RSA cryptosystem - discrete secret primes

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Why do we bother to take $n$ as a product of two secret primes in RSA cryptosystem? If $e$ is public, $d$ is private and prime factorization of $n$ is not secret, what would happen?




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    Why do we bother to take $n$ as a product of two secret primes in RSA cryptosystem? If $e$ is public, $d$ is private and prime factorization of $n$ is not secret, what would happen?




    cryptography




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      Why do we bother to take $n$ as a product of two secret primes in RSA cryptosystem? If $e$ is public, $d$ is private and prime factorization of $n$ is not secret, what would happen?




      cryptography




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      Why do we bother to take $n$ as a product of two secret primes in RSA cryptosystem? If $e$ is public, $d$ is private and prime factorization of $n$ is not secret, what would happen?





      cryptography





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          I'm referring to https://simple.wikipedia.org/wiki/RSA_algorithm



          If anybody knows the factorization of $n$, they can effectively calculate $phi(n)$ (Euler totient function) and then with the knowledge of the public key $e$ do step 5 from the linked website themselves effectively. So they have the private key $d$ and can now do everything the 'rightful' owner of the private key can do.






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            I'm referring to https://simple.wikipedia.org/wiki/RSA_algorithm



            If anybody knows the factorization of $n$, they can effectively calculate $phi(n)$ (Euler totient function) and then with the knowledge of the public key $e$ do step 5 from the linked website themselves effectively. So they have the private key $d$ and can now do everything the 'rightful' owner of the private key can do.






            share|cite|improve this answer

























              up vote
              1
              down vote













              I'm referring to https://simple.wikipedia.org/wiki/RSA_algorithm



              If anybody knows the factorization of $n$, they can effectively calculate $phi(n)$ (Euler totient function) and then with the knowledge of the public key $e$ do step 5 from the linked website themselves effectively. So they have the private key $d$ and can now do everything the 'rightful' owner of the private key can do.






              share|cite|improve this answer























                up vote
                1
                down vote










                up vote
                1
                down vote









                I'm referring to https://simple.wikipedia.org/wiki/RSA_algorithm



                If anybody knows the factorization of $n$, they can effectively calculate $phi(n)$ (Euler totient function) and then with the knowledge of the public key $e$ do step 5 from the linked website themselves effectively. So they have the private key $d$ and can now do everything the 'rightful' owner of the private key can do.






                share|cite|improve this answer













                I'm referring to https://simple.wikipedia.org/wiki/RSA_algorithm



                If anybody knows the factorization of $n$, they can effectively calculate $phi(n)$ (Euler totient function) and then with the knowledge of the public key $e$ do step 5 from the linked website themselves effectively. So they have the private key $d$ and can now do everything the 'rightful' owner of the private key can do.







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                answered yesterday









                Ingix

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