New Twist - sum of numbers printed on billiard balls in a bag
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Given that all the balls in a bag have one number (either 0, 1, 2, 3, or 4) printed on them, and given that there are 30 balls in the bag, how many possible combinations of balls can be taken from the bag where the sum of the numbers printed on the balls adds up to 30? The twist is the sum of the numbers...
I am unsure how to tackle this one.
combinations
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up vote
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Given that all the balls in a bag have one number (either 0, 1, 2, 3, or 4) printed on them, and given that there are 30 balls in the bag, how many possible combinations of balls can be taken from the bag where the sum of the numbers printed on the balls adds up to 30? The twist is the sum of the numbers...
I am unsure how to tackle this one.
combinations
3
It depends on which numbers the balls have. E.g. if they all have a $0$, then the answer is $0$.
– joriki
Jul 25 at 18:06
3
There are 30 balls but only five numbers. How many times does each number occur? Do they all occur the same number of times?
– David K
Jul 25 at 18:07
1
Or are you asking about all possible combinations that might arise for all possible labelings of the balls, not just for one given labeling?
– joriki
Jul 25 at 18:08
Sorry, I mis-stated the problem. 30 balls will be drawn from a bag that has enough quantity of each number of balls, so that no matter how many it takes to reach a sum of thirty, there will always be enough. How many combinations are possible? Thanks for taking the time to help with this.
– user579527
Jul 26 at 20:24
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Given that all the balls in a bag have one number (either 0, 1, 2, 3, or 4) printed on them, and given that there are 30 balls in the bag, how many possible combinations of balls can be taken from the bag where the sum of the numbers printed on the balls adds up to 30? The twist is the sum of the numbers...
I am unsure how to tackle this one.
combinations
Given that all the balls in a bag have one number (either 0, 1, 2, 3, or 4) printed on them, and given that there are 30 balls in the bag, how many possible combinations of balls can be taken from the bag where the sum of the numbers printed on the balls adds up to 30? The twist is the sum of the numbers...
I am unsure how to tackle this one.
combinations
edited Jul 25 at 18:12


amWhy
189k25219431
189k25219431
asked Jul 25 at 18:04
user579527
1
1
3
It depends on which numbers the balls have. E.g. if they all have a $0$, then the answer is $0$.
– joriki
Jul 25 at 18:06
3
There are 30 balls but only five numbers. How many times does each number occur? Do they all occur the same number of times?
– David K
Jul 25 at 18:07
1
Or are you asking about all possible combinations that might arise for all possible labelings of the balls, not just for one given labeling?
– joriki
Jul 25 at 18:08
Sorry, I mis-stated the problem. 30 balls will be drawn from a bag that has enough quantity of each number of balls, so that no matter how many it takes to reach a sum of thirty, there will always be enough. How many combinations are possible? Thanks for taking the time to help with this.
– user579527
Jul 26 at 20:24
add a comment |Â
3
It depends on which numbers the balls have. E.g. if they all have a $0$, then the answer is $0$.
– joriki
Jul 25 at 18:06
3
There are 30 balls but only five numbers. How many times does each number occur? Do they all occur the same number of times?
– David K
Jul 25 at 18:07
1
Or are you asking about all possible combinations that might arise for all possible labelings of the balls, not just for one given labeling?
– joriki
Jul 25 at 18:08
Sorry, I mis-stated the problem. 30 balls will be drawn from a bag that has enough quantity of each number of balls, so that no matter how many it takes to reach a sum of thirty, there will always be enough. How many combinations are possible? Thanks for taking the time to help with this.
– user579527
Jul 26 at 20:24
3
3
It depends on which numbers the balls have. E.g. if they all have a $0$, then the answer is $0$.
– joriki
Jul 25 at 18:06
It depends on which numbers the balls have. E.g. if they all have a $0$, then the answer is $0$.
– joriki
Jul 25 at 18:06
3
3
There are 30 balls but only five numbers. How many times does each number occur? Do they all occur the same number of times?
– David K
Jul 25 at 18:07
There are 30 balls but only five numbers. How many times does each number occur? Do they all occur the same number of times?
– David K
Jul 25 at 18:07
1
1
Or are you asking about all possible combinations that might arise for all possible labelings of the balls, not just for one given labeling?
– joriki
Jul 25 at 18:08
Or are you asking about all possible combinations that might arise for all possible labelings of the balls, not just for one given labeling?
– joriki
Jul 25 at 18:08
Sorry, I mis-stated the problem. 30 balls will be drawn from a bag that has enough quantity of each number of balls, so that no matter how many it takes to reach a sum of thirty, there will always be enough. How many combinations are possible? Thanks for taking the time to help with this.
– user579527
Jul 26 at 20:24
Sorry, I mis-stated the problem. 30 balls will be drawn from a bag that has enough quantity of each number of balls, so that no matter how many it takes to reach a sum of thirty, there will always be enough. How many combinations are possible? Thanks for taking the time to help with this.
– user579527
Jul 26 at 20:24
add a comment |Â
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3
It depends on which numbers the balls have. E.g. if they all have a $0$, then the answer is $0$.
– joriki
Jul 25 at 18:06
3
There are 30 balls but only five numbers. How many times does each number occur? Do they all occur the same number of times?
– David K
Jul 25 at 18:07
1
Or are you asking about all possible combinations that might arise for all possible labelings of the balls, not just for one given labeling?
– joriki
Jul 25 at 18:08
Sorry, I mis-stated the problem. 30 balls will be drawn from a bag that has enough quantity of each number of balls, so that no matter how many it takes to reach a sum of thirty, there will always be enough. How many combinations are possible? Thanks for taking the time to help with this.
– user579527
Jul 26 at 20:24