Is it possible to graph $f(x) = (-2)^x$?
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
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I can plot points on the coordinate plane only when my x
value is integer. What's happening on the graph when x
is fraction? My calculator breaks raising a negative number to a fractional exponent.
This website can't graph the function either: https://www.desmos.com/calculator/xucwdp4dz3
Can we graph that function somehow?
functions exponential-function exponentiation
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up vote
0
down vote
favorite
I can plot points on the coordinate plane only when my x
value is integer. What's happening on the graph when x
is fraction? My calculator breaks raising a negative number to a fractional exponent.
This website can't graph the function either: https://www.desmos.com/calculator/xucwdp4dz3
Can we graph that function somehow?
functions exponential-function exponentiation
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I can plot points on the coordinate plane only when my x
value is integer. What's happening on the graph when x
is fraction? My calculator breaks raising a negative number to a fractional exponent.
This website can't graph the function either: https://www.desmos.com/calculator/xucwdp4dz3
Can we graph that function somehow?
functions exponential-function exponentiation
I can plot points on the coordinate plane only when my x
value is integer. What's happening on the graph when x
is fraction? My calculator breaks raising a negative number to a fractional exponent.
This website can't graph the function either: https://www.desmos.com/calculator/xucwdp4dz3
Can we graph that function somehow?
functions exponential-function exponentiation
asked 2 days ago


Vitalii Paprotskyi
636
636
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1 Answer
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That function is not defined in a lot of points on the real axis. For example, if you take $x=frac12$ then $(-2)^x=(-1)^x*2^x=sqrt-1*sqrt2$, so you are taking a square root of a negative number here and hence the function is not defined at $x=frac12$. So to do something with this function you need to work in the complex plane, and even then there will be some problems.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
That function is not defined in a lot of points on the real axis. For example, if you take $x=frac12$ then $(-2)^x=(-1)^x*2^x=sqrt-1*sqrt2$, so you are taking a square root of a negative number here and hence the function is not defined at $x=frac12$. So to do something with this function you need to work in the complex plane, and even then there will be some problems.
add a comment |Â
up vote
3
down vote
accepted
That function is not defined in a lot of points on the real axis. For example, if you take $x=frac12$ then $(-2)^x=(-1)^x*2^x=sqrt-1*sqrt2$, so you are taking a square root of a negative number here and hence the function is not defined at $x=frac12$. So to do something with this function you need to work in the complex plane, and even then there will be some problems.
add a comment |Â
up vote
3
down vote
accepted
up vote
3
down vote
accepted
That function is not defined in a lot of points on the real axis. For example, if you take $x=frac12$ then $(-2)^x=(-1)^x*2^x=sqrt-1*sqrt2$, so you are taking a square root of a negative number here and hence the function is not defined at $x=frac12$. So to do something with this function you need to work in the complex plane, and even then there will be some problems.
That function is not defined in a lot of points on the real axis. For example, if you take $x=frac12$ then $(-2)^x=(-1)^x*2^x=sqrt-1*sqrt2$, so you are taking a square root of a negative number here and hence the function is not defined at $x=frac12$. So to do something with this function you need to work in the complex plane, and even then there will be some problems.
answered 2 days ago
Mark
5849
5849
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add a comment |Â
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