Irreducible representations of $operatornameGL_n(mathbbC)$

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I just started to learn representation theory and I'm interested in the irreducible representations of $operatornameGL_n(mathbbC)$. I looked them up in three different books and apparently, I misunderstood something because for me, they are inconsistent statements.




Stanley (Enumerative Combinatorics II, Theorem A2.4):
The irreducible polynomial representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ can be indexed by partitions
$lambda$ of length at most $n$.



Bump (Lie Groups, Theorem 38.3):
The irreducible algebraic representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ are indexed by integer sequences
$lambda_1geqlambda_2geqdotsgeqlambda_n$.



Fulton, Harris (Representation Theory, Proposition 15.47):
Every irreducible complex representation of $operatornameGL_n(mathbbC)$ is isomorphic to $varphi^lambda$
for a unique index $lambda=lambda_1,dots,lambda_n$ with
$lambda_1geqlambda_2geqdotsgeqlambda_n$.




My questions are:



  1. Is every algebraic irreducible representation indexed by a partition or by an integer sequence with $lambda_1geqlambda_2geqdotsgeqlambda_n$?

  2. Can every irreducible representation be indexed by an integer partition with $lambda_1geqlambda_2geqdotsgeqlambda_n$ or only the irreducible alegbraic representations?






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  • What values do Fulton-Harris allow for the $lambda_i$?
    – Tobias Kildetoft
    Jul 24 at 7:29










  • I just looked up the result in Stanley, and you misquoted it slightly. It should be "polynomial" instead of "algebraic".
    – Tobias Kildetoft
    Jul 24 at 7:34










  • @TobiasKildetoft It says that some of the $lambda_i$ can be negative. So, they're integers.
    – user160919
    Jul 24 at 7:35











  • @TobiasKildetoft That's true. But aren't polynomial and algebraic representations not the same thing?
    – user160919
    Jul 24 at 7:36






  • 3




    No, being polynomial is stronger than being algebraic, and here it precisely amounts to whether one allows negative powers of the determinant to appear.
    – Tobias Kildetoft
    Jul 24 at 7:45














up vote
0
down vote

favorite












I just started to learn representation theory and I'm interested in the irreducible representations of $operatornameGL_n(mathbbC)$. I looked them up in three different books and apparently, I misunderstood something because for me, they are inconsistent statements.




Stanley (Enumerative Combinatorics II, Theorem A2.4):
The irreducible polynomial representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ can be indexed by partitions
$lambda$ of length at most $n$.



Bump (Lie Groups, Theorem 38.3):
The irreducible algebraic representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ are indexed by integer sequences
$lambda_1geqlambda_2geqdotsgeqlambda_n$.



Fulton, Harris (Representation Theory, Proposition 15.47):
Every irreducible complex representation of $operatornameGL_n(mathbbC)$ is isomorphic to $varphi^lambda$
for a unique index $lambda=lambda_1,dots,lambda_n$ with
$lambda_1geqlambda_2geqdotsgeqlambda_n$.




My questions are:



  1. Is every algebraic irreducible representation indexed by a partition or by an integer sequence with $lambda_1geqlambda_2geqdotsgeqlambda_n$?

  2. Can every irreducible representation be indexed by an integer partition with $lambda_1geqlambda_2geqdotsgeqlambda_n$ or only the irreducible alegbraic representations?






share|cite|improve this question





















  • What values do Fulton-Harris allow for the $lambda_i$?
    – Tobias Kildetoft
    Jul 24 at 7:29










  • I just looked up the result in Stanley, and you misquoted it slightly. It should be "polynomial" instead of "algebraic".
    – Tobias Kildetoft
    Jul 24 at 7:34










  • @TobiasKildetoft It says that some of the $lambda_i$ can be negative. So, they're integers.
    – user160919
    Jul 24 at 7:35











  • @TobiasKildetoft That's true. But aren't polynomial and algebraic representations not the same thing?
    – user160919
    Jul 24 at 7:36






  • 3




    No, being polynomial is stronger than being algebraic, and here it precisely amounts to whether one allows negative powers of the determinant to appear.
    – Tobias Kildetoft
    Jul 24 at 7:45












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I just started to learn representation theory and I'm interested in the irreducible representations of $operatornameGL_n(mathbbC)$. I looked them up in three different books and apparently, I misunderstood something because for me, they are inconsistent statements.




Stanley (Enumerative Combinatorics II, Theorem A2.4):
The irreducible polynomial representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ can be indexed by partitions
$lambda$ of length at most $n$.



Bump (Lie Groups, Theorem 38.3):
The irreducible algebraic representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ are indexed by integer sequences
$lambda_1geqlambda_2geqdotsgeqlambda_n$.



Fulton, Harris (Representation Theory, Proposition 15.47):
Every irreducible complex representation of $operatornameGL_n(mathbbC)$ is isomorphic to $varphi^lambda$
for a unique index $lambda=lambda_1,dots,lambda_n$ with
$lambda_1geqlambda_2geqdotsgeqlambda_n$.




My questions are:



  1. Is every algebraic irreducible representation indexed by a partition or by an integer sequence with $lambda_1geqlambda_2geqdotsgeqlambda_n$?

  2. Can every irreducible representation be indexed by an integer partition with $lambda_1geqlambda_2geqdotsgeqlambda_n$ or only the irreducible alegbraic representations?






share|cite|improve this question













I just started to learn representation theory and I'm interested in the irreducible representations of $operatornameGL_n(mathbbC)$. I looked them up in three different books and apparently, I misunderstood something because for me, they are inconsistent statements.




Stanley (Enumerative Combinatorics II, Theorem A2.4):
The irreducible polynomial representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ can be indexed by partitions
$lambda$ of length at most $n$.



Bump (Lie Groups, Theorem 38.3):
The irreducible algebraic representations $varphi^lambda$ of $operatornameGL_n(mathbbC)$ are indexed by integer sequences
$lambda_1geqlambda_2geqdotsgeqlambda_n$.



Fulton, Harris (Representation Theory, Proposition 15.47):
Every irreducible complex representation of $operatornameGL_n(mathbbC)$ is isomorphic to $varphi^lambda$
for a unique index $lambda=lambda_1,dots,lambda_n$ with
$lambda_1geqlambda_2geqdotsgeqlambda_n$.




My questions are:



  1. Is every algebraic irreducible representation indexed by a partition or by an integer sequence with $lambda_1geqlambda_2geqdotsgeqlambda_n$?

  2. Can every irreducible representation be indexed by an integer partition with $lambda_1geqlambda_2geqdotsgeqlambda_n$ or only the irreducible alegbraic representations?








share|cite|improve this question












share|cite|improve this question




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edited Jul 24 at 7:47
























asked Jul 24 at 7:22









user160919

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  • What values do Fulton-Harris allow for the $lambda_i$?
    – Tobias Kildetoft
    Jul 24 at 7:29










  • I just looked up the result in Stanley, and you misquoted it slightly. It should be "polynomial" instead of "algebraic".
    – Tobias Kildetoft
    Jul 24 at 7:34










  • @TobiasKildetoft It says that some of the $lambda_i$ can be negative. So, they're integers.
    – user160919
    Jul 24 at 7:35











  • @TobiasKildetoft That's true. But aren't polynomial and algebraic representations not the same thing?
    – user160919
    Jul 24 at 7:36






  • 3




    No, being polynomial is stronger than being algebraic, and here it precisely amounts to whether one allows negative powers of the determinant to appear.
    – Tobias Kildetoft
    Jul 24 at 7:45
















  • What values do Fulton-Harris allow for the $lambda_i$?
    – Tobias Kildetoft
    Jul 24 at 7:29










  • I just looked up the result in Stanley, and you misquoted it slightly. It should be "polynomial" instead of "algebraic".
    – Tobias Kildetoft
    Jul 24 at 7:34










  • @TobiasKildetoft It says that some of the $lambda_i$ can be negative. So, they're integers.
    – user160919
    Jul 24 at 7:35











  • @TobiasKildetoft That's true. But aren't polynomial and algebraic representations not the same thing?
    – user160919
    Jul 24 at 7:36






  • 3




    No, being polynomial is stronger than being algebraic, and here it precisely amounts to whether one allows negative powers of the determinant to appear.
    – Tobias Kildetoft
    Jul 24 at 7:45















What values do Fulton-Harris allow for the $lambda_i$?
– Tobias Kildetoft
Jul 24 at 7:29




What values do Fulton-Harris allow for the $lambda_i$?
– Tobias Kildetoft
Jul 24 at 7:29












I just looked up the result in Stanley, and you misquoted it slightly. It should be "polynomial" instead of "algebraic".
– Tobias Kildetoft
Jul 24 at 7:34




I just looked up the result in Stanley, and you misquoted it slightly. It should be "polynomial" instead of "algebraic".
– Tobias Kildetoft
Jul 24 at 7:34












@TobiasKildetoft It says that some of the $lambda_i$ can be negative. So, they're integers.
– user160919
Jul 24 at 7:35





@TobiasKildetoft It says that some of the $lambda_i$ can be negative. So, they're integers.
– user160919
Jul 24 at 7:35













@TobiasKildetoft That's true. But aren't polynomial and algebraic representations not the same thing?
– user160919
Jul 24 at 7:36




@TobiasKildetoft That's true. But aren't polynomial and algebraic representations not the same thing?
– user160919
Jul 24 at 7:36




3




3




No, being polynomial is stronger than being algebraic, and here it precisely amounts to whether one allows negative powers of the determinant to appear.
– Tobias Kildetoft
Jul 24 at 7:45




No, being polynomial is stronger than being algebraic, and here it precisely amounts to whether one allows negative powers of the determinant to appear.
– Tobias Kildetoft
Jul 24 at 7:45















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