Finding the argument of a complex fraction (doing something wrong but not knowing what)

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I am working on a problem, and I think that I miss something very simple but I do not get what I am doing wrong.




The problem:




I need to find the argument of the following function (all the variables are real and greater or equal to zero and I work in radians):



$$argleft(frac1texta_1cdotleft(omegatextjright)^3+texta_2cdotleft(omegatextjright)^2+texta_3cdotleft(omegatextjright)+1right)=$$
$$argleft(frac1-texta_1cdotomega^3cdottextj-texta_2cdotomega^2+texta_3cdotomegacdottextj+1right)=$$
$$argleft(frac11-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag1$$



Where $textj^2=i^2=-1$



Using the rules for the agument we can write:



$$argleft(1right)-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$0-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag2$$



Setting $argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright):=varphileft(omegaright)$.




My work:




I got the following function for the argument:



$$
varphileft(omegaright)=begincases
-arctanleft(fractexta_3omega-texta_1omega^31-texta_2omega^2right)spacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(pi+arctanleft(left|fractexta_3omega-texta_1omega^31-texta_2omega^2right|right)right)spacespacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3\
\
-left(fracpi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(frac3pi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3
endcasestag3
$$



But it does not match with the function I got using software, so I'm somewhere wrong in $left(3right)$. And I do not find where







share|cite|improve this question





















  • What happened to $a_3$ in your final result?
    – Jens
    Jul 19 at 18:27










  • Is it $a_2omega$ or $a_2 omega^2$?
    – Jens
    Jul 19 at 18:35










  • @Jens In the final answer I got it right, but not in my problem statement. Now it is correct (thank for your help already!).
    – Jan
    Jul 19 at 18:37










  • Have you tried the standard way of defining Atan2?
    – Jens
    Jul 19 at 19:01










  • @Jens That is the thing I used.
    – Jan
    Jul 19 at 19:08














up vote
0
down vote

favorite
1












I am working on a problem, and I think that I miss something very simple but I do not get what I am doing wrong.




The problem:




I need to find the argument of the following function (all the variables are real and greater or equal to zero and I work in radians):



$$argleft(frac1texta_1cdotleft(omegatextjright)^3+texta_2cdotleft(omegatextjright)^2+texta_3cdotleft(omegatextjright)+1right)=$$
$$argleft(frac1-texta_1cdotomega^3cdottextj-texta_2cdotomega^2+texta_3cdotomegacdottextj+1right)=$$
$$argleft(frac11-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag1$$



Where $textj^2=i^2=-1$



Using the rules for the agument we can write:



$$argleft(1right)-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$0-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag2$$



Setting $argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright):=varphileft(omegaright)$.




My work:




I got the following function for the argument:



$$
varphileft(omegaright)=begincases
-arctanleft(fractexta_3omega-texta_1omega^31-texta_2omega^2right)spacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(pi+arctanleft(left|fractexta_3omega-texta_1omega^31-texta_2omega^2right|right)right)spacespacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3\
\
-left(fracpi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(frac3pi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3
endcasestag3
$$



But it does not match with the function I got using software, so I'm somewhere wrong in $left(3right)$. And I do not find where







share|cite|improve this question





















  • What happened to $a_3$ in your final result?
    – Jens
    Jul 19 at 18:27










  • Is it $a_2omega$ or $a_2 omega^2$?
    – Jens
    Jul 19 at 18:35










  • @Jens In the final answer I got it right, but not in my problem statement. Now it is correct (thank for your help already!).
    – Jan
    Jul 19 at 18:37










  • Have you tried the standard way of defining Atan2?
    – Jens
    Jul 19 at 19:01










  • @Jens That is the thing I used.
    – Jan
    Jul 19 at 19:08












up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





I am working on a problem, and I think that I miss something very simple but I do not get what I am doing wrong.




The problem:




I need to find the argument of the following function (all the variables are real and greater or equal to zero and I work in radians):



$$argleft(frac1texta_1cdotleft(omegatextjright)^3+texta_2cdotleft(omegatextjright)^2+texta_3cdotleft(omegatextjright)+1right)=$$
$$argleft(frac1-texta_1cdotomega^3cdottextj-texta_2cdotomega^2+texta_3cdotomegacdottextj+1right)=$$
$$argleft(frac11-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag1$$



Where $textj^2=i^2=-1$



Using the rules for the agument we can write:



$$argleft(1right)-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$0-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag2$$



Setting $argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright):=varphileft(omegaright)$.




My work:




I got the following function for the argument:



$$
varphileft(omegaright)=begincases
-arctanleft(fractexta_3omega-texta_1omega^31-texta_2omega^2right)spacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(pi+arctanleft(left|fractexta_3omega-texta_1omega^31-texta_2omega^2right|right)right)spacespacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3\
\
-left(fracpi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(frac3pi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3
endcasestag3
$$



But it does not match with the function I got using software, so I'm somewhere wrong in $left(3right)$. And I do not find where







share|cite|improve this question













I am working on a problem, and I think that I miss something very simple but I do not get what I am doing wrong.




The problem:




I need to find the argument of the following function (all the variables are real and greater or equal to zero and I work in radians):



$$argleft(frac1texta_1cdotleft(omegatextjright)^3+texta_2cdotleft(omegatextjright)^2+texta_3cdotleft(omegatextjright)+1right)=$$
$$argleft(frac1-texta_1cdotomega^3cdottextj-texta_2cdotomega^2+texta_3cdotomegacdottextj+1right)=$$
$$argleft(frac11-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag1$$



Where $textj^2=i^2=-1$



Using the rules for the agument we can write:



$$argleft(1right)-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$0-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)=$$
$$-argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright)tag2$$



Setting $argleft(1-texta_2cdotomega^2+left(texta_3cdotomega-texta_1cdotomega^3right)cdottextjright):=varphileft(omegaright)$.




My work:




I got the following function for the argument:



$$
varphileft(omegaright)=begincases
-arctanleft(fractexta_3omega-texta_1omega^31-texta_2omega^2right)spacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(pi+arctanleft(left|fractexta_3omega-texta_1omega^31-texta_2omega^2right|right)right)spacespacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3\
\
-left(fracpi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacespacetextwhen:spacespace1<texta_2omega^2spacewedgespacetexta_3omega>texta_1omega^3\
\
-left(frac3pi2+arctanleft(left|frac1-texta_2omega^2texta_3omega-texta_1omega^3right|right)right)spacespacespacetextwhen:spacespace1>texta_2omega^2spacewedgespacetexta_3omega<texta_1omega^3
endcasestag3
$$



But it does not match with the function I got using software, so I'm somewhere wrong in $left(3right)$. And I do not find where









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 19 at 18:36
























asked Jul 19 at 18:15









Jan

21.6k31239




21.6k31239











  • What happened to $a_3$ in your final result?
    – Jens
    Jul 19 at 18:27










  • Is it $a_2omega$ or $a_2 omega^2$?
    – Jens
    Jul 19 at 18:35










  • @Jens In the final answer I got it right, but not in my problem statement. Now it is correct (thank for your help already!).
    – Jan
    Jul 19 at 18:37










  • Have you tried the standard way of defining Atan2?
    – Jens
    Jul 19 at 19:01










  • @Jens That is the thing I used.
    – Jan
    Jul 19 at 19:08
















  • What happened to $a_3$ in your final result?
    – Jens
    Jul 19 at 18:27










  • Is it $a_2omega$ or $a_2 omega^2$?
    – Jens
    Jul 19 at 18:35










  • @Jens In the final answer I got it right, but not in my problem statement. Now it is correct (thank for your help already!).
    – Jan
    Jul 19 at 18:37










  • Have you tried the standard way of defining Atan2?
    – Jens
    Jul 19 at 19:01










  • @Jens That is the thing I used.
    – Jan
    Jul 19 at 19:08















What happened to $a_3$ in your final result?
– Jens
Jul 19 at 18:27




What happened to $a_3$ in your final result?
– Jens
Jul 19 at 18:27












Is it $a_2omega$ or $a_2 omega^2$?
– Jens
Jul 19 at 18:35




Is it $a_2omega$ or $a_2 omega^2$?
– Jens
Jul 19 at 18:35












@Jens In the final answer I got it right, but not in my problem statement. Now it is correct (thank for your help already!).
– Jan
Jul 19 at 18:37




@Jens In the final answer I got it right, but not in my problem statement. Now it is correct (thank for your help already!).
– Jan
Jul 19 at 18:37












Have you tried the standard way of defining Atan2?
– Jens
Jul 19 at 19:01




Have you tried the standard way of defining Atan2?
– Jens
Jul 19 at 19:01












@Jens That is the thing I used.
– Jan
Jul 19 at 19:08




@Jens That is the thing I used.
– Jan
Jul 19 at 19:08















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