With $1>a,b,c,d>0$ does $a-b>c-d>0$ imply $a/b>c/d$? [on hold]

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I can prove that if $d>b$ then the implication is true, but what if $dle b $?




algebra-precalculus inequality real-numbers




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put on hold as unclear what you're asking by amWhy, Leucippus, Lord Shark the Unknown, Taroccoesbrocco, Shailesh yesterday


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • You question is wrong no matter lager than $1$ or smaller than $1$.
    – Riemann
    2 days ago














up vote
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down vote

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1












I can prove that if $d>b$ then the implication is true, but what if $dle b $?




algebra-precalculus inequality real-numbers




share|cite|improve this question











put on hold as unclear what you're asking by amWhy, Leucippus, Lord Shark the Unknown, Taroccoesbrocco, Shailesh yesterday


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • You question is wrong no matter lager than $1$ or smaller than $1$.
    – Riemann
    2 days ago












up vote
-1
down vote

favorite
1









up vote
-1
down vote

favorite
1






1





I can prove that if $d>b$ then the implication is true, but what if $dle b $?




algebra-precalculus inequality real-numbers




share|cite|improve this question











I can prove that if $d>b$ then the implication is true, but what if $dle b $?





algebra-precalculus inequality real-numbers





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked 2 days ago









Richard

515511




515511




put on hold as unclear what you're asking by amWhy, Leucippus, Lord Shark the Unknown, Taroccoesbrocco, Shailesh yesterday


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






put on hold as unclear what you're asking by amWhy, Leucippus, Lord Shark the Unknown, Taroccoesbrocco, Shailesh yesterday


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.













  • You question is wrong no matter lager than $1$ or smaller than $1$.
    – Riemann
    2 days ago
















  • You question is wrong no matter lager than $1$ or smaller than $1$.
    – Riemann
    2 days ago















You question is wrong no matter lager than $1$ or smaller than $1$.
– Riemann
2 days ago




You question is wrong no matter lager than $1$ or smaller than $1$.
– Riemann
2 days ago










1 Answer
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The implication is not true in general; here is a counterexample.



Consider $a=0.9,b=0.7,c=0.2,d=0.1$. Then $a-b=0.2>c-d=0.1>0$, but $fracab=frac97<fraccd=2$.






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote



    accepted










    The implication is not true in general; here is a counterexample.



    Consider $a=0.9,b=0.7,c=0.2,d=0.1$. Then $a-b=0.2>c-d=0.1>0$, but $fracab=frac97<fraccd=2$.






    share|cite|improve this answer

























      up vote
      2
      down vote



      accepted










      The implication is not true in general; here is a counterexample.



      Consider $a=0.9,b=0.7,c=0.2,d=0.1$. Then $a-b=0.2>c-d=0.1>0$, but $fracab=frac97<fraccd=2$.






      share|cite|improve this answer























        up vote
        2
        down vote



        accepted







        up vote
        2
        down vote



        accepted






        The implication is not true in general; here is a counterexample.



        Consider $a=0.9,b=0.7,c=0.2,d=0.1$. Then $a-b=0.2>c-d=0.1>0$, but $fracab=frac97<fraccd=2$.






        share|cite|improve this answer













        The implication is not true in general; here is a counterexample.



        Consider $a=0.9,b=0.7,c=0.2,d=0.1$. Then $a-b=0.2>c-d=0.1>0$, but $fracab=frac97<fraccd=2$.







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        share|cite|improve this answer











        answered 2 days ago









        Benedict Randall Shaw

        1367




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