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Discuss when Newton's method gives linear or quadratic convergence for the function $f(x) = x^2(x - 1)$. [on hold]
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Discuss when Newton's method gives linear or quadratic convergence for the function $f(x) = x^2(x - 1)$.
if know that newtons method will converge quadratically when $f(p) = 0$ and $f'(p)$ not equal to 0. where p is the actual root. however, I m stuck on how to proceed with this problem. do I have to find the closest approx. to p and then try it? how about linear convergence?
optimization newton-raphson
asked Aug 3 at 9:06
Aryan Arora
12
put on hold as off-topic by José Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus Aug 4 at 2:29
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РJos̩ Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus
add a comment |Â
up vote
-4
down vote
favorite
Discuss when Newton's method gives linear or quadratic convergence for the function $f(x) = x^2(x - 1)$.
if know that newtons method will converge quadratically when $f(p) = 0$ and $f'(p)$ not equal to 0. where p is the actual root. however, I m stuck on how to proceed with this problem. do I have to find the closest approx. to p and then try it? how about linear convergence?
optimization newton-raphson
asked Aug 3 at 9:06
Aryan Arora
12
put on hold as off-topic by José Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus Aug 4 at 2:29
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РJos̩ Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus
You deleted your old math.stackexchange.com/questions/2870871/…, now be consequent and delete this one too because it is exactly the same.
– gammatester
Aug 3 at 9:09
@gammatester i did it because someone kept commenting jokes and all. idk why people just want to be rude here and not just help. i am being extremely polite.
– Aryan Arora
Aug 3 at 9:12
@gammatester i did not get any help and that's why i asked it again. uk why? coz people like you just want to poke others instead of just helping. instead of being so rude be consequent and leave.
– Aryan Arora
Aug 3 at 9:17
1
You did not even say, where and why you get stuck. How can we help then? And I suggest that you read math.stackexchange.com/help/how-to-ask
– gammatester
Aug 3 at 9:22
@gammatester I clearly stated my idea and asked if that's the right thing.
– Aryan Arora
Aug 3 at 9:23
add a comment |Â
up vote
-4
down vote
favorite
up vote
-4
down vote
favorite
Discuss when Newton's method gives linear or quadratic convergence for the function $f(x) = x^2(x - 1)$.
if know that newtons method will converge quadratically when $f(p) = 0$ and $f'(p)$ not equal to 0. where p is the actual root. however, I m stuck on how to proceed with this problem. do I have to find the closest approx. to p and then try it? how about linear convergence?
optimization newton-raphson
asked Aug 3 at 9:06
Aryan Arora
12
Discuss when Newton's method gives linear or quadratic convergence for the function $f(x) = x^2(x - 1)$.
if know that newtons method will converge quadratically when $f(p) = 0$ and $f'(p)$ not equal to 0. where p is the actual root. however, I m stuck on how to proceed with this problem. do I have to find the closest approx. to p and then try it? how about linear convergence?
optimization newton-raphson
asked Aug 3 at 9:06
Aryan Arora
12
asked Aug 3 at 9:06
Aryan Arora
12
asked Aug 3 at 9:06
Aryan Arora
12
asked Aug 3 at 9:06
Aryan Arora
12
12
put on hold as off-topic by José Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus Aug 4 at 2:29
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РJos̩ Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus
put on hold as off-topic by José Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus Aug 4 at 2:29
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." РJos̩ Carlos Santos, John B, Claude Leibovici, max_zorn, Leucippus
You deleted your old math.stackexchange.com/questions/2870871/…, now be consequent and delete this one too because it is exactly the same.
– gammatester
Aug 3 at 9:09
@gammatester i did it because someone kept commenting jokes and all. idk why people just want to be rude here and not just help. i am being extremely polite.
– Aryan Arora
Aug 3 at 9:12
@gammatester i did not get any help and that's why i asked it again. uk why? coz people like you just want to poke others instead of just helping. instead of being so rude be consequent and leave.
– Aryan Arora
Aug 3 at 9:17
1
You did not even say, where and why you get stuck. How can we help then? And I suggest that you read math.stackexchange.com/help/how-to-ask
– gammatester
Aug 3 at 9:22
@gammatester I clearly stated my idea and asked if that's the right thing.
– Aryan Arora
Aug 3 at 9:23
add a comment |Â
You deleted your old math.stackexchange.com/questions/2870871/…, now be consequent and delete this one too because it is exactly the same.
– gammatester
Aug 3 at 9:09
@gammatester i did it because someone kept commenting jokes and all. idk why people just want to be rude here and not just help. i am being extremely polite.
– Aryan Arora
Aug 3 at 9:12
@gammatester i did not get any help and that's why i asked it again. uk why? coz people like you just want to poke others instead of just helping. instead of being so rude be consequent and leave.
– Aryan Arora
Aug 3 at 9:17
1
You did not even say, where and why you get stuck. How can we help then? And I suggest that you read math.stackexchange.com/help/how-to-ask
– gammatester
Aug 3 at 9:22
@gammatester I clearly stated my idea and asked if that's the right thing.
– Aryan Arora
Aug 3 at 9:23
You deleted your old math.stackexchange.com/questions/2870871/…, now be consequent and delete this one too because it is exactly the same.
– gammatester
Aug 3 at 9:09
You deleted your old math.stackexchange.com/questions/2870871/…, now be consequent and delete this one too because it is exactly the same.
– gammatester
Aug 3 at 9:09
@gammatester i did it because someone kept commenting jokes and all. idk why people just want to be rude here and not just help. i am being extremely polite.
– Aryan Arora
Aug 3 at 9:12
@gammatester i did it because someone kept commenting jokes and all. idk why people just want to be rude here and not just help. i am being extremely polite.
– Aryan Arora
Aug 3 at 9:12
@gammatester i did not get any help and that's why i asked it again. uk why? coz people like you just want to poke others instead of just helping. instead of being so rude be consequent and leave.
– Aryan Arora
Aug 3 at 9:17
@gammatester i did not get any help and that's why i asked it again. uk why? coz people like you just want to poke others instead of just helping. instead of being so rude be consequent and leave.
– Aryan Arora
Aug 3 at 9:17
1
1
You did not even say, where and why you get stuck. How can we help then? And I suggest that you read math.stackexchange.com/help/how-to-ask
– gammatester
Aug 3 at 9:22
You did not even say, where and why you get stuck. How can we help then? And I suggest that you read math.stackexchange.com/help/how-to-ask
– gammatester
Aug 3 at 9:22
@gammatester I clearly stated my idea and asked if that's the right thing.
– Aryan Arora
Aug 3 at 9:23
@gammatester I clearly stated my idea and asked if that's the right thing.
– Aryan Arora
Aug 3 at 9:23
add a comment |Â
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You deleted your old math.stackexchange.com/questions/2870871/…, now be consequent and delete this one too because it is exactly the same.
– gammatester
Aug 3 at 9:09
@gammatester i did it because someone kept commenting jokes and all. idk why people just want to be rude here and not just help. i am being extremely polite.
– Aryan Arora
Aug 3 at 9:12
@gammatester i did not get any help and that's why i asked it again. uk why? coz people like you just want to poke others instead of just helping. instead of being so rude be consequent and leave.
– Aryan Arora
Aug 3 at 9:17
1
You did not even say, where and why you get stuck. How can we help then? And I suggest that you read math.stackexchange.com/help/how-to-ask
– gammatester
Aug 3 at 9:22
@gammatester I clearly stated my idea and asked if that's the right thing.
– Aryan Arora
Aug 3 at 9:23