What is the first digit of $-10$?
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Generally, what is the first digit of a negative whole number? In case of $-10$, it can not be $-1$, because a digit is defined to be from $0$ to $9$. Is it $1$? Or does it not have the first digit at all and it is just the first $number$ $-1$?
elementary-number-theory decimal-expansion
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up vote
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Generally, what is the first digit of a negative whole number? In case of $-10$, it can not be $-1$, because a digit is defined to be from $0$ to $9$. Is it $1$? Or does it not have the first digit at all and it is just the first $number$ $-1$?
elementary-number-theory decimal-expansion
The minus is just a sign. It does not go with a digit.
– Sean Roberson
Jul 14 at 18:49
I would say $1$ is the first digit. There are however 10-adic integers where $-10$ can be expressed by $..9990$ which actually doesn't have a leading digit, it has infinitely many of them, and all are $9$.
– Berci
Jul 14 at 18:49
I believe you mis-typed the $0$ at the end of the $..999$. If it was deliberate, could you please give a little further explanation?
– Archil Zhvania
Jul 14 at 18:58
@SeanRoberson So you're saying the first digit is still $1$, correct?
– Archil Zhvania
Jul 14 at 18:59
Yes, the "first digit" of 19 or -19 is 1.
– user247327
Jul 14 at 19:11
 |Â
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up vote
3
down vote
favorite
up vote
3
down vote
favorite
Generally, what is the first digit of a negative whole number? In case of $-10$, it can not be $-1$, because a digit is defined to be from $0$ to $9$. Is it $1$? Or does it not have the first digit at all and it is just the first $number$ $-1$?
elementary-number-theory decimal-expansion
Generally, what is the first digit of a negative whole number? In case of $-10$, it can not be $-1$, because a digit is defined to be from $0$ to $9$. Is it $1$? Or does it not have the first digit at all and it is just the first $number$ $-1$?
elementary-number-theory decimal-expansion
asked Jul 14 at 18:42


Archil Zhvania
1285
1285
The minus is just a sign. It does not go with a digit.
– Sean Roberson
Jul 14 at 18:49
I would say $1$ is the first digit. There are however 10-adic integers where $-10$ can be expressed by $..9990$ which actually doesn't have a leading digit, it has infinitely many of them, and all are $9$.
– Berci
Jul 14 at 18:49
I believe you mis-typed the $0$ at the end of the $..999$. If it was deliberate, could you please give a little further explanation?
– Archil Zhvania
Jul 14 at 18:58
@SeanRoberson So you're saying the first digit is still $1$, correct?
– Archil Zhvania
Jul 14 at 18:59
Yes, the "first digit" of 19 or -19 is 1.
– user247327
Jul 14 at 19:11
 |Â
show 1 more comment
The minus is just a sign. It does not go with a digit.
– Sean Roberson
Jul 14 at 18:49
I would say $1$ is the first digit. There are however 10-adic integers where $-10$ can be expressed by $..9990$ which actually doesn't have a leading digit, it has infinitely many of them, and all are $9$.
– Berci
Jul 14 at 18:49
I believe you mis-typed the $0$ at the end of the $..999$. If it was deliberate, could you please give a little further explanation?
– Archil Zhvania
Jul 14 at 18:58
@SeanRoberson So you're saying the first digit is still $1$, correct?
– Archil Zhvania
Jul 14 at 18:59
Yes, the "first digit" of 19 or -19 is 1.
– user247327
Jul 14 at 19:11
The minus is just a sign. It does not go with a digit.
– Sean Roberson
Jul 14 at 18:49
The minus is just a sign. It does not go with a digit.
– Sean Roberson
Jul 14 at 18:49
I would say $1$ is the first digit. There are however 10-adic integers where $-10$ can be expressed by $..9990$ which actually doesn't have a leading digit, it has infinitely many of them, and all are $9$.
– Berci
Jul 14 at 18:49
I would say $1$ is the first digit. There are however 10-adic integers where $-10$ can be expressed by $..9990$ which actually doesn't have a leading digit, it has infinitely many of them, and all are $9$.
– Berci
Jul 14 at 18:49
I believe you mis-typed the $0$ at the end of the $..999$. If it was deliberate, could you please give a little further explanation?
– Archil Zhvania
Jul 14 at 18:58
I believe you mis-typed the $0$ at the end of the $..999$. If it was deliberate, could you please give a little further explanation?
– Archil Zhvania
Jul 14 at 18:58
@SeanRoberson So you're saying the first digit is still $1$, correct?
– Archil Zhvania
Jul 14 at 18:59
@SeanRoberson So you're saying the first digit is still $1$, correct?
– Archil Zhvania
Jul 14 at 18:59
Yes, the "first digit" of 19 or -19 is 1.
– user247327
Jul 14 at 19:11
Yes, the "first digit" of 19 or -19 is 1.
– user247327
Jul 14 at 19:11
 |Â
show 1 more comment
1 Answer
1
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As per the comments, the first digit of $-10$ is $1$.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
As per the comments, the first digit of $-10$ is $1$.
add a comment |Â
up vote
1
down vote
accepted
As per the comments, the first digit of $-10$ is $1$.
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
As per the comments, the first digit of $-10$ is $1$.
As per the comments, the first digit of $-10$ is $1$.
answered Jul 15 at 1:48


Martin Roberts
1,189318
1,189318
add a comment |Â
add a comment |Â
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The minus is just a sign. It does not go with a digit.
– Sean Roberson
Jul 14 at 18:49
I would say $1$ is the first digit. There are however 10-adic integers where $-10$ can be expressed by $..9990$ which actually doesn't have a leading digit, it has infinitely many of them, and all are $9$.
– Berci
Jul 14 at 18:49
I believe you mis-typed the $0$ at the end of the $..999$. If it was deliberate, could you please give a little further explanation?
– Archil Zhvania
Jul 14 at 18:58
@SeanRoberson So you're saying the first digit is still $1$, correct?
– Archil Zhvania
Jul 14 at 18:59
Yes, the "first digit" of 19 or -19 is 1.
– user247327
Jul 14 at 19:11