relative interiors of a k dimensional simplex

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Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.







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  • I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
    – Shachar Har-Shuv
    Jul 23 at 9:16














up vote
-1
down vote

favorite












Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.







share|cite|improve this question





















  • I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
    – Shachar Har-Shuv
    Jul 23 at 9:16












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.







share|cite|improve this question













Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 23 at 11:07
























asked Jul 23 at 9:10









Farzam

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  • I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
    – Shachar Har-Shuv
    Jul 23 at 9:16
















  • I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
    – Shachar Har-Shuv
    Jul 23 at 9:16















I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16




I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16















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