Probability 2 dice question [closed]
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If $2$ six sided dice are rolled, what are the odds of getting matching numbers?
probability
closed as off-topic by amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024 Aug 2 at 19:20
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024
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If $2$ six sided dice are rolled, what are the odds of getting matching numbers?
probability
closed as off-topic by amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024 Aug 2 at 19:20
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024
2
Hint: first roll a die that results in some number. What is the probability that the second die results in this number?
– drhab
Aug 2 at 18:17
1/6? The answer I have is 1/5, hence I got confused
– user9513164
Aug 2 at 18:19
2
$1/6$ is correct (if the dice are unbiased).
– drhab
Aug 2 at 18:22
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up vote
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down vote
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If $2$ six sided dice are rolled, what are the odds of getting matching numbers?
probability
If $2$ six sided dice are rolled, what are the odds of getting matching numbers?
probability
edited Aug 2 at 18:49
Javi
2,1481625
2,1481625
asked Aug 2 at 18:13
user9513164
123
123
closed as off-topic by amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024 Aug 2 at 19:20
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024
closed as off-topic by amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024 Aug 2 at 19:20
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, José Carlos Santos, John Ma, Mostafa Ayaz, Stefan4024
2
Hint: first roll a die that results in some number. What is the probability that the second die results in this number?
– drhab
Aug 2 at 18:17
1/6? The answer I have is 1/5, hence I got confused
– user9513164
Aug 2 at 18:19
2
$1/6$ is correct (if the dice are unbiased).
– drhab
Aug 2 at 18:22
add a comment |Â
2
Hint: first roll a die that results in some number. What is the probability that the second die results in this number?
– drhab
Aug 2 at 18:17
1/6? The answer I have is 1/5, hence I got confused
– user9513164
Aug 2 at 18:19
2
$1/6$ is correct (if the dice are unbiased).
– drhab
Aug 2 at 18:22
2
2
Hint: first roll a die that results in some number. What is the probability that the second die results in this number?
– drhab
Aug 2 at 18:17
Hint: first roll a die that results in some number. What is the probability that the second die results in this number?
– drhab
Aug 2 at 18:17
1/6? The answer I have is 1/5, hence I got confused
– user9513164
Aug 2 at 18:19
1/6? The answer I have is 1/5, hence I got confused
– user9513164
Aug 2 at 18:19
2
2
$1/6$ is correct (if the dice are unbiased).
– drhab
Aug 2 at 18:22
$1/6$ is correct (if the dice are unbiased).
– drhab
Aug 2 at 18:22
add a comment |Â
2 Answers
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Two six-sided dice are thrown the sample space is given by $Omega = 1,2,3,4,5,6 times 1,2,3,4,5,6 $
$$beginbmatrix (1,1) & (2,1) & (3,1) & (4,1) & (5,1) & (6,1) \ (1,2) & (2,2) & (3,2) & (4,2) & (5,2) & (6,2) \ (1,3) & (2,3) & (3,3) & (4,3) & (5,3) & (6,3) \ (1,4) & (2,4) & (3,4) & (4,4) & (5,4) & (6,4) \ (1,5) & (2,5) & (3,5) & (4,5) & (5,5) & (6,5) \ (1,6) & (2,6) & (3,6) & (4,6) & (5,6) & (6,6) \ endbmatrix $$
There are $36 $ possibilites. Right across the diagonal we have doubles. That is
$$ D = (1,1) ,(2,2) ,(3,3),(4,4),(5,5),(6,6) $$
The probability is
$$ P = fracDOmega = frac636 = frac16$$
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1 out of 6. The first die roll you can get anything. The second die rolled has to be one specific value out of 6 possible outcomes.
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Two six-sided dice are thrown the sample space is given by $Omega = 1,2,3,4,5,6 times 1,2,3,4,5,6 $
$$beginbmatrix (1,1) & (2,1) & (3,1) & (4,1) & (5,1) & (6,1) \ (1,2) & (2,2) & (3,2) & (4,2) & (5,2) & (6,2) \ (1,3) & (2,3) & (3,3) & (4,3) & (5,3) & (6,3) \ (1,4) & (2,4) & (3,4) & (4,4) & (5,4) & (6,4) \ (1,5) & (2,5) & (3,5) & (4,5) & (5,5) & (6,5) \ (1,6) & (2,6) & (3,6) & (4,6) & (5,6) & (6,6) \ endbmatrix $$
There are $36 $ possibilites. Right across the diagonal we have doubles. That is
$$ D = (1,1) ,(2,2) ,(3,3),(4,4),(5,5),(6,6) $$
The probability is
$$ P = fracDOmega = frac636 = frac16$$
add a comment |Â
up vote
1
down vote
Two six-sided dice are thrown the sample space is given by $Omega = 1,2,3,4,5,6 times 1,2,3,4,5,6 $
$$beginbmatrix (1,1) & (2,1) & (3,1) & (4,1) & (5,1) & (6,1) \ (1,2) & (2,2) & (3,2) & (4,2) & (5,2) & (6,2) \ (1,3) & (2,3) & (3,3) & (4,3) & (5,3) & (6,3) \ (1,4) & (2,4) & (3,4) & (4,4) & (5,4) & (6,4) \ (1,5) & (2,5) & (3,5) & (4,5) & (5,5) & (6,5) \ (1,6) & (2,6) & (3,6) & (4,6) & (5,6) & (6,6) \ endbmatrix $$
There are $36 $ possibilites. Right across the diagonal we have doubles. That is
$$ D = (1,1) ,(2,2) ,(3,3),(4,4),(5,5),(6,6) $$
The probability is
$$ P = fracDOmega = frac636 = frac16$$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Two six-sided dice are thrown the sample space is given by $Omega = 1,2,3,4,5,6 times 1,2,3,4,5,6 $
$$beginbmatrix (1,1) & (2,1) & (3,1) & (4,1) & (5,1) & (6,1) \ (1,2) & (2,2) & (3,2) & (4,2) & (5,2) & (6,2) \ (1,3) & (2,3) & (3,3) & (4,3) & (5,3) & (6,3) \ (1,4) & (2,4) & (3,4) & (4,4) & (5,4) & (6,4) \ (1,5) & (2,5) & (3,5) & (4,5) & (5,5) & (6,5) \ (1,6) & (2,6) & (3,6) & (4,6) & (5,6) & (6,6) \ endbmatrix $$
There are $36 $ possibilites. Right across the diagonal we have doubles. That is
$$ D = (1,1) ,(2,2) ,(3,3),(4,4),(5,5),(6,6) $$
The probability is
$$ P = fracDOmega = frac636 = frac16$$
Two six-sided dice are thrown the sample space is given by $Omega = 1,2,3,4,5,6 times 1,2,3,4,5,6 $
$$beginbmatrix (1,1) & (2,1) & (3,1) & (4,1) & (5,1) & (6,1) \ (1,2) & (2,2) & (3,2) & (4,2) & (5,2) & (6,2) \ (1,3) & (2,3) & (3,3) & (4,3) & (5,3) & (6,3) \ (1,4) & (2,4) & (3,4) & (4,4) & (5,4) & (6,4) \ (1,5) & (2,5) & (3,5) & (4,5) & (5,5) & (6,5) \ (1,6) & (2,6) & (3,6) & (4,6) & (5,6) & (6,6) \ endbmatrix $$
There are $36 $ possibilites. Right across the diagonal we have doubles. That is
$$ D = (1,1) ,(2,2) ,(3,3),(4,4),(5,5),(6,6) $$
The probability is
$$ P = fracDOmega = frac636 = frac16$$
answered Aug 2 at 18:26


RHowe
825715
825715
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1 out of 6. The first die roll you can get anything. The second die rolled has to be one specific value out of 6 possible outcomes.
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
add a comment |Â
up vote
0
down vote
1 out of 6. The first die roll you can get anything. The second die rolled has to be one specific value out of 6 possible outcomes.
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
add a comment |Â
up vote
0
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up vote
0
down vote
1 out of 6. The first die roll you can get anything. The second die rolled has to be one specific value out of 6 possible outcomes.
1 out of 6. The first die roll you can get anything. The second die rolled has to be one specific value out of 6 possible outcomes.
answered Aug 2 at 18:17


Mason
1,1271223
1,1271223
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
add a comment |Â
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Thanks for confirming!
– user9513164
Aug 2 at 18:20
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
Yup. Follow up: what's the probability that you roll two die and get different numbers?
– Mason
Aug 2 at 18:22
add a comment |Â
2
Hint: first roll a die that results in some number. What is the probability that the second die results in this number?
– drhab
Aug 2 at 18:17
1/6? The answer I have is 1/5, hence I got confused
– user9513164
Aug 2 at 18:19
2
$1/6$ is correct (if the dice are unbiased).
– drhab
Aug 2 at 18:22