite proportion point of the directed line segment $overlineAB.$ Denote the three points as $$A(x_a,y_a),B(x_b,y_b),C(x_c,y_c).$$We've known that $x_a=1,y_a=2$,$x_c=0,y_c=0$ and $lambda=dfracoverlineACoverlineCB=dfrac12.$ Thus, by the formula of definite proportion, we obtain $$fracx_a+lambda x_b1+lambda=frac1+dfrac12x_b1+dfrac12=x_c=0,~~~~fracy_a+lambda y_b1+lambda=frac2+dfrac12y_b1+dfrac12=y_c=0.$$
As a result $$x_b=-2,~~~y_b=-4.$$
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Refer to the graph:
$hspace6cm$
Note that the triangles $Delta ADO$ and $Delta ABC$ are similar. Hence:
$$fracAOAB=fracADAC=fracDOBC iff frac13=frac2AC=frac1BC iff AC=6; BC=3.$$
Can you figure out the coordinates of the point $B$?
add a comment |Â
up vote
0
down vote
Refer to the graph:
$hspace6cm$
Note that the triangles $Delta ADO$ and $Delta ABC$ are similar. Hence:
$$fracAOAB=fracADAC=fracDOBC iff frac13=frac2AC=frac1BC iff AC=6; BC=3.$$
Can you figure out the coordinates of the point $B$?
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Refer to the graph:
$hspace6cm$
Note that the triangles $Delta ADO$ and $Delta ABC$ are similar. Hence:
$$fracAOAB=fracADAC=fracDOBC iff frac13=frac2AC=frac1BC iff AC=6; BC=3.$$
Can you figure out the coordinates of the point $B$?
Refer to the graph:
$hspace6cm$
Note that the triangles $Delta ADO$ and $Delta ABC$ are similar. Hence:
$$fracAOAB=fracADAC=fracDOBC iff frac13=frac2AC=frac1BC iff AC=6; BC=3.$$
Can you figure out the coordinates of the point $B$?
answered Aug 3 at 14:16


farruhota
13.4k2632
13.4k2632
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up vote
-1
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Notice that $C$ is a definite proportion point of the directed line segment $overlineAB.$ Denote the three points as $$A(x_a,y_a),B(x_b,y_b),C(x_c,y_c).$$We've known that $x_a=1,y_a=2$,$x_c=0,y_c=0$ and $lambda=dfracoverlineACoverlineCB=dfrac12.$ Thus, by the formula of definite proportion, we obtain $$fracx_a+lambda x_b1+lambda=frac1+dfrac12x_b1+dfrac12=x_c=0,~~~~fracy_a+lambda y_b1+lambda=frac2+dfrac12y_b1+dfrac12=y_c=0.$$
As a result $$x_b=-2,~~~y_b=-4.$$
add a comment |Â
up vote
-1
down vote
Notice that $C$ is a definite proportion point of the directed line segment $overlineAB.$ Denote the three points as $$A(x_a,y_a),B(x_b,y_b),C(x_c,y_c).$$We've known that $x_a=1,y_a=2$,$x_c=0,y_c=0$ and $lambda=dfracoverlineACoverlineCB=dfrac12.$ Thus, by the formula of definite proportion, we obtain $$fracx_a+lambda x_b1+lambda=frac1+dfrac12x_b1+dfrac12=x_c=0,~~~~fracy_a+lambda y_b1+lambda=frac2+dfrac12y_b1+dfrac12=y_c=0.$$
As a result $$x_b=-2,~~~y_b=-4.$$
add a comment |Â
up vote
-1
down vote
up vote
-1
down vote
Notice that $C$ is a definite proportion point of the directed line segment $overlineAB.$ Denote the three points as $$A(x_a,y_a),B(x_b,y_b),C(x_c,y_c).$$We've known that $x_a=1,y_a=2$,$x_c=0,y_c=0$ and $lambda=dfracoverlineACoverlineCB=dfrac12.$ Thus, by the formula of definite proportion, we obtain $$fracx_a+lambda x_b1+lambda=frac1+dfrac12x_b1+dfrac12=x_c=0,~~~~fracy_a+lambda y_b1+lambda=frac2+dfrac12y_b1+dfrac12=y_c=0.$$
As a result $$x_b=-2,~~~y_b=-4.$$
Notice that $C$ is a definite proportion point of the directed line segment $overlineAB.$ Denote the three points as $$A(x_a,y_a),B(x_b,y_b),C(x_c,y_c).$$We've known that $x_a=1,y_a=2$,$x_c=0,y_c=0$ and $lambda=dfracoverlineACoverlineCB=dfrac12.$ Thus, by the formula of definite proportion, we obtain $$fracx_a+lambda x_b1+lambda=frac1+dfrac12x_b1+dfrac12=x_c=0,~~~~fracy_a+lambda y_b1+lambda=frac2+dfrac12y_b1+dfrac12=y_c=0.$$
As a result $$x_b=-2,~~~y_b=-4.$$
answered Aug 3 at 8:31
mengdie1982
2,840216
2,840216
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You will find you get better help if you can show what your thoughts are, or what you've already attempted (by editing your question) :)
– postmortes
Aug 3 at 5:56
I am unable to get the answer
– user581382
Aug 3 at 5:57
Welcome to math.SE. If you describe the thoughts you've into this problem/the work you've done, we can offer help with the specific problem you're having. If you don't be prepared that the question will get closed for lack of context quite fast.
– Henrik
Aug 3 at 6:04