Matrix functions which are not scalar coefficient power series expansions.

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Inspired by this question, I started to wondering (firstly) if there exist any (useful / famous) matrix functions which are not defined as power series expansions with scalar coefficients, but rather matrix coefficients:



$$f(bf A) = sum_k=0^infty bf C_k A^k, bf C_k,Ain M^ntimes n$$



I suppose that it would be more difficult to show that $bf A$ diagonalizable $Rightarrow f(bf A)$ diagonalizable (in the general case) as it obviously is in the special case $forall k: bf C_k=c_kbf I$ (scalar coefficients). Since identity commutes with all matrices.



(Is it even true? (secondly))







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  • I kind of doubt that $A$ diagonalizable implies $f(A)$ diagonalizable unless there were additional constraints on the $C_k$
    – Dark Malthorp
    Jul 31 at 19:07










  • @DarkMalthorp Yes I also very much doubt it, but I am also not sure if many such functions make sense. Most matrix functions I have seen are power series expansions of normal one variable real valued functions which always have scalar coefficients.
    – mathreadler
    Jul 31 at 19:16














up vote
2
down vote

favorite
2












Inspired by this question, I started to wondering (firstly) if there exist any (useful / famous) matrix functions which are not defined as power series expansions with scalar coefficients, but rather matrix coefficients:



$$f(bf A) = sum_k=0^infty bf C_k A^k, bf C_k,Ain M^ntimes n$$



I suppose that it would be more difficult to show that $bf A$ diagonalizable $Rightarrow f(bf A)$ diagonalizable (in the general case) as it obviously is in the special case $forall k: bf C_k=c_kbf I$ (scalar coefficients). Since identity commutes with all matrices.



(Is it even true? (secondly))







share|cite|improve this question





















  • I kind of doubt that $A$ diagonalizable implies $f(A)$ diagonalizable unless there were additional constraints on the $C_k$
    – Dark Malthorp
    Jul 31 at 19:07










  • @DarkMalthorp Yes I also very much doubt it, but I am also not sure if many such functions make sense. Most matrix functions I have seen are power series expansions of normal one variable real valued functions which always have scalar coefficients.
    – mathreadler
    Jul 31 at 19:16












up vote
2
down vote

favorite
2









up vote
2
down vote

favorite
2






2





Inspired by this question, I started to wondering (firstly) if there exist any (useful / famous) matrix functions which are not defined as power series expansions with scalar coefficients, but rather matrix coefficients:



$$f(bf A) = sum_k=0^infty bf C_k A^k, bf C_k,Ain M^ntimes n$$



I suppose that it would be more difficult to show that $bf A$ diagonalizable $Rightarrow f(bf A)$ diagonalizable (in the general case) as it obviously is in the special case $forall k: bf C_k=c_kbf I$ (scalar coefficients). Since identity commutes with all matrices.



(Is it even true? (secondly))







share|cite|improve this question













Inspired by this question, I started to wondering (firstly) if there exist any (useful / famous) matrix functions which are not defined as power series expansions with scalar coefficients, but rather matrix coefficients:



$$f(bf A) = sum_k=0^infty bf C_k A^k, bf C_k,Ain M^ntimes n$$



I suppose that it would be more difficult to show that $bf A$ diagonalizable $Rightarrow f(bf A)$ diagonalizable (in the general case) as it obviously is in the special case $forall k: bf C_k=c_kbf I$ (scalar coefficients). Since identity commutes with all matrices.



(Is it even true? (secondly))









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 31 at 15:52
























asked Jul 31 at 15:45









mathreadler

13.5k71857




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  • I kind of doubt that $A$ diagonalizable implies $f(A)$ diagonalizable unless there were additional constraints on the $C_k$
    – Dark Malthorp
    Jul 31 at 19:07










  • @DarkMalthorp Yes I also very much doubt it, but I am also not sure if many such functions make sense. Most matrix functions I have seen are power series expansions of normal one variable real valued functions which always have scalar coefficients.
    – mathreadler
    Jul 31 at 19:16
















  • I kind of doubt that $A$ diagonalizable implies $f(A)$ diagonalizable unless there were additional constraints on the $C_k$
    – Dark Malthorp
    Jul 31 at 19:07










  • @DarkMalthorp Yes I also very much doubt it, but I am also not sure if many such functions make sense. Most matrix functions I have seen are power series expansions of normal one variable real valued functions which always have scalar coefficients.
    – mathreadler
    Jul 31 at 19:16















I kind of doubt that $A$ diagonalizable implies $f(A)$ diagonalizable unless there were additional constraints on the $C_k$
– Dark Malthorp
Jul 31 at 19:07




I kind of doubt that $A$ diagonalizable implies $f(A)$ diagonalizable unless there were additional constraints on the $C_k$
– Dark Malthorp
Jul 31 at 19:07












@DarkMalthorp Yes I also very much doubt it, but I am also not sure if many such functions make sense. Most matrix functions I have seen are power series expansions of normal one variable real valued functions which always have scalar coefficients.
– mathreadler
Jul 31 at 19:16




@DarkMalthorp Yes I also very much doubt it, but I am also not sure if many such functions make sense. Most matrix functions I have seen are power series expansions of normal one variable real valued functions which always have scalar coefficients.
– mathreadler
Jul 31 at 19:16















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