How do I get the arc of the circumference in the exercise?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
0
down vote

favorite












I have this exercise:
enter image description here



So my development was:



Draw a line $OB$, that measures $r$ = radius.



The line $OD$ also measures $r$



If the arc $BC = 100$, so the arc $BW = 80$



Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$



Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.



In a picture:



enter image description here



But according to the guide the result must be $40$, ¿What is wrong with my development?







share|cite|improve this question





















  • I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
    – John Wayland Bales
    Jul 28 at 21:39










  • By the way, WBD= 80 is not correct.
    – Seyed
    Jul 28 at 21:50











  • @Seyed, was $angleOBD$, edited.
    – Mattiu
    Jul 28 at 23:23










  • That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
    – marty cohen
    Jul 28 at 23:51










  • Yes it looks, but i need know why my answer is wrong
    – Mattiu
    Jul 29 at 1:19














up vote
0
down vote

favorite












I have this exercise:
enter image description here



So my development was:



Draw a line $OB$, that measures $r$ = radius.



The line $OD$ also measures $r$



If the arc $BC = 100$, so the arc $BW = 80$



Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$



Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.



In a picture:



enter image description here



But according to the guide the result must be $40$, ¿What is wrong with my development?







share|cite|improve this question





















  • I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
    – John Wayland Bales
    Jul 28 at 21:39










  • By the way, WBD= 80 is not correct.
    – Seyed
    Jul 28 at 21:50











  • @Seyed, was $angleOBD$, edited.
    – Mattiu
    Jul 28 at 23:23










  • That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
    – marty cohen
    Jul 28 at 23:51










  • Yes it looks, but i need know why my answer is wrong
    – Mattiu
    Jul 29 at 1:19












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have this exercise:
enter image description here



So my development was:



Draw a line $OB$, that measures $r$ = radius.



The line $OD$ also measures $r$



If the arc $BC = 100$, so the arc $BW = 80$



Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$



Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.



In a picture:



enter image description here



But according to the guide the result must be $40$, ¿What is wrong with my development?







share|cite|improve this question













I have this exercise:
enter image description here



So my development was:



Draw a line $OB$, that measures $r$ = radius.



The line $OD$ also measures $r$



If the arc $BC = 100$, so the arc $BW = 80$



Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$



Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.



In a picture:



enter image description here



But according to the guide the result must be $40$, ¿What is wrong with my development?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 28 at 23:22
























asked Jul 28 at 21:26









Mattiu

759316




759316











  • I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
    – John Wayland Bales
    Jul 28 at 21:39










  • By the way, WBD= 80 is not correct.
    – Seyed
    Jul 28 at 21:50











  • @Seyed, was $angleOBD$, edited.
    – Mattiu
    Jul 28 at 23:23










  • That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
    – marty cohen
    Jul 28 at 23:51










  • Yes it looks, but i need know why my answer is wrong
    – Mattiu
    Jul 29 at 1:19
















  • I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
    – John Wayland Bales
    Jul 28 at 21:39










  • By the way, WBD= 80 is not correct.
    – Seyed
    Jul 28 at 21:50











  • @Seyed, was $angleOBD$, edited.
    – Mattiu
    Jul 28 at 23:23










  • That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
    – marty cohen
    Jul 28 at 23:51










  • Yes it looks, but i need know why my answer is wrong
    – Mattiu
    Jul 29 at 1:19















I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39




I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39












By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50





By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50













@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23




@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23












That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51




That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51












Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19




Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19















active

oldest

votes











Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2865583%2fhow-do-i-get-the-arc-of-the-circumference-in-the-exercise%23new-answer', 'question_page');

);

Post as a guest



































active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes










 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2865583%2fhow-do-i-get-the-arc-of-the-circumference-in-the-exercise%23new-answer', 'question_page');

);

Post as a guest













































































Comments

Popular posts from this blog

What is the equation of a 3D cone with generalised tilt?

Color the edges and diagonals of a regular polygon

Relationship between determinant of matrix and determinant of adjoint?