The GCF of unknown monomials
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There are three monomials such that the greatest common factor of the first and second monomials is $2xy$, and the greatest common factor of the second and third monomials is $2x^2y$. What is the greatest common factor of the three monomials?
polynomials factoring greatest-common-divisor
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up vote
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There are three monomials such that the greatest common factor of the first and second monomials is $2xy$, and the greatest common factor of the second and third monomials is $2x^2y$. What is the greatest common factor of the three monomials?
polynomials factoring greatest-common-divisor
1
What are your thoughts on the problem? What have you tried so far?
– Matt
Aug 3 at 1:21
@Matt I thought that the answer would be 2x^2y / 2xy, but I don't think that the answer would simply be 'x'.
– Billy
Aug 3 at 1:27
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
There are three monomials such that the greatest common factor of the first and second monomials is $2xy$, and the greatest common factor of the second and third monomials is $2x^2y$. What is the greatest common factor of the three monomials?
polynomials factoring greatest-common-divisor
There are three monomials such that the greatest common factor of the first and second monomials is $2xy$, and the greatest common factor of the second and third monomials is $2x^2y$. What is the greatest common factor of the three monomials?
polynomials factoring greatest-common-divisor
edited Aug 3 at 2:52
Math Lover
12.2k21132
12.2k21132
asked Aug 3 at 1:19


Billy
22
22
1
What are your thoughts on the problem? What have you tried so far?
– Matt
Aug 3 at 1:21
@Matt I thought that the answer would be 2x^2y / 2xy, but I don't think that the answer would simply be 'x'.
– Billy
Aug 3 at 1:27
add a comment |Â
1
What are your thoughts on the problem? What have you tried so far?
– Matt
Aug 3 at 1:21
@Matt I thought that the answer would be 2x^2y / 2xy, but I don't think that the answer would simply be 'x'.
– Billy
Aug 3 at 1:27
1
1
What are your thoughts on the problem? What have you tried so far?
– Matt
Aug 3 at 1:21
What are your thoughts on the problem? What have you tried so far?
– Matt
Aug 3 at 1:21
@Matt I thought that the answer would be 2x^2y / 2xy, but I don't think that the answer would simply be 'x'.
– Billy
Aug 3 at 1:27
@Matt I thought that the answer would be 2x^2y / 2xy, but I don't think that the answer would simply be 'x'.
– Billy
Aug 3 at 1:27
add a comment |Â
1 Answer
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Given the GCD of first and second monomials is $2xy$ and the GCD of the second and third monomials is $2x^2y$.
You just need to pick the biggest factors that both of them share.
So, $2xy$ and $2x^2y$ have the common factor $2xy$
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Given the GCD of first and second monomials is $2xy$ and the GCD of the second and third monomials is $2x^2y$.
You just need to pick the biggest factors that both of them share.
So, $2xy$ and $2x^2y$ have the common factor $2xy$
add a comment |Â
up vote
0
down vote
accepted
Given the GCD of first and second monomials is $2xy$ and the GCD of the second and third monomials is $2x^2y$.
You just need to pick the biggest factors that both of them share.
So, $2xy$ and $2x^2y$ have the common factor $2xy$
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Given the GCD of first and second monomials is $2xy$ and the GCD of the second and third monomials is $2x^2y$.
You just need to pick the biggest factors that both of them share.
So, $2xy$ and $2x^2y$ have the common factor $2xy$
Given the GCD of first and second monomials is $2xy$ and the GCD of the second and third monomials is $2x^2y$.
You just need to pick the biggest factors that both of them share.
So, $2xy$ and $2x^2y$ have the common factor $2xy$
answered Aug 3 at 1:23
Key Flex
3,683422
3,683422
add a comment |Â
add a comment |Â
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1
What are your thoughts on the problem? What have you tried so far?
– Matt
Aug 3 at 1:21
@Matt I thought that the answer would be 2x^2y / 2xy, but I don't think that the answer would simply be 'x'.
– Billy
Aug 3 at 1:27