Equivalent forms Optimization

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We were told to assume in class that the below optimization formulations are equivalent-



$$min_wmax_delta:||(X+delta)w-y||_2^2$$



$$min_w||Xw-y||_2^2+lambda||w||_2^2 $$



for appropriately chosen $lambda$.



$X,deltain R^mtimes n,~win R^ntimes1,~yin R^mtimes1$



Can someone please explain why this is true? A reference paper pointing this out would also be appreciated.







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  • What does $|delta|_2$ mean when $delta$ is a matrix?
    – angryavian
    Jul 24 at 4:04






  • 4




    proceedings.mlr.press/v28/yang13e.pdf
    – LinAlg
    Jul 24 at 13:59






  • 1




    There's a perfectly standard defenition of the 2-norm of a matrix that isn't the Frobenius norm. Wny not write $| delta |_F$, since that's what you mean?
    – Brian Borchers
    Jul 24 at 15:23






  • 1




    @MichaelGrant Thanks, I am familiar with both definitions. I was just trying to get OP to clarify, since I have seen some people use $|cdot|_2$ to refer to Frobenius norm, while [most] others use it to refer to operator norm.
    – angryavian
    Jul 27 at 17:05






  • 1




    Fair enough. I consider the Frobenius interpretation incorrect. Let’s fight the good fight!
    – Michael Grant
    Jul 27 at 17:06














up vote
4
down vote

favorite
3












We were told to assume in class that the below optimization formulations are equivalent-



$$min_wmax_delta:||(X+delta)w-y||_2^2$$



$$min_w||Xw-y||_2^2+lambda||w||_2^2 $$



for appropriately chosen $lambda$.



$X,deltain R^mtimes n,~win R^ntimes1,~yin R^mtimes1$



Can someone please explain why this is true? A reference paper pointing this out would also be appreciated.







share|cite|improve this question





















  • What does $|delta|_2$ mean when $delta$ is a matrix?
    – angryavian
    Jul 24 at 4:04






  • 4




    proceedings.mlr.press/v28/yang13e.pdf
    – LinAlg
    Jul 24 at 13:59






  • 1




    There's a perfectly standard defenition of the 2-norm of a matrix that isn't the Frobenius norm. Wny not write $| delta |_F$, since that's what you mean?
    – Brian Borchers
    Jul 24 at 15:23






  • 1




    @MichaelGrant Thanks, I am familiar with both definitions. I was just trying to get OP to clarify, since I have seen some people use $|cdot|_2$ to refer to Frobenius norm, while [most] others use it to refer to operator norm.
    – angryavian
    Jul 27 at 17:05






  • 1




    Fair enough. I consider the Frobenius interpretation incorrect. Let’s fight the good fight!
    – Michael Grant
    Jul 27 at 17:06












up vote
4
down vote

favorite
3









up vote
4
down vote

favorite
3






3





We were told to assume in class that the below optimization formulations are equivalent-



$$min_wmax_delta:||(X+delta)w-y||_2^2$$



$$min_w||Xw-y||_2^2+lambda||w||_2^2 $$



for appropriately chosen $lambda$.



$X,deltain R^mtimes n,~win R^ntimes1,~yin R^mtimes1$



Can someone please explain why this is true? A reference paper pointing this out would also be appreciated.







share|cite|improve this question













We were told to assume in class that the below optimization formulations are equivalent-



$$min_wmax_delta:||(X+delta)w-y||_2^2$$



$$min_w||Xw-y||_2^2+lambda||w||_2^2 $$



for appropriately chosen $lambda$.



$X,deltain R^mtimes n,~win R^ntimes1,~yin R^mtimes1$



Can someone please explain why this is true? A reference paper pointing this out would also be appreciated.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 27 at 14:11









Michael Grant

14.6k11743




14.6k11743









asked Jul 24 at 3:38









Amrit Prasad

727




727











  • What does $|delta|_2$ mean when $delta$ is a matrix?
    – angryavian
    Jul 24 at 4:04






  • 4




    proceedings.mlr.press/v28/yang13e.pdf
    – LinAlg
    Jul 24 at 13:59






  • 1




    There's a perfectly standard defenition of the 2-norm of a matrix that isn't the Frobenius norm. Wny not write $| delta |_F$, since that's what you mean?
    – Brian Borchers
    Jul 24 at 15:23






  • 1




    @MichaelGrant Thanks, I am familiar with both definitions. I was just trying to get OP to clarify, since I have seen some people use $|cdot|_2$ to refer to Frobenius norm, while [most] others use it to refer to operator norm.
    – angryavian
    Jul 27 at 17:05






  • 1




    Fair enough. I consider the Frobenius interpretation incorrect. Let’s fight the good fight!
    – Michael Grant
    Jul 27 at 17:06
















  • What does $|delta|_2$ mean when $delta$ is a matrix?
    – angryavian
    Jul 24 at 4:04






  • 4




    proceedings.mlr.press/v28/yang13e.pdf
    – LinAlg
    Jul 24 at 13:59






  • 1




    There's a perfectly standard defenition of the 2-norm of a matrix that isn't the Frobenius norm. Wny not write $| delta |_F$, since that's what you mean?
    – Brian Borchers
    Jul 24 at 15:23






  • 1




    @MichaelGrant Thanks, I am familiar with both definitions. I was just trying to get OP to clarify, since I have seen some people use $|cdot|_2$ to refer to Frobenius norm, while [most] others use it to refer to operator norm.
    – angryavian
    Jul 27 at 17:05






  • 1




    Fair enough. I consider the Frobenius interpretation incorrect. Let’s fight the good fight!
    – Michael Grant
    Jul 27 at 17:06















What does $|delta|_2$ mean when $delta$ is a matrix?
– angryavian
Jul 24 at 4:04




What does $|delta|_2$ mean when $delta$ is a matrix?
– angryavian
Jul 24 at 4:04




4




4




proceedings.mlr.press/v28/yang13e.pdf
– LinAlg
Jul 24 at 13:59




proceedings.mlr.press/v28/yang13e.pdf
– LinAlg
Jul 24 at 13:59




1




1




There's a perfectly standard defenition of the 2-norm of a matrix that isn't the Frobenius norm. Wny not write $| delta |_F$, since that's what you mean?
– Brian Borchers
Jul 24 at 15:23




There's a perfectly standard defenition of the 2-norm of a matrix that isn't the Frobenius norm. Wny not write $| delta |_F$, since that's what you mean?
– Brian Borchers
Jul 24 at 15:23




1




1




@MichaelGrant Thanks, I am familiar with both definitions. I was just trying to get OP to clarify, since I have seen some people use $|cdot|_2$ to refer to Frobenius norm, while [most] others use it to refer to operator norm.
– angryavian
Jul 27 at 17:05




@MichaelGrant Thanks, I am familiar with both definitions. I was just trying to get OP to clarify, since I have seen some people use $|cdot|_2$ to refer to Frobenius norm, while [most] others use it to refer to operator norm.
– angryavian
Jul 27 at 17:05




1




1




Fair enough. I consider the Frobenius interpretation incorrect. Let’s fight the good fight!
– Michael Grant
Jul 27 at 17:06




Fair enough. I consider the Frobenius interpretation incorrect. Let’s fight the good fight!
– Michael Grant
Jul 27 at 17:06















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