How do I get the arc of the circumference in the exercise?
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I have this exercise:
So my development was:
Draw a line $OB$, that measures $r$ = radius.
The line $OD$ also measures $r$
If the arc $BC = 100$, so the arc $BW = 80$
Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$
Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.
In a picture:
But according to the guide the result must be $40$, ¿What is wrong with my development?
geometry
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up vote
0
down vote
favorite
I have this exercise:
So my development was:
Draw a line $OB$, that measures $r$ = radius.
The line $OD$ also measures $r$
If the arc $BC = 100$, so the arc $BW = 80$
Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$
Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.
In a picture:
But according to the guide the result must be $40$, ¿What is wrong with my development?
geometry
I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39
By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50
@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23
That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51
Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have this exercise:
So my development was:
Draw a line $OB$, that measures $r$ = radius.
The line $OD$ also measures $r$
If the arc $BC = 100$, so the arc $BW = 80$
Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$
Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.
In a picture:
But according to the guide the result must be $40$, ¿What is wrong with my development?
geometry
I have this exercise:
So my development was:
Draw a line $OB$, that measures $r$ = radius.
The line $OD$ also measures $r$
If the arc $BC = 100$, so the arc $BW = 80$
Then, the triangle $ODB$ is isosceles of $BD$ base and sides of $r$
Since, the arc $BW = 80$ and $angleBDW$ is the center angle, so $angleBDO = 80$, besides the triangle $ODB$ is isosceles, then $angleOBD = 80$, so the center angle $angleDOB = 20$, therefore the arc $BD = 20$.
In a picture:
But according to the guide the result must be $40$, ¿What is wrong with my development?
geometry
edited Jul 28 at 23:22
asked Jul 28 at 21:26
Mattiu
759316
759316
I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39
By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50
@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23
That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51
Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19
add a comment |Â
I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39
By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50
@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23
That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51
Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19
I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39
I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39
By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50
By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50
@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23
@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23
That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51
That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51
Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19
Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19
add a comment |Â
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I see nothing wrong with your argument. It is probably just an error or misprint in the guide.
– John Wayland Bales
Jul 28 at 21:39
By the way, WBD= 80 is not correct.
– Seyed
Jul 28 at 21:50
@Seyed, was $angleOBD$, edited.
– Mattiu
Jul 28 at 23:23
That is a very badly drawn picture. It looks like the center of arc BD is W, not O.
– marty cohen
Jul 28 at 23:51
Yes it looks, but i need know why my answer is wrong
– Mattiu
Jul 29 at 1:19