How to prove the following statement? [closed]

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a=b ∨ a=c ∨ b=c = T



I have expanded the LHS as follows. But have no clue how to continue from there



(a=>b)∧(b=>a) ∨ (a=>c)∧(c=>a) ∨ (b=>c)∧(c=>b)



Link for the question [Q (p)].
http://www.cs.utoronto.ca/~hehner/aPToP/solutions/Ex6.pdf



The solution is not understood.







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closed as off-topic by Shailesh, Leucippus, Lord Shark the Unknown, TheGeekGreek, John Ma Jul 29 at 8:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Leucippus, TheGeekGreek
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Could you give more background about the questions? I am not understanding what we are proving and why we are doing so!
    – Aniruddha Deshmukh
    Jul 29 at 3:48










  • @AniruddhaDeshmukh will you follow the link provided. It has similar proof questions like this.
    – Dhananjaya Senanayake
    Jul 29 at 4:04










  • Please, instead of posting links, could you type some words in order to explain what you are talking about? If $a$, $b$ and $c$ represent propositions, what is the meaning of $a = b$? What is T?
    – Taroccoesbrocco
    Jul 29 at 4:11











  • @Taroccoesbrocco, a=b means if and only if, a=>b means if then, and T means binary Truth or 1 .
    – Dhananjaya Senanayake
    Jul 29 at 4:23










  • @DhananjayaSenanayake It does have the proof. But, I am not getting the context. Why is it so? What are $a, b, c$? Kindly clarify!
    – Aniruddha Deshmukh
    Jul 29 at 4:23














up vote
0
down vote

favorite












a=b ∨ a=c ∨ b=c = T



I have expanded the LHS as follows. But have no clue how to continue from there



(a=>b)∧(b=>a) ∨ (a=>c)∧(c=>a) ∨ (b=>c)∧(c=>b)



Link for the question [Q (p)].
http://www.cs.utoronto.ca/~hehner/aPToP/solutions/Ex6.pdf



The solution is not understood.







share|cite|improve this question











closed as off-topic by Shailesh, Leucippus, Lord Shark the Unknown, TheGeekGreek, John Ma Jul 29 at 8:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Leucippus, TheGeekGreek
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Could you give more background about the questions? I am not understanding what we are proving and why we are doing so!
    – Aniruddha Deshmukh
    Jul 29 at 3:48










  • @AniruddhaDeshmukh will you follow the link provided. It has similar proof questions like this.
    – Dhananjaya Senanayake
    Jul 29 at 4:04










  • Please, instead of posting links, could you type some words in order to explain what you are talking about? If $a$, $b$ and $c$ represent propositions, what is the meaning of $a = b$? What is T?
    – Taroccoesbrocco
    Jul 29 at 4:11











  • @Taroccoesbrocco, a=b means if and only if, a=>b means if then, and T means binary Truth or 1 .
    – Dhananjaya Senanayake
    Jul 29 at 4:23










  • @DhananjayaSenanayake It does have the proof. But, I am not getting the context. Why is it so? What are $a, b, c$? Kindly clarify!
    – Aniruddha Deshmukh
    Jul 29 at 4:23












up vote
0
down vote

favorite









up vote
0
down vote

favorite











a=b ∨ a=c ∨ b=c = T



I have expanded the LHS as follows. But have no clue how to continue from there



(a=>b)∧(b=>a) ∨ (a=>c)∧(c=>a) ∨ (b=>c)∧(c=>b)



Link for the question [Q (p)].
http://www.cs.utoronto.ca/~hehner/aPToP/solutions/Ex6.pdf



The solution is not understood.







share|cite|improve this question











a=b ∨ a=c ∨ b=c = T



I have expanded the LHS as follows. But have no clue how to continue from there



(a=>b)∧(b=>a) ∨ (a=>c)∧(c=>a) ∨ (b=>c)∧(c=>b)



Link for the question [Q (p)].
http://www.cs.utoronto.ca/~hehner/aPToP/solutions/Ex6.pdf



The solution is not understood.









share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 29 at 2:47









Dhananjaya Senanayake

6




6




closed as off-topic by Shailesh, Leucippus, Lord Shark the Unknown, TheGeekGreek, John Ma Jul 29 at 8:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Leucippus, TheGeekGreek
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Shailesh, Leucippus, Lord Shark the Unknown, TheGeekGreek, John Ma Jul 29 at 8:44


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Leucippus, TheGeekGreek
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 1




    Could you give more background about the questions? I am not understanding what we are proving and why we are doing so!
    – Aniruddha Deshmukh
    Jul 29 at 3:48










  • @AniruddhaDeshmukh will you follow the link provided. It has similar proof questions like this.
    – Dhananjaya Senanayake
    Jul 29 at 4:04










  • Please, instead of posting links, could you type some words in order to explain what you are talking about? If $a$, $b$ and $c$ represent propositions, what is the meaning of $a = b$? What is T?
    – Taroccoesbrocco
    Jul 29 at 4:11











  • @Taroccoesbrocco, a=b means if and only if, a=>b means if then, and T means binary Truth or 1 .
    – Dhananjaya Senanayake
    Jul 29 at 4:23










  • @DhananjayaSenanayake It does have the proof. But, I am not getting the context. Why is it so? What are $a, b, c$? Kindly clarify!
    – Aniruddha Deshmukh
    Jul 29 at 4:23












  • 1




    Could you give more background about the questions? I am not understanding what we are proving and why we are doing so!
    – Aniruddha Deshmukh
    Jul 29 at 3:48










  • @AniruddhaDeshmukh will you follow the link provided. It has similar proof questions like this.
    – Dhananjaya Senanayake
    Jul 29 at 4:04










  • Please, instead of posting links, could you type some words in order to explain what you are talking about? If $a$, $b$ and $c$ represent propositions, what is the meaning of $a = b$? What is T?
    – Taroccoesbrocco
    Jul 29 at 4:11











  • @Taroccoesbrocco, a=b means if and only if, a=>b means if then, and T means binary Truth or 1 .
    – Dhananjaya Senanayake
    Jul 29 at 4:23










  • @DhananjayaSenanayake It does have the proof. But, I am not getting the context. Why is it so? What are $a, b, c$? Kindly clarify!
    – Aniruddha Deshmukh
    Jul 29 at 4:23







1




1




Could you give more background about the questions? I am not understanding what we are proving and why we are doing so!
– Aniruddha Deshmukh
Jul 29 at 3:48




Could you give more background about the questions? I am not understanding what we are proving and why we are doing so!
– Aniruddha Deshmukh
Jul 29 at 3:48












@AniruddhaDeshmukh will you follow the link provided. It has similar proof questions like this.
– Dhananjaya Senanayake
Jul 29 at 4:04




@AniruddhaDeshmukh will you follow the link provided. It has similar proof questions like this.
– Dhananjaya Senanayake
Jul 29 at 4:04












Please, instead of posting links, could you type some words in order to explain what you are talking about? If $a$, $b$ and $c$ represent propositions, what is the meaning of $a = b$? What is T?
– Taroccoesbrocco
Jul 29 at 4:11





Please, instead of posting links, could you type some words in order to explain what you are talking about? If $a$, $b$ and $c$ represent propositions, what is the meaning of $a = b$? What is T?
– Taroccoesbrocco
Jul 29 at 4:11













@Taroccoesbrocco, a=b means if and only if, a=>b means if then, and T means binary Truth or 1 .
– Dhananjaya Senanayake
Jul 29 at 4:23




@Taroccoesbrocco, a=b means if and only if, a=>b means if then, and T means binary Truth or 1 .
– Dhananjaya Senanayake
Jul 29 at 4:23












@DhananjayaSenanayake It does have the proof. But, I am not getting the context. Why is it so? What are $a, b, c$? Kindly clarify!
– Aniruddha Deshmukh
Jul 29 at 4:23




@DhananjayaSenanayake It does have the proof. But, I am not getting the context. Why is it so? What are $a, b, c$? Kindly clarify!
– Aniruddha Deshmukh
Jul 29 at 4:23










1 Answer
1






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Lets say without loss of generality that $a<=>b$. Then, a and b are both true or both false, which means that $a=>b$ and $b=>a$.






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    Lets say without loss of generality that $a<=>b$. Then, a and b are both true or both false, which means that $a=>b$ and $b=>a$.






    share|cite|improve this answer

























      up vote
      1
      down vote













      Lets say without loss of generality that $a<=>b$. Then, a and b are both true or both false, which means that $a=>b$ and $b=>a$.






      share|cite|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        Lets say without loss of generality that $a<=>b$. Then, a and b are both true or both false, which means that $a=>b$ and $b=>a$.






        share|cite|improve this answer













        Lets say without loss of generality that $a<=>b$. Then, a and b are both true or both false, which means that $a=>b$ and $b=>a$.







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 29 at 6:41









        Eulerrr

        1646




        1646












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