the number of ice cream cones sold can be shown by N(x)=(100logx)+21,

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question: the number of ice cream cones sold can be shown by N(x)=(100logx)+21, where x is the number of days since the beginning of july, the price of ice cream cones is shown by p(x)=0.05x^3 + 0.03x^2 where x is the amount of days since july 1st. what is the rate of change of revenue between July 5th&26th



I have yet to have done differentiation, this is just precalc but I dont know how to set this up to give me the equation for rate of change as in f(x2)-f(x1) divided by (x2)-(x1)




algebra-precalculus




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  • the revenue is equal to the price times quantity. So $f(x)=N(x)cdot p(x)$. Now you can evaluate the change of $f(x)$.
    – farruhota
    Jul 22 at 5:54














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question: the number of ice cream cones sold can be shown by N(x)=(100logx)+21, where x is the number of days since the beginning of july, the price of ice cream cones is shown by p(x)=0.05x^3 + 0.03x^2 where x is the amount of days since july 1st. what is the rate of change of revenue between July 5th&26th



I have yet to have done differentiation, this is just precalc but I dont know how to set this up to give me the equation for rate of change as in f(x2)-f(x1) divided by (x2)-(x1)




algebra-precalculus




share|cite|improve this question



















  • the revenue is equal to the price times quantity. So $f(x)=N(x)cdot p(x)$. Now you can evaluate the change of $f(x)$.
    – farruhota
    Jul 22 at 5:54












up vote
0
down vote

favorite









up vote
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down vote

favorite











question: the number of ice cream cones sold can be shown by N(x)=(100logx)+21, where x is the number of days since the beginning of july, the price of ice cream cones is shown by p(x)=0.05x^3 + 0.03x^2 where x is the amount of days since july 1st. what is the rate of change of revenue between July 5th&26th



I have yet to have done differentiation, this is just precalc but I dont know how to set this up to give me the equation for rate of change as in f(x2)-f(x1) divided by (x2)-(x1)




algebra-precalculus




share|cite|improve this question











question: the number of ice cream cones sold can be shown by N(x)=(100logx)+21, where x is the number of days since the beginning of july, the price of ice cream cones is shown by p(x)=0.05x^3 + 0.03x^2 where x is the amount of days since july 1st. what is the rate of change of revenue between July 5th&26th



I have yet to have done differentiation, this is just precalc but I dont know how to set this up to give me the equation for rate of change as in f(x2)-f(x1) divided by (x2)-(x1)





algebra-precalculus





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asked Jul 22 at 2:44









milliep

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  • the revenue is equal to the price times quantity. So $f(x)=N(x)cdot p(x)$. Now you can evaluate the change of $f(x)$.
    – farruhota
    Jul 22 at 5:54
















  • the revenue is equal to the price times quantity. So $f(x)=N(x)cdot p(x)$. Now you can evaluate the change of $f(x)$.
    – farruhota
    Jul 22 at 5:54















the revenue is equal to the price times quantity. So $f(x)=N(x)cdot p(x)$. Now you can evaluate the change of $f(x)$.
– farruhota
Jul 22 at 5:54




the revenue is equal to the price times quantity. So $f(x)=N(x)cdot p(x)$. Now you can evaluate the change of $f(x)$.
– farruhota
Jul 22 at 5:54










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Your thought for rate of change is correct. You need to plug into the equations to find the number of cones sold on the $5^th$ and the $26^th$ and the price they are sold at. How do you get the revenue once you have the number of cones and the price per cone?






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    Your thought for rate of change is correct. You need to plug into the equations to find the number of cones sold on the $5^th$ and the $26^th$ and the price they are sold at. How do you get the revenue once you have the number of cones and the price per cone?






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      up vote
      0
      down vote













      Your thought for rate of change is correct. You need to plug into the equations to find the number of cones sold on the $5^th$ and the $26^th$ and the price they are sold at. How do you get the revenue once you have the number of cones and the price per cone?






      share|cite|improve this answer























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        down vote










        up vote
        0
        down vote









        Your thought for rate of change is correct. You need to plug into the equations to find the number of cones sold on the $5^th$ and the $26^th$ and the price they are sold at. How do you get the revenue once you have the number of cones and the price per cone?






        share|cite|improve this answer













        Your thought for rate of change is correct. You need to plug into the equations to find the number of cones sold on the $5^th$ and the $26^th$ and the price they are sold at. How do you get the revenue once you have the number of cones and the price per cone?







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        answered Jul 22 at 3:10









        Ross Millikan

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