Can we express $expBig(sum_ialpha_iln(x_i)Big) = sum_ialpha_iexpbig(ln(x_i)big)$? [closed]

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Is this equality correct:
$$expBig(sum_ialpha_iln(x_i)Big) = sum_ialpha_iexpbig(ln(x_i)big),?$$



I need to express $prod_ix_i^alpha^i$ using exp and logarithm.



How can I do this if the aforementioned way is incorrect?




exponential-function




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closed as off-topic by Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex Jul 29 at 0:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    No it is not....
    – Randall
    Jul 28 at 17:56










  • By properties of the exponential function: $e^sum_i a_i=prod_i e^a_i$
    – Michal Dvořák
    Jul 28 at 17:58











  • What makes you think that it could be correct?
    – Vera
    Jul 28 at 18:05










  • In the first place, i dont know the reason for downvoting. Could you please point me the problem with my question
    – Malintha
    Jul 28 at 18:06














up vote
-6
down vote

favorite












Is this equality correct:
$$expBig(sum_ialpha_iln(x_i)Big) = sum_ialpha_iexpbig(ln(x_i)big),?$$



I need to express $prod_ix_i^alpha^i$ using exp and logarithm.



How can I do this if the aforementioned way is incorrect?




exponential-function




share|cite|improve this question













closed as off-topic by Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex Jul 29 at 0:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    No it is not....
    – Randall
    Jul 28 at 17:56










  • By properties of the exponential function: $e^sum_i a_i=prod_i e^a_i$
    – Michal Dvořák
    Jul 28 at 17:58











  • What makes you think that it could be correct?
    – Vera
    Jul 28 at 18:05










  • In the first place, i dont know the reason for downvoting. Could you please point me the problem with my question
    – Malintha
    Jul 28 at 18:06












up vote
-6
down vote

favorite









up vote
-6
down vote

favorite











Is this equality correct:
$$expBig(sum_ialpha_iln(x_i)Big) = sum_ialpha_iexpbig(ln(x_i)big),?$$



I need to express $prod_ix_i^alpha^i$ using exp and logarithm.



How can I do this if the aforementioned way is incorrect?




exponential-function




share|cite|improve this question













Is this equality correct:
$$expBig(sum_ialpha_iln(x_i)Big) = sum_ialpha_iexpbig(ln(x_i)big),?$$



I need to express $prod_ix_i^alpha^i$ using exp and logarithm.



How can I do this if the aforementioned way is incorrect?





exponential-function





share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 28 at 18:18









Batominovski

23k22777




23k22777









asked Jul 28 at 17:55









Malintha

1276




1276




closed as off-topic by Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex Jul 29 at 0:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex Jul 29 at 0:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Batominovski, José Carlos Santos, Shaun, amWhy, Key Flex
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 2




    No it is not....
    – Randall
    Jul 28 at 17:56










  • By properties of the exponential function: $e^sum_i a_i=prod_i e^a_i$
    – Michal Dvořák
    Jul 28 at 17:58











  • What makes you think that it could be correct?
    – Vera
    Jul 28 at 18:05










  • In the first place, i dont know the reason for downvoting. Could you please point me the problem with my question
    – Malintha
    Jul 28 at 18:06












  • 2




    No it is not....
    – Randall
    Jul 28 at 17:56










  • By properties of the exponential function: $e^sum_i a_i=prod_i e^a_i$
    – Michal Dvořák
    Jul 28 at 17:58











  • What makes you think that it could be correct?
    – Vera
    Jul 28 at 18:05










  • In the first place, i dont know the reason for downvoting. Could you please point me the problem with my question
    – Malintha
    Jul 28 at 18:06







2




2




No it is not....
– Randall
Jul 28 at 17:56




No it is not....
– Randall
Jul 28 at 17:56












By properties of the exponential function: $e^sum_i a_i=prod_i e^a_i$
– Michal Dvořák
Jul 28 at 17:58





By properties of the exponential function: $e^sum_i a_i=prod_i e^a_i$
– Michal Dvořák
Jul 28 at 17:58













What makes you think that it could be correct?
– Vera
Jul 28 at 18:05




What makes you think that it could be correct?
– Vera
Jul 28 at 18:05












In the first place, i dont know the reason for downvoting. Could you please point me the problem with my question
– Malintha
Jul 28 at 18:06




In the first place, i dont know the reason for downvoting. Could you please point me the problem with my question
– Malintha
Jul 28 at 18:06










1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










No, it is incorrect. Instead of the sum on the r.h.s, you need a product.



$$exp(sum_ialpha_iln x_i)=prod_ix_i^alpha_i$$






share|cite|improve this answer





















  • I edited my question with my original problem. can you have a look
    – Malintha
    Jul 28 at 18:00










  • Isn’t this answer exactly what you want??
    – Randall
    Jul 28 at 18:02










  • yes, it is.....
    – Malintha
    Jul 28 at 18:05

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










No, it is incorrect. Instead of the sum on the r.h.s, you need a product.



$$exp(sum_ialpha_iln x_i)=prod_ix_i^alpha_i$$






share|cite|improve this answer





















  • I edited my question with my original problem. can you have a look
    – Malintha
    Jul 28 at 18:00










  • Isn’t this answer exactly what you want??
    – Randall
    Jul 28 at 18:02










  • yes, it is.....
    – Malintha
    Jul 28 at 18:05














up vote
2
down vote



accepted










No, it is incorrect. Instead of the sum on the r.h.s, you need a product.



$$exp(sum_ialpha_iln x_i)=prod_ix_i^alpha_i$$






share|cite|improve this answer





















  • I edited my question with my original problem. can you have a look
    – Malintha
    Jul 28 at 18:00










  • Isn’t this answer exactly what you want??
    – Randall
    Jul 28 at 18:02










  • yes, it is.....
    – Malintha
    Jul 28 at 18:05












up vote
2
down vote



accepted







up vote
2
down vote



accepted






No, it is incorrect. Instead of the sum on the r.h.s, you need a product.



$$exp(sum_ialpha_iln x_i)=prod_ix_i^alpha_i$$






share|cite|improve this answer













No, it is incorrect. Instead of the sum on the r.h.s, you need a product.



$$exp(sum_ialpha_iln x_i)=prod_ix_i^alpha_i$$







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered Jul 28 at 17:56









uniquesolution

7,536721




7,536721











  • I edited my question with my original problem. can you have a look
    – Malintha
    Jul 28 at 18:00










  • Isn’t this answer exactly what you want??
    – Randall
    Jul 28 at 18:02










  • yes, it is.....
    – Malintha
    Jul 28 at 18:05
















  • I edited my question with my original problem. can you have a look
    – Malintha
    Jul 28 at 18:00










  • Isn’t this answer exactly what you want??
    – Randall
    Jul 28 at 18:02










  • yes, it is.....
    – Malintha
    Jul 28 at 18:05















I edited my question with my original problem. can you have a look
– Malintha
Jul 28 at 18:00




I edited my question with my original problem. can you have a look
– Malintha
Jul 28 at 18:00












Isn’t this answer exactly what you want??
– Randall
Jul 28 at 18:02




Isn’t this answer exactly what you want??
– Randall
Jul 28 at 18:02












yes, it is.....
– Malintha
Jul 28 at 18:05




yes, it is.....
– Malintha
Jul 28 at 18:05


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