Derivative of function expressed in determinant form

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How to find the derivative of this function?







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How to find the derivative of this function?







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  • 1




    What's the question?
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    Jul 29 at 10:04










  • The question image available on clicking the topic please.
    – Vijoy Kumar
    Jul 29 at 10:18












up vote
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up vote
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enter image description here



How to find the derivative of this function?







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enter image description here



How to find the derivative of this function?









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edited Jul 29 at 10:20









Chinnapparaj R

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asked Jul 29 at 9:51









Vijoy Kumar

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  • 1




    What's the question?
    – Lord Shark the Unknown
    Jul 29 at 10:04










  • The question image available on clicking the topic please.
    – Vijoy Kumar
    Jul 29 at 10:18












  • 1




    What's the question?
    – Lord Shark the Unknown
    Jul 29 at 10:04










  • The question image available on clicking the topic please.
    – Vijoy Kumar
    Jul 29 at 10:18







1




1




What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04




What's the question?
– Lord Shark the Unknown
Jul 29 at 10:04












The question image available on clicking the topic please.
– Vijoy Kumar
Jul 29 at 10:18




The question image available on clicking the topic please.
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2 Answers
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Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.






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    If,



    $$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$



    then,



    $$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$



    where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.



    OR



    You can just expand the determinant manually and calculate the derivative.






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      2 Answers
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      2 Answers
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      Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.






      share|cite|improve this answer

























        up vote
        0
        down vote













        Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.






        share|cite|improve this answer























          up vote
          0
          down vote










          up vote
          0
          down vote









          Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.






          share|cite|improve this answer













          Since the determinant of an $ ntimes n $ matrix is a multilinear function of the rows, its derivative is found by using the Leibniz product rule with $ n $ factors. In other words, the derivative of the determinant is the sum of $ n $ determinants where you take the derivative of a different row for each summand.







          share|cite|improve this answer













          share|cite|improve this answer



          share|cite|improve this answer











          answered Jul 29 at 17:49









          Somos

          11k1831




          11k1831




















              up vote
              0
              down vote













              If,



              $$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$



              then,



              $$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$



              where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.



              OR



              You can just expand the determinant manually and calculate the derivative.






              share|cite|improve this answer

























                up vote
                0
                down vote













                If,



                $$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$



                then,



                $$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$



                where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.



                OR



                You can just expand the determinant manually and calculate the derivative.






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  If,



                  $$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$



                  then,



                  $$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$



                  where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.



                  OR



                  You can just expand the determinant manually and calculate the derivative.






                  share|cite|improve this answer













                  If,



                  $$f(x)=|C_1(x) quad C_2(x) quad C_3(x)|$$



                  then,



                  $$f'(x)=|C_1'(x) quad C_2(x) quad C_3(x)|+|C_1(x) quad C_2'(x) quad C_3(x)|+|C_1(x) quad C_2(x) quad C_3'(x)|$$



                  where, $C_1$, $C_2$ and $C_3$ are columns of the determinant. Same can be said for the rows of a determinant.



                  OR



                  You can just expand the determinant manually and calculate the derivative.







                  share|cite|improve this answer













                  share|cite|improve this answer



                  share|cite|improve this answer











                  answered Jul 29 at 17:53









                  prog_SAHIL

                  773217




                  773217






















                       

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