The Hilbert space $textIm(M^1/2)$, where $M$ is a positive operator.

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In this question $F$ stands for a complex Hilbert space with inner product $langlecdot;,;cdotrangle$ and the norm $|cdot|$. Let $mathcalB(F)$ the algebra of all bounded linear operators on $F$.



Let $Min mathcalB(F)^+$ (i.e. $langle Mx;, ;xranglegeq 0$ for all $xin F$) and $P$ be the orthogonal projection of $F$ onto the closure of $textIm(M)$.



According to this answer $textIm(M^1/2)$ endow with the inner product
$$tag1 (M^1/2x,M^1/2y)_textIm(M^1/2):=langle Px, Pyrangle,;forall, x,y in F,$$
is a Hilbert space.



َAccording also to this answer, for any $xin F$ there exists a sequence $(x_n)_n$ with
$$M^1/2x=lim_nto infty Mx_n Longleftrightarrow lim_nto infty|Mx_n-M^1/2x|=0.$$




If $SinmathcalB(textIm(M^1/2))$, is it true that for all $xin F$, we have
$$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);?$$




I ask this question because I see in this paper that $textIm(M)$ is dense in $textIm(M^1/2)$. However, I'm facing difficulties to understand if the density is with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1) or with respect to the topology induced by $langlecdot,cdotrangle$.







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  • The second link shows that $operatornameIm(M)$ is dense in $operatornameIm(M^1/2)$ with respect to the subspace topology induced by $F$, i.e. with respect to $langle,cdot,,,cdot,rangle$. I don't know right away whether it's also dense with respect to the topology coming from $(1)$. For a general $S in mathcalB(F)$, we must expect $SM^1/2xnotin operatornameIm(M^1/2)$, so the highlighted part doesn't make sense in the stated generality.
    – Daniel Fischer♦
    17 hours ago










  • @DanielFischer Thank you very much for your comment. Sorry, here $SinmathcalB(textIm(M^1/2))$ and thus $SM^1/2xin textIm(M^1/2)$ for all $xin F$.
    – Schüler
    15 hours ago










  • @DanielFischer Is the equality $$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);$$ true only if $textIm(M)$ is dense in $textIm(M^1/2)$ with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1)? Thank you for your help.
    – Schüler
    12 hours ago














up vote
3
down vote

favorite












In this question $F$ stands for a complex Hilbert space with inner product $langlecdot;,;cdotrangle$ and the norm $|cdot|$. Let $mathcalB(F)$ the algebra of all bounded linear operators on $F$.



Let $Min mathcalB(F)^+$ (i.e. $langle Mx;, ;xranglegeq 0$ for all $xin F$) and $P$ be the orthogonal projection of $F$ onto the closure of $textIm(M)$.



According to this answer $textIm(M^1/2)$ endow with the inner product
$$tag1 (M^1/2x,M^1/2y)_textIm(M^1/2):=langle Px, Pyrangle,;forall, x,y in F,$$
is a Hilbert space.



َAccording also to this answer, for any $xin F$ there exists a sequence $(x_n)_n$ with
$$M^1/2x=lim_nto infty Mx_n Longleftrightarrow lim_nto infty|Mx_n-M^1/2x|=0.$$




If $SinmathcalB(textIm(M^1/2))$, is it true that for all $xin F$, we have
$$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);?$$




I ask this question because I see in this paper that $textIm(M)$ is dense in $textIm(M^1/2)$. However, I'm facing difficulties to understand if the density is with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1) or with respect to the topology induced by $langlecdot,cdotrangle$.







share|cite|improve this question





















  • The second link shows that $operatornameIm(M)$ is dense in $operatornameIm(M^1/2)$ with respect to the subspace topology induced by $F$, i.e. with respect to $langle,cdot,,,cdot,rangle$. I don't know right away whether it's also dense with respect to the topology coming from $(1)$. For a general $S in mathcalB(F)$, we must expect $SM^1/2xnotin operatornameIm(M^1/2)$, so the highlighted part doesn't make sense in the stated generality.
    – Daniel Fischer♦
    17 hours ago










  • @DanielFischer Thank you very much for your comment. Sorry, here $SinmathcalB(textIm(M^1/2))$ and thus $SM^1/2xin textIm(M^1/2)$ for all $xin F$.
    – Schüler
    15 hours ago










  • @DanielFischer Is the equality $$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);$$ true only if $textIm(M)$ is dense in $textIm(M^1/2)$ with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1)? Thank you for your help.
    – Schüler
    12 hours ago












up vote
3
down vote

favorite









up vote
3
down vote

favorite











In this question $F$ stands for a complex Hilbert space with inner product $langlecdot;,;cdotrangle$ and the norm $|cdot|$. Let $mathcalB(F)$ the algebra of all bounded linear operators on $F$.



Let $Min mathcalB(F)^+$ (i.e. $langle Mx;, ;xranglegeq 0$ for all $xin F$) and $P$ be the orthogonal projection of $F$ onto the closure of $textIm(M)$.



According to this answer $textIm(M^1/2)$ endow with the inner product
$$tag1 (M^1/2x,M^1/2y)_textIm(M^1/2):=langle Px, Pyrangle,;forall, x,y in F,$$
is a Hilbert space.



َAccording also to this answer, for any $xin F$ there exists a sequence $(x_n)_n$ with
$$M^1/2x=lim_nto infty Mx_n Longleftrightarrow lim_nto infty|Mx_n-M^1/2x|=0.$$




If $SinmathcalB(textIm(M^1/2))$, is it true that for all $xin F$, we have
$$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);?$$




I ask this question because I see in this paper that $textIm(M)$ is dense in $textIm(M^1/2)$. However, I'm facing difficulties to understand if the density is with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1) or with respect to the topology induced by $langlecdot,cdotrangle$.







share|cite|improve this question













In this question $F$ stands for a complex Hilbert space with inner product $langlecdot;,;cdotrangle$ and the norm $|cdot|$. Let $mathcalB(F)$ the algebra of all bounded linear operators on $F$.



Let $Min mathcalB(F)^+$ (i.e. $langle Mx;, ;xranglegeq 0$ for all $xin F$) and $P$ be the orthogonal projection of $F$ onto the closure of $textIm(M)$.



According to this answer $textIm(M^1/2)$ endow with the inner product
$$tag1 (M^1/2x,M^1/2y)_textIm(M^1/2):=langle Px, Pyrangle,;forall, x,y in F,$$
is a Hilbert space.



َAccording also to this answer, for any $xin F$ there exists a sequence $(x_n)_n$ with
$$M^1/2x=lim_nto infty Mx_n Longleftrightarrow lim_nto infty|Mx_n-M^1/2x|=0.$$




If $SinmathcalB(textIm(M^1/2))$, is it true that for all $xin F$, we have
$$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);?$$




I ask this question because I see in this paper that $textIm(M)$ is dense in $textIm(M^1/2)$. However, I'm facing difficulties to understand if the density is with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1) or with respect to the topology induced by $langlecdot,cdotrangle$.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited 15 hours ago
























asked Jul 28 at 11:29









Schüler

1,3311321




1,3311321











  • The second link shows that $operatornameIm(M)$ is dense in $operatornameIm(M^1/2)$ with respect to the subspace topology induced by $F$, i.e. with respect to $langle,cdot,,,cdot,rangle$. I don't know right away whether it's also dense with respect to the topology coming from $(1)$. For a general $S in mathcalB(F)$, we must expect $SM^1/2xnotin operatornameIm(M^1/2)$, so the highlighted part doesn't make sense in the stated generality.
    – Daniel Fischer♦
    17 hours ago










  • @DanielFischer Thank you very much for your comment. Sorry, here $SinmathcalB(textIm(M^1/2))$ and thus $SM^1/2xin textIm(M^1/2)$ for all $xin F$.
    – Schüler
    15 hours ago










  • @DanielFischer Is the equality $$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);$$ true only if $textIm(M)$ is dense in $textIm(M^1/2)$ with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1)? Thank you for your help.
    – Schüler
    12 hours ago
















  • The second link shows that $operatornameIm(M)$ is dense in $operatornameIm(M^1/2)$ with respect to the subspace topology induced by $F$, i.e. with respect to $langle,cdot,,,cdot,rangle$. I don't know right away whether it's also dense with respect to the topology coming from $(1)$. For a general $S in mathcalB(F)$, we must expect $SM^1/2xnotin operatornameIm(M^1/2)$, so the highlighted part doesn't make sense in the stated generality.
    – Daniel Fischer♦
    17 hours ago










  • @DanielFischer Thank you very much for your comment. Sorry, here $SinmathcalB(textIm(M^1/2))$ and thus $SM^1/2xin textIm(M^1/2)$ for all $xin F$.
    – Schüler
    15 hours ago










  • @DanielFischer Is the equality $$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);$$ true only if $textIm(M)$ is dense in $textIm(M^1/2)$ with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1)? Thank you for your help.
    – Schüler
    12 hours ago















The second link shows that $operatornameIm(M)$ is dense in $operatornameIm(M^1/2)$ with respect to the subspace topology induced by $F$, i.e. with respect to $langle,cdot,,,cdot,rangle$. I don't know right away whether it's also dense with respect to the topology coming from $(1)$. For a general $S in mathcalB(F)$, we must expect $SM^1/2xnotin operatornameIm(M^1/2)$, so the highlighted part doesn't make sense in the stated generality.
– Daniel Fischer♦
17 hours ago




The second link shows that $operatornameIm(M)$ is dense in $operatornameIm(M^1/2)$ with respect to the subspace topology induced by $F$, i.e. with respect to $langle,cdot,,,cdot,rangle$. I don't know right away whether it's also dense with respect to the topology coming from $(1)$. For a general $S in mathcalB(F)$, we must expect $SM^1/2xnotin operatornameIm(M^1/2)$, so the highlighted part doesn't make sense in the stated generality.
– Daniel Fischer♦
17 hours ago












@DanielFischer Thank you very much for your comment. Sorry, here $SinmathcalB(textIm(M^1/2))$ and thus $SM^1/2xin textIm(M^1/2)$ for all $xin F$.
– Schüler
15 hours ago




@DanielFischer Thank you very much for your comment. Sorry, here $SinmathcalB(textIm(M^1/2))$ and thus $SM^1/2xin textIm(M^1/2)$ for all $xin F$.
– Schüler
15 hours ago












@DanielFischer Is the equality $$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);$$ true only if $textIm(M)$ is dense in $textIm(M^1/2)$ with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1)? Thank you for your help.
– Schüler
12 hours ago




@DanielFischer Is the equality $$|SM^1/2x|_textIm(M^1/2)=lim_nto infty |SMx_n|_textIm(M^1/2);$$ true only if $textIm(M)$ is dense in $textIm(M^1/2)$ with respect to the topology induced by the inner product on $textIm(M^1/2)$ defined in (1)? Thank you for your help.
– Schüler
12 hours ago















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