Prove that the following matrix is semidefinite.
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Let $X=[X_1, X_2]$ be a full column rank matrix, where $X_1$ is a $ntimes p$ matrix and $X_2$ is a $ntimes q$ matrix. Both $X_1$ and $X_2$ are full column rank matrices. That is to say, $rm rank(X)=p+q$, $rm rank(X_1)=p$ and $rm rank(X_2)=q$. Prove that the matrix $X(X^TX)^-1X^T-X_1(X_1^TX_1)^-1X_1^T$ is a positive semidefinite matrix.
I try to use Woodbury inverse formula, but it seems fails. Thanks for your help:)
matrices positive-semidefinite
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Let $X=[X_1, X_2]$ be a full column rank matrix, where $X_1$ is a $ntimes p$ matrix and $X_2$ is a $ntimes q$ matrix. Both $X_1$ and $X_2$ are full column rank matrices. That is to say, $rm rank(X)=p+q$, $rm rank(X_1)=p$ and $rm rank(X_2)=q$. Prove that the matrix $X(X^TX)^-1X^T-X_1(X_1^TX_1)^-1X_1^T$ is a positive semidefinite matrix.
I try to use Woodbury inverse formula, but it seems fails. Thanks for your help:)
matrices positive-semidefinite
Are all of those matrices real?
– Mostafa Ayaz
Jul 22 at 8:56
Thank you Mostafa. Yes, there are real.
– Ning Zheng
Jul 22 at 8:57
Also what about $p$ , $q$ and $n$? Is $ple n$ and $qle n$ and $p+qle n$?
– Mostafa Ayaz
Jul 22 at 8:59
Yes, of course. Otherwise they are full row rank, instead of full column rank.
– Ning Zheng
Jul 22 at 9:08
add a comment |Â
up vote
0
down vote
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up vote
0
down vote
favorite
Let $X=[X_1, X_2]$ be a full column rank matrix, where $X_1$ is a $ntimes p$ matrix and $X_2$ is a $ntimes q$ matrix. Both $X_1$ and $X_2$ are full column rank matrices. That is to say, $rm rank(X)=p+q$, $rm rank(X_1)=p$ and $rm rank(X_2)=q$. Prove that the matrix $X(X^TX)^-1X^T-X_1(X_1^TX_1)^-1X_1^T$ is a positive semidefinite matrix.
I try to use Woodbury inverse formula, but it seems fails. Thanks for your help:)
matrices positive-semidefinite
Let $X=[X_1, X_2]$ be a full column rank matrix, where $X_1$ is a $ntimes p$ matrix and $X_2$ is a $ntimes q$ matrix. Both $X_1$ and $X_2$ are full column rank matrices. That is to say, $rm rank(X)=p+q$, $rm rank(X_1)=p$ and $rm rank(X_2)=q$. Prove that the matrix $X(X^TX)^-1X^T-X_1(X_1^TX_1)^-1X_1^T$ is a positive semidefinite matrix.
I try to use Woodbury inverse formula, but it seems fails. Thanks for your help:)
matrices positive-semidefinite
asked Jul 22 at 8:49
Ning Zheng
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112
Are all of those matrices real?
– Mostafa Ayaz
Jul 22 at 8:56
Thank you Mostafa. Yes, there are real.
– Ning Zheng
Jul 22 at 8:57
Also what about $p$ , $q$ and $n$? Is $ple n$ and $qle n$ and $p+qle n$?
– Mostafa Ayaz
Jul 22 at 8:59
Yes, of course. Otherwise they are full row rank, instead of full column rank.
– Ning Zheng
Jul 22 at 9:08
add a comment |Â
Are all of those matrices real?
– Mostafa Ayaz
Jul 22 at 8:56
Thank you Mostafa. Yes, there are real.
– Ning Zheng
Jul 22 at 8:57
Also what about $p$ , $q$ and $n$? Is $ple n$ and $qle n$ and $p+qle n$?
– Mostafa Ayaz
Jul 22 at 8:59
Yes, of course. Otherwise they are full row rank, instead of full column rank.
– Ning Zheng
Jul 22 at 9:08
Are all of those matrices real?
– Mostafa Ayaz
Jul 22 at 8:56
Are all of those matrices real?
– Mostafa Ayaz
Jul 22 at 8:56
Thank you Mostafa. Yes, there are real.
– Ning Zheng
Jul 22 at 8:57
Thank you Mostafa. Yes, there are real.
– Ning Zheng
Jul 22 at 8:57
Also what about $p$ , $q$ and $n$? Is $ple n$ and $qle n$ and $p+qle n$?
– Mostafa Ayaz
Jul 22 at 8:59
Also what about $p$ , $q$ and $n$? Is $ple n$ and $qle n$ and $p+qle n$?
– Mostafa Ayaz
Jul 22 at 8:59
Yes, of course. Otherwise they are full row rank, instead of full column rank.
– Ning Zheng
Jul 22 at 9:08
Yes, of course. Otherwise they are full row rank, instead of full column rank.
– Ning Zheng
Jul 22 at 9:08
add a comment |Â
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Are all of those matrices real?
– Mostafa Ayaz
Jul 22 at 8:56
Thank you Mostafa. Yes, there are real.
– Ning Zheng
Jul 22 at 8:57
Also what about $p$ , $q$ and $n$? Is $ple n$ and $qle n$ and $p+qle n$?
– Mostafa Ayaz
Jul 22 at 8:59
Yes, of course. Otherwise they are full row rank, instead of full column rank.
– Ning Zheng
Jul 22 at 9:08