ODE arising from best constant for Sobolev Embedding [closed]

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I was trying to solve the critical exponent PDE
$$Delta u = u^fracn+2n-2$$
in $mathbbR^n$ and ultimately reduced it to the following ODE $$fracdydr=ce^int_0^ry-y^2-fracyr$$
with the initial condition $y(0)=k in mathbbR$ for any $ngeq 3$. I want to prove existence and uniqueness in $[0,epsilon)$. I tried to do this for the simpler case
$$fracdydr=1-y^2-fracyr$$
but even here I don't know how to deal with the $1/r$. Any hints?







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closed as off-topic by Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel Jul 17 at 0:54


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel
If this question can be reworded to fit the rules in the help center, please edit the question.
















    up vote
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    down vote

    favorite
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    I was trying to solve the critical exponent PDE
    $$Delta u = u^fracn+2n-2$$
    in $mathbbR^n$ and ultimately reduced it to the following ODE $$fracdydr=ce^int_0^ry-y^2-fracyr$$
    with the initial condition $y(0)=k in mathbbR$ for any $ngeq 3$. I want to prove existence and uniqueness in $[0,epsilon)$. I tried to do this for the simpler case
    $$fracdydr=1-y^2-fracyr$$
    but even here I don't know how to deal with the $1/r$. Any hints?







    share|cite|improve this question













    closed as off-topic by Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel Jul 17 at 0:54


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel
    If this question can be reworded to fit the rules in the help center, please edit the question.














      up vote
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      down vote

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      up vote
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      I was trying to solve the critical exponent PDE
      $$Delta u = u^fracn+2n-2$$
      in $mathbbR^n$ and ultimately reduced it to the following ODE $$fracdydr=ce^int_0^ry-y^2-fracyr$$
      with the initial condition $y(0)=k in mathbbR$ for any $ngeq 3$. I want to prove existence and uniqueness in $[0,epsilon)$. I tried to do this for the simpler case
      $$fracdydr=1-y^2-fracyr$$
      but even here I don't know how to deal with the $1/r$. Any hints?







      share|cite|improve this question













      I was trying to solve the critical exponent PDE
      $$Delta u = u^fracn+2n-2$$
      in $mathbbR^n$ and ultimately reduced it to the following ODE $$fracdydr=ce^int_0^ry-y^2-fracyr$$
      with the initial condition $y(0)=k in mathbbR$ for any $ngeq 3$. I want to prove existence and uniqueness in $[0,epsilon)$. I tried to do this for the simpler case
      $$fracdydr=1-y^2-fracyr$$
      but even here I don't know how to deal with the $1/r$. Any hints?









      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited Jul 16 at 12:02
























      asked Jul 16 at 10:59







      user456218











      closed as off-topic by Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel Jul 17 at 0:54


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel
      If this question can be reworded to fit the rules in the help center, please edit the question.




      closed as off-topic by Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel Jul 17 at 0:54


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Alex Francisco, Taroccoesbrocco, Brian Borchers, José Carlos Santos, Parcly Taxel
      If this question can be reworded to fit the rules in the help center, please edit the question.




















          1 Answer
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          Hint.



          Making the variable change



          $$
          y = fracz'zRightarrow r z''+z'-r z = 0
          $$



          which is linear. All this for $r z ne 0$






          share|cite|improve this answer





















          • This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
            – user456218
            Jul 16 at 11:40






          • 1




            @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
            – Cesareo
            Jul 16 at 11:44











          • Okay, but this won't work in the general case :(
            – user456218
            Jul 16 at 11:54
















          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote













          Hint.



          Making the variable change



          $$
          y = fracz'zRightarrow r z''+z'-r z = 0
          $$



          which is linear. All this for $r z ne 0$






          share|cite|improve this answer





















          • This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
            – user456218
            Jul 16 at 11:40






          • 1




            @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
            – Cesareo
            Jul 16 at 11:44











          • Okay, but this won't work in the general case :(
            – user456218
            Jul 16 at 11:54














          up vote
          1
          down vote













          Hint.



          Making the variable change



          $$
          y = fracz'zRightarrow r z''+z'-r z = 0
          $$



          which is linear. All this for $r z ne 0$






          share|cite|improve this answer





















          • This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
            – user456218
            Jul 16 at 11:40






          • 1




            @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
            – Cesareo
            Jul 16 at 11:44











          • Okay, but this won't work in the general case :(
            – user456218
            Jul 16 at 11:54












          up vote
          1
          down vote










          up vote
          1
          down vote









          Hint.



          Making the variable change



          $$
          y = fracz'zRightarrow r z''+z'-r z = 0
          $$



          which is linear. All this for $r z ne 0$






          share|cite|improve this answer













          Hint.



          Making the variable change



          $$
          y = fracz'zRightarrow r z''+z'-r z = 0
          $$



          which is linear. All this for $r z ne 0$







          share|cite|improve this answer













          share|cite|improve this answer



          share|cite|improve this answer











          answered Jul 16 at 11:10









          Cesareo

          5,7922412




          5,7922412











          • This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
            – user456218
            Jul 16 at 11:40






          • 1




            @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
            – Cesareo
            Jul 16 at 11:44











          • Okay, but this won't work in the general case :(
            – user456218
            Jul 16 at 11:54
















          • This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
            – user456218
            Jul 16 at 11:40






          • 1




            @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
            – Cesareo
            Jul 16 at 11:44











          • Okay, but this won't work in the general case :(
            – user456218
            Jul 16 at 11:54















          This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
          – user456218
          Jul 16 at 11:40




          This is the ODE I started with. Can you solve it? Because the 1/r is there as well.
          – user456218
          Jul 16 at 11:40




          1




          1




          @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
          – Cesareo
          Jul 16 at 11:44





          @AdityaKumar The solution is $y(r) = C_1 J_0(i r)+C_2 Y_0(-i r)$ (Bessel functions)
          – Cesareo
          Jul 16 at 11:44













          Okay, but this won't work in the general case :(
          – user456218
          Jul 16 at 11:54




          Okay, but this won't work in the general case :(
          – user456218
          Jul 16 at 11:54


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