Determining whether a relation disrupts freeness of a subgroup

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Suppose we examine a group with presentation $G = langle a, b, c ~vert~ c^2 rangle$. It's my suspicion that the subgroup $langle a, b rangle$ is free, since the relation in the presentation does not "touch" these generators. However, in more complicated scenarios, this may be difficult to determine. For example, if $G= langle a,b,c,d ~vert~ acd^-1b^-1 rangle$, is the subgroup $langle a, b rangle$ free? Again, I suspect yes, though I am not sure how to prove it, if it is even true.



Are there conditions on the relations that can help easily determine whether a subset of generators generates a free subgroup under the relations?







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    en.m.wikipedia.org/wiki/Freiheitssatz
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Suppose we examine a group with presentation $G = langle a, b, c ~vert~ c^2 rangle$. It's my suspicion that the subgroup $langle a, b rangle$ is free, since the relation in the presentation does not "touch" these generators. However, in more complicated scenarios, this may be difficult to determine. For example, if $G= langle a,b,c,d ~vert~ acd^-1b^-1 rangle$, is the subgroup $langle a, b rangle$ free? Again, I suspect yes, though I am not sure how to prove it, if it is even true.



Are there conditions on the relations that can help easily determine whether a subset of generators generates a free subgroup under the relations?







share|cite|improve this question















  • 3




    en.m.wikipedia.org/wiki/Freiheitssatz
    – Steve D
    Jul 18 at 18:30












up vote
1
down vote

favorite









up vote
1
down vote

favorite











Suppose we examine a group with presentation $G = langle a, b, c ~vert~ c^2 rangle$. It's my suspicion that the subgroup $langle a, b rangle$ is free, since the relation in the presentation does not "touch" these generators. However, in more complicated scenarios, this may be difficult to determine. For example, if $G= langle a,b,c,d ~vert~ acd^-1b^-1 rangle$, is the subgroup $langle a, b rangle$ free? Again, I suspect yes, though I am not sure how to prove it, if it is even true.



Are there conditions on the relations that can help easily determine whether a subset of generators generates a free subgroup under the relations?







share|cite|improve this question











Suppose we examine a group with presentation $G = langle a, b, c ~vert~ c^2 rangle$. It's my suspicion that the subgroup $langle a, b rangle$ is free, since the relation in the presentation does not "touch" these generators. However, in more complicated scenarios, this may be difficult to determine. For example, if $G= langle a,b,c,d ~vert~ acd^-1b^-1 rangle$, is the subgroup $langle a, b rangle$ free? Again, I suspect yes, though I am not sure how to prove it, if it is even true.



Are there conditions on the relations that can help easily determine whether a subset of generators generates a free subgroup under the relations?









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asked Jul 18 at 16:54









MightyTyGuy

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  • 3




    en.m.wikipedia.org/wiki/Freiheitssatz
    – Steve D
    Jul 18 at 18:30












  • 3




    en.m.wikipedia.org/wiki/Freiheitssatz
    – Steve D
    Jul 18 at 18:30







3




3




en.m.wikipedia.org/wiki/Freiheitssatz
– Steve D
Jul 18 at 18:30




en.m.wikipedia.org/wiki/Freiheitssatz
– Steve D
Jul 18 at 18:30










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The first example is a free product of the free group on $langle a,b rangle$ and the cyclic group $langle c rangle$ of order $2$.



In the second example, you just eliminate the generator $d$, and see that $G$ is the free group on $a,b,c$.






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    down vote













    The first example is a free product of the free group on $langle a,b rangle$ and the cyclic group $langle c rangle$ of order $2$.



    In the second example, you just eliminate the generator $d$, and see that $G$ is the free group on $a,b,c$.






    share|cite|improve this answer

























      up vote
      3
      down vote













      The first example is a free product of the free group on $langle a,b rangle$ and the cyclic group $langle c rangle$ of order $2$.



      In the second example, you just eliminate the generator $d$, and see that $G$ is the free group on $a,b,c$.






      share|cite|improve this answer























        up vote
        3
        down vote










        up vote
        3
        down vote









        The first example is a free product of the free group on $langle a,b rangle$ and the cyclic group $langle c rangle$ of order $2$.



        In the second example, you just eliminate the generator $d$, and see that $G$ is the free group on $a,b,c$.






        share|cite|improve this answer













        The first example is a free product of the free group on $langle a,b rangle$ and the cyclic group $langle c rangle$ of order $2$.



        In the second example, you just eliminate the generator $d$, and see that $G$ is the free group on $a,b,c$.







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 18 at 16:59









        Derek Holt

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