Given two surface equation, convert to polar coordinates and find the volume of the solid using triple integral
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Consider the surfaces given by
$$
M:(x^2+z^2-z)^2=(x^2+z^2)
$$
$$
N:y^2=x^2+z^2
$$
(a) Notice that since there is no y present in M the shape of the surface is a cylinder determined by its shape in the xz-plane! Convert M to polar coordinates and sketch the surface. What’s the name of the type of curve that determines its shape? Note: You may assume r not euqal 0.
(b) Sketch the solid bounded by M, N and the xz-plane.
(c) Find the volume of the solid by setting up an appropriate triple integral and computing.
Hint: Polar! Also, some functions are odd.
a) I got $$r=0$$ and $$r=1+sin theta $$
and i know the shape of r=1+sin theta is a cardioid
b) I know N is a elliptical cone, but I dont know how to sketch them on a graph, and I have no idea how the solid would look like.
I am stuck afterward...
calculus integration polar-coordinates volume
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up vote
0
down vote
favorite
Consider the surfaces given by
$$
M:(x^2+z^2-z)^2=(x^2+z^2)
$$
$$
N:y^2=x^2+z^2
$$
(a) Notice that since there is no y present in M the shape of the surface is a cylinder determined by its shape in the xz-plane! Convert M to polar coordinates and sketch the surface. What’s the name of the type of curve that determines its shape? Note: You may assume r not euqal 0.
(b) Sketch the solid bounded by M, N and the xz-plane.
(c) Find the volume of the solid by setting up an appropriate triple integral and computing.
Hint: Polar! Also, some functions are odd.
a) I got $$r=0$$ and $$r=1+sin theta $$
and i know the shape of r=1+sin theta is a cardioid
b) I know N is a elliptical cone, but I dont know how to sketch them on a graph, and I have no idea how the solid would look like.
I am stuck afterward...
calculus integration polar-coordinates volume
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Consider the surfaces given by
$$
M:(x^2+z^2-z)^2=(x^2+z^2)
$$
$$
N:y^2=x^2+z^2
$$
(a) Notice that since there is no y present in M the shape of the surface is a cylinder determined by its shape in the xz-plane! Convert M to polar coordinates and sketch the surface. What’s the name of the type of curve that determines its shape? Note: You may assume r not euqal 0.
(b) Sketch the solid bounded by M, N and the xz-plane.
(c) Find the volume of the solid by setting up an appropriate triple integral and computing.
Hint: Polar! Also, some functions are odd.
a) I got $$r=0$$ and $$r=1+sin theta $$
and i know the shape of r=1+sin theta is a cardioid
b) I know N is a elliptical cone, but I dont know how to sketch them on a graph, and I have no idea how the solid would look like.
I am stuck afterward...
calculus integration polar-coordinates volume
Consider the surfaces given by
$$
M:(x^2+z^2-z)^2=(x^2+z^2)
$$
$$
N:y^2=x^2+z^2
$$
(a) Notice that since there is no y present in M the shape of the surface is a cylinder determined by its shape in the xz-plane! Convert M to polar coordinates and sketch the surface. What’s the name of the type of curve that determines its shape? Note: You may assume r not euqal 0.
(b) Sketch the solid bounded by M, N and the xz-plane.
(c) Find the volume of the solid by setting up an appropriate triple integral and computing.
Hint: Polar! Also, some functions are odd.
a) I got $$r=0$$ and $$r=1+sin theta $$
and i know the shape of r=1+sin theta is a cardioid
b) I know N is a elliptical cone, but I dont know how to sketch them on a graph, and I have no idea how the solid would look like.
I am stuck afterward...
calculus integration polar-coordinates volume
asked Jul 24 at 5:14
gummug
1
1
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1 Answer
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$x = rcostheta\
z = rsin theta\
y= y$
Jacobain
$dx dy dz = r dy dr dtheta$
Regarding $M,$ as you say $r = 1 + sin theta$ which is a cartiod cylinder.
$N$ is a double cone (not elliptical)
$y^2 = r^2\
y = pm r$
$V = int_0^2piint_0^1-sinthetaint_-r^r r dy dr dtheta$
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
$x = rcostheta\
z = rsin theta\
y= y$
Jacobain
$dx dy dz = r dy dr dtheta$
Regarding $M,$ as you say $r = 1 + sin theta$ which is a cartiod cylinder.
$N$ is a double cone (not elliptical)
$y^2 = r^2\
y = pm r$
$V = int_0^2piint_0^1-sinthetaint_-r^r r dy dr dtheta$
add a comment |Â
up vote
1
down vote
$x = rcostheta\
z = rsin theta\
y= y$
Jacobain
$dx dy dz = r dy dr dtheta$
Regarding $M,$ as you say $r = 1 + sin theta$ which is a cartiod cylinder.
$N$ is a double cone (not elliptical)
$y^2 = r^2\
y = pm r$
$V = int_0^2piint_0^1-sinthetaint_-r^r r dy dr dtheta$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
$x = rcostheta\
z = rsin theta\
y= y$
Jacobain
$dx dy dz = r dy dr dtheta$
Regarding $M,$ as you say $r = 1 + sin theta$ which is a cartiod cylinder.
$N$ is a double cone (not elliptical)
$y^2 = r^2\
y = pm r$
$V = int_0^2piint_0^1-sinthetaint_-r^r r dy dr dtheta$
$x = rcostheta\
z = rsin theta\
y= y$
Jacobain
$dx dy dz = r dy dr dtheta$
Regarding $M,$ as you say $r = 1 + sin theta$ which is a cartiod cylinder.
$N$ is a double cone (not elliptical)
$y^2 = r^2\
y = pm r$
$V = int_0^2piint_0^1-sinthetaint_-r^r r dy dr dtheta$
answered Jul 24 at 5:31
Doug M
39.1k31749
39.1k31749
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