Difficulty in this Olympiad problem [closed]
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Peter was cutting a pipe with an outside diameter of 20cm. When the cut was just through the wall of the pipe, it was 10 cm in length. How thick was the wall of the pipe in centimeters?
contest-math problem-solving
closed as off-topic by Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister Aug 6 at 13:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister
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Peter was cutting a pipe with an outside diameter of 20cm. When the cut was just through the wall of the pipe, it was 10 cm in length. How thick was the wall of the pipe in centimeters?
contest-math problem-solving
closed as off-topic by Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister Aug 6 at 13:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister
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You should show us what you have done so far.
– Le Anh Dung
Aug 6 at 6:10
This is from a competition from 2015: here's a link. In general it's good form to say exactly where/when the problem is from.
– Mason
Aug 6 at 7:07
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up vote
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Peter was cutting a pipe with an outside diameter of 20cm. When the cut was just through the wall of the pipe, it was 10 cm in length. How thick was the wall of the pipe in centimeters?
contest-math problem-solving
Peter was cutting a pipe with an outside diameter of 20cm. When the cut was just through the wall of the pipe, it was 10 cm in length. How thick was the wall of the pipe in centimeters?
contest-math problem-solving
edited Aug 6 at 6:59
Le Anh Dung
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723318
asked Aug 6 at 6:03


Daniyal Bilal
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closed as off-topic by Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister Aug 6 at 13:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister
closed as off-topic by Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister Aug 6 at 13:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Jyrki Lahtonen, amWhy, Jendrik Stelzner, Delta-u, Adrian Keister
1
You should show us what you have done so far.
– Le Anh Dung
Aug 6 at 6:10
This is from a competition from 2015: here's a link. In general it's good form to say exactly where/when the problem is from.
– Mason
Aug 6 at 7:07
add a comment |Â
1
You should show us what you have done so far.
– Le Anh Dung
Aug 6 at 6:10
This is from a competition from 2015: here's a link. In general it's good form to say exactly where/when the problem is from.
– Mason
Aug 6 at 7:07
1
1
You should show us what you have done so far.
– Le Anh Dung
Aug 6 at 6:10
You should show us what you have done so far.
– Le Anh Dung
Aug 6 at 6:10
This is from a competition from 2015: here's a link. In general it's good form to say exactly where/when the problem is from.
– Mason
Aug 6 at 7:07
This is from a competition from 2015: here's a link. In general it's good form to say exactly where/when the problem is from.
– Mason
Aug 6 at 7:07
add a comment |Â
1 Answer
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Given that the cut is just through the wall of the pipe, that means on the outside circle of diameter 20cm, and thus radius 10cm, it has a chord of length 10cm such that the chord is also tangent to the inner circle.
If you draw that chord and draw two segments connecting either endpoint of the chord to the center of the 10cm radius circle, you get an equilateral triangle. Taking the altitude of that triangle with the base being the chord, you can find the altitude length to be equal to $5 sqrt3$. This attitude is also the radius of the inner circle as the chord is tangent to the inner circle and altitudes form right angles with the base.
Thus, the thickness of the pipe is then $10 - 5 sqrt3 = 5(2-sqrt3)$, which is choice (E).
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
votes
active
oldest
votes
up vote
1
down vote
Given that the cut is just through the wall of the pipe, that means on the outside circle of diameter 20cm, and thus radius 10cm, it has a chord of length 10cm such that the chord is also tangent to the inner circle.
If you draw that chord and draw two segments connecting either endpoint of the chord to the center of the 10cm radius circle, you get an equilateral triangle. Taking the altitude of that triangle with the base being the chord, you can find the altitude length to be equal to $5 sqrt3$. This attitude is also the radius of the inner circle as the chord is tangent to the inner circle and altitudes form right angles with the base.
Thus, the thickness of the pipe is then $10 - 5 sqrt3 = 5(2-sqrt3)$, which is choice (E).
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Given that the cut is just through the wall of the pipe, that means on the outside circle of diameter 20cm, and thus radius 10cm, it has a chord of length 10cm such that the chord is also tangent to the inner circle.
If you draw that chord and draw two segments connecting either endpoint of the chord to the center of the 10cm radius circle, you get an equilateral triangle. Taking the altitude of that triangle with the base being the chord, you can find the altitude length to be equal to $5 sqrt3$. This attitude is also the radius of the inner circle as the chord is tangent to the inner circle and altitudes form right angles with the base.
Thus, the thickness of the pipe is then $10 - 5 sqrt3 = 5(2-sqrt3)$, which is choice (E).
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up vote
1
down vote
up vote
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down vote
Given that the cut is just through the wall of the pipe, that means on the outside circle of diameter 20cm, and thus radius 10cm, it has a chord of length 10cm such that the chord is also tangent to the inner circle.
If you draw that chord and draw two segments connecting either endpoint of the chord to the center of the 10cm radius circle, you get an equilateral triangle. Taking the altitude of that triangle with the base being the chord, you can find the altitude length to be equal to $5 sqrt3$. This attitude is also the radius of the inner circle as the chord is tangent to the inner circle and altitudes form right angles with the base.
Thus, the thickness of the pipe is then $10 - 5 sqrt3 = 5(2-sqrt3)$, which is choice (E).
Given that the cut is just through the wall of the pipe, that means on the outside circle of diameter 20cm, and thus radius 10cm, it has a chord of length 10cm such that the chord is also tangent to the inner circle.
If you draw that chord and draw two segments connecting either endpoint of the chord to the center of the 10cm radius circle, you get an equilateral triangle. Taking the altitude of that triangle with the base being the chord, you can find the altitude length to be equal to $5 sqrt3$. This attitude is also the radius of the inner circle as the chord is tangent to the inner circle and altitudes form right angles with the base.
Thus, the thickness of the pipe is then $10 - 5 sqrt3 = 5(2-sqrt3)$, which is choice (E).
answered Aug 6 at 6:14
Stone
329214
329214
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1
You should show us what you have done so far.
– Le Anh Dung
Aug 6 at 6:10
This is from a competition from 2015: here's a link. In general it's good form to say exactly where/when the problem is from.
– Mason
Aug 6 at 7:07