Why Bousfield localization preserves homotopy pull-backs?
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Studying chromatic homotopy theory I encountered the chromatic fracture square
$requireAMScd$
beginCD
L_K(n) vee K(m)X @>>> L_K(m)X\
@V V V @VV V\
L_K(n)X @>>> L_K(n)L_K(m)X
endCD
for $n<m$. Then I was told that applying a Bousfield localization functor we preserve the homotopy pull-back, this is useful since applying $L_K(t)$ for $n <t<m$ we get the equality $L_K(t)L_K(n)vee K(m)X= L_K(t)L_K(m)X $
since the lower terms become zero.
I would like to know a proof of this claim. Also a reference for this fact is well accepted.
Thank you for any help.
stable-homotopy-theory pullback
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up vote
0
down vote
favorite
Studying chromatic homotopy theory I encountered the chromatic fracture square
$requireAMScd$
beginCD
L_K(n) vee K(m)X @>>> L_K(m)X\
@V V V @VV V\
L_K(n)X @>>> L_K(n)L_K(m)X
endCD
for $n<m$. Then I was told that applying a Bousfield localization functor we preserve the homotopy pull-back, this is useful since applying $L_K(t)$ for $n <t<m$ we get the equality $L_K(t)L_K(n)vee K(m)X= L_K(t)L_K(m)X $
since the lower terms become zero.
I would like to know a proof of this claim. Also a reference for this fact is well accepted.
Thank you for any help.
stable-homotopy-theory pullback
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Studying chromatic homotopy theory I encountered the chromatic fracture square
$requireAMScd$
beginCD
L_K(n) vee K(m)X @>>> L_K(m)X\
@V V V @VV V\
L_K(n)X @>>> L_K(n)L_K(m)X
endCD
for $n<m$. Then I was told that applying a Bousfield localization functor we preserve the homotopy pull-back, this is useful since applying $L_K(t)$ for $n <t<m$ we get the equality $L_K(t)L_K(n)vee K(m)X= L_K(t)L_K(m)X $
since the lower terms become zero.
I would like to know a proof of this claim. Also a reference for this fact is well accepted.
Thank you for any help.
stable-homotopy-theory pullback
Studying chromatic homotopy theory I encountered the chromatic fracture square
$requireAMScd$
beginCD
L_K(n) vee K(m)X @>>> L_K(m)X\
@V V V @VV V\
L_K(n)X @>>> L_K(n)L_K(m)X
endCD
for $n<m$. Then I was told that applying a Bousfield localization functor we preserve the homotopy pull-back, this is useful since applying $L_K(t)$ for $n <t<m$ we get the equality $L_K(t)L_K(n)vee K(m)X= L_K(t)L_K(m)X $
since the lower terms become zero.
I would like to know a proof of this claim. Also a reference for this fact is well accepted.
Thank you for any help.
stable-homotopy-theory pullback
edited Jul 20 at 8:07
asked Jul 18 at 17:13
N.B.
433212
433212
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1 Answer
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I just need to observe that the Bousfield localization, being a left adjoint, preserves homotopy colimits. Now by stability of the stable homotopy category homotopy pull-backs and pushouts coincide.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
I just need to observe that the Bousfield localization, being a left adjoint, preserves homotopy colimits. Now by stability of the stable homotopy category homotopy pull-backs and pushouts coincide.
add a comment |Â
up vote
0
down vote
I just need to observe that the Bousfield localization, being a left adjoint, preserves homotopy colimits. Now by stability of the stable homotopy category homotopy pull-backs and pushouts coincide.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
I just need to observe that the Bousfield localization, being a left adjoint, preserves homotopy colimits. Now by stability of the stable homotopy category homotopy pull-backs and pushouts coincide.
I just need to observe that the Bousfield localization, being a left adjoint, preserves homotopy colimits. Now by stability of the stable homotopy category homotopy pull-backs and pushouts coincide.
answered Jul 20 at 12:46
N.B.
433212
433212
add a comment |Â
add a comment |Â
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