relative interiors of a k dimensional simplex
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Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.
analysis convex-analysis
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up vote
-1
down vote
favorite
Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.
analysis convex-analysis
I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.
analysis convex-analysis
Can anyone prove that the relative interior of a k dimensional simplex is nonempty?
I've found a proof for that which was based on the properties of a continuous function but I couldn't understand the details.
analysis convex-analysis
edited Jul 23 at 11:07
asked Jul 23 at 9:10


Farzam
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I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16
add a comment |Â
I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16
I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16
I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16
add a comment |Â
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I think it is easy to prove by induction if you know the recursive definition of a simplex. Sketch - a k-1 has an internal point, move it to the k'th dimension to get an internal point of a k-dimensional simplex.
– Shachar Har-Shuv
Jul 23 at 9:16