Derivative of function expressed in determinant form
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How to find the derivative of this function?
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How to find the derivative of this function?
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– Lord Shark the Unknown
Jul 29 at 10:04
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– Vijoy Kumar
Jul 29 at 10:18
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up vote
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How to find the derivative of this function?
derivatives
How to find the derivative of this function?
derivatives
edited Jul 29 at 10:20


Chinnapparaj R
1,489315
1,489315
asked Jul 29 at 9:51


Vijoy Kumar
4
4
1
What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04
The question image available on clicking the topic please.
– Vijoy Kumar
Jul 29 at 10:18
add a comment |Â
1
What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04
The question image available on clicking the topic please.
– Vijoy Kumar
Jul 29 at 10:18
1
1
What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04
What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04
The question image available on clicking the topic please.
– Vijoy Kumar
Jul 29 at 10:18
The question image available on clicking the topic please.
– Vijoy Kumar
Jul 29 at 10:18
add a comment |Â
2 Answers
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Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.
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0
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If,
$$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$
then,
$$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$
where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.
OR
You can just expand the determinant manually and calculate the derivative.
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.
add a comment |Â
up vote
0
down vote
Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.
Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.
answered Jul 29 at 17:49


Somos
11k1831
11k1831
add a comment |Â
add a comment |Â
up vote
0
down vote
If,
$$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$
then,
$$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$
where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.
OR
You can just expand the determinant manually and calculate the derivative.
add a comment |Â
up vote
0
down vote
If,
$$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$
then,
$$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$
where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.
OR
You can just expand the determinant manually and calculate the derivative.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
If,
$$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$
then,
$$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$
where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.
OR
You can just expand the determinant manually and calculate the derivative.
If,
$$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$
then,
$$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$
where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.
OR
You can just expand the determinant manually and calculate the derivative.
answered Jul 29 at 17:53


prog_SAHIL
773217
773217
add a comment |Â
add a comment |Â
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1
What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04
The question image available on clicking the topic please.
– Vijoy Kumar
Jul 29 at 10:18