Minimum of random and constant scaled with random variable

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Suppose that $X$ and $Y$are independent random variables, while $c geq 0$ is a constant. More specifically, $X$ is the $n$-fold convolution of $Y$. Is it then correct to say the following?



$min(Y,c)+X = min(Y+X, c+X)$



Obviously this would be correct for only constants. But does it hold for random variables?







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    up vote
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    down vote

    favorite












    Suppose that $X$ and $Y$are independent random variables, while $c geq 0$ is a constant. More specifically, $X$ is the $n$-fold convolution of $Y$. Is it then correct to say the following?



    $min(Y,c)+X = min(Y+X, c+X)$



    Obviously this would be correct for only constants. But does it hold for random variables?







    share|cite|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Suppose that $X$ and $Y$are independent random variables, while $c geq 0$ is a constant. More specifically, $X$ is the $n$-fold convolution of $Y$. Is it then correct to say the following?



      $min(Y,c)+X = min(Y+X, c+X)$



      Obviously this would be correct for only constants. But does it hold for random variables?







      share|cite|improve this question













      Suppose that $X$ and $Y$are independent random variables, while $c geq 0$ is a constant. More specifically, $X$ is the $n$-fold convolution of $Y$. Is it then correct to say the following?



      $min(Y,c)+X = min(Y+X, c+X)$



      Obviously this would be correct for only constants. But does it hold for random variables?









      share|cite|improve this question












      share|cite|improve this question




      share|cite|improve this question








      edited Jul 20 at 9:54
























      asked Jul 20 at 9:40









      JoeS

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          This has nothing to do with random variables. For any three real numbers $a,b,c$ we have $min (a,c)+b =min (a+b,c+b)$ so the same holds for random variables. [You can just verify the equation for the cases $a leq c$ and $a>c$].






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          • Thanks for the quick reply!
            – JoeS
            Jul 20 at 10:07










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          1 Answer
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          This has nothing to do with random variables. For any three real numbers $a,b,c$ we have $min (a,c)+b =min (a+b,c+b)$ so the same holds for random variables. [You can just verify the equation for the cases $a leq c$ and $a>c$].






          share|cite|improve this answer





















          • Thanks for the quick reply!
            – JoeS
            Jul 20 at 10:07














          up vote
          1
          down vote













          This has nothing to do with random variables. For any three real numbers $a,b,c$ we have $min (a,c)+b =min (a+b,c+b)$ so the same holds for random variables. [You can just verify the equation for the cases $a leq c$ and $a>c$].






          share|cite|improve this answer





















          • Thanks for the quick reply!
            – JoeS
            Jul 20 at 10:07












          up vote
          1
          down vote










          up vote
          1
          down vote









          This has nothing to do with random variables. For any three real numbers $a,b,c$ we have $min (a,c)+b =min (a+b,c+b)$ so the same holds for random variables. [You can just verify the equation for the cases $a leq c$ and $a>c$].






          share|cite|improve this answer













          This has nothing to do with random variables. For any three real numbers $a,b,c$ we have $min (a,c)+b =min (a+b,c+b)$ so the same holds for random variables. [You can just verify the equation for the cases $a leq c$ and $a>c$].







          share|cite|improve this answer













          share|cite|improve this answer



          share|cite|improve this answer











          answered Jul 20 at 9:55









          Kavi Rama Murthy

          20.6k2830




          20.6k2830











          • Thanks for the quick reply!
            – JoeS
            Jul 20 at 10:07
















          • Thanks for the quick reply!
            – JoeS
            Jul 20 at 10:07















          Thanks for the quick reply!
          – JoeS
          Jul 20 at 10:07




          Thanks for the quick reply!
          – JoeS
          Jul 20 at 10:07












           

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