Proving $int x^x dx$ is not elementary
Clash Royale CLAN TAG#URR8PPP
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Please verify if my reasoning is correct.
Write $x^x$ as $e^xln x$. Then let $f(x)=1$ and $g(x)=xln x$.
$R'(x) + g'(x)R(x) = f(x)$ will be $R'(x) + (ln x+1)R(x) = 1$, which solution is $R(x) = c_1x^-x + x^-x int_1^x u^u du$, then there's no rational solution $R$ to the ode, then $int x^x dx$ is not elementary, by Liouville's Theorem Corollary (page 24).
Thanks!
calculus integration indefinite-integrals elementary-functions
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up vote
0
down vote
favorite
Please verify if my reasoning is correct.
Write $x^x$ as $e^xln x$. Then let $f(x)=1$ and $g(x)=xln x$.
$R'(x) + g'(x)R(x) = f(x)$ will be $R'(x) + (ln x+1)R(x) = 1$, which solution is $R(x) = c_1x^-x + x^-x int_1^x u^u du$, then there's no rational solution $R$ to the ode, then $int x^x dx$ is not elementary, by Liouville's Theorem Corollary (page 24).
Thanks!
calculus integration indefinite-integrals elementary-functions
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Please verify if my reasoning is correct.
Write $x^x$ as $e^xln x$. Then let $f(x)=1$ and $g(x)=xln x$.
$R'(x) + g'(x)R(x) = f(x)$ will be $R'(x) + (ln x+1)R(x) = 1$, which solution is $R(x) = c_1x^-x + x^-x int_1^x u^u du$, then there's no rational solution $R$ to the ode, then $int x^x dx$ is not elementary, by Liouville's Theorem Corollary (page 24).
Thanks!
calculus integration indefinite-integrals elementary-functions
Please verify if my reasoning is correct.
Write $x^x$ as $e^xln x$. Then let $f(x)=1$ and $g(x)=xln x$.
$R'(x) + g'(x)R(x) = f(x)$ will be $R'(x) + (ln x+1)R(x) = 1$, which solution is $R(x) = c_1x^-x + x^-x int_1^x u^u du$, then there's no rational solution $R$ to the ode, then $int x^x dx$ is not elementary, by Liouville's Theorem Corollary (page 24).
Thanks!
calculus integration indefinite-integrals elementary-functions
asked Aug 6 at 4:21
dude3221
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