ODE with power series and non-zero initial conditions
Clash Royale CLAN TAG#URR8PPP
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I should resolve
$$y''-(1+x)y=0$$
First for $y(0)=-3,y'(0)=6$. In this case, I got some values until for $a_5$ but I didn't see anything between the $a_n$, so I got:
$$y(x)=frac212+sum_n=3^inftyleft[(n+1)(n+2)a_n+2+a_n-1right]x^n$$
I don't know if it's right but I have a bigger problem: what am I supposed to do when the initial conditions are $y(2)=4$ and $y'(2)=3$?
differential-equations power-series
add a comment |Â
up vote
0
down vote
favorite
I should resolve
$$y''-(1+x)y=0$$
First for $y(0)=-3,y'(0)=6$. In this case, I got some values until for $a_5$ but I didn't see anything between the $a_n$, so I got:
$$y(x)=frac212+sum_n=3^inftyleft[(n+1)(n+2)a_n+2+a_n-1right]x^n$$
I don't know if it's right but I have a bigger problem: what am I supposed to do when the initial conditions are $y(2)=4$ and $y'(2)=3$?
differential-equations power-series
4
Being very lazy, I suppose that I should define $t=x-2$ and make the series in terms of $t$.
– Claude Leibovici
Jul 16 at 4:12
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I should resolve
$$y''-(1+x)y=0$$
First for $y(0)=-3,y'(0)=6$. In this case, I got some values until for $a_5$ but I didn't see anything between the $a_n$, so I got:
$$y(x)=frac212+sum_n=3^inftyleft[(n+1)(n+2)a_n+2+a_n-1right]x^n$$
I don't know if it's right but I have a bigger problem: what am I supposed to do when the initial conditions are $y(2)=4$ and $y'(2)=3$?
differential-equations power-series
I should resolve
$$y''-(1+x)y=0$$
First for $y(0)=-3,y'(0)=6$. In this case, I got some values until for $a_5$ but I didn't see anything between the $a_n$, so I got:
$$y(x)=frac212+sum_n=3^inftyleft[(n+1)(n+2)a_n+2+a_n-1right]x^n$$
I don't know if it's right but I have a bigger problem: what am I supposed to do when the initial conditions are $y(2)=4$ and $y'(2)=3$?
differential-equations power-series
asked Jul 16 at 2:31
mvfs314
422210
422210
4
Being very lazy, I suppose that I should define $t=x-2$ and make the series in terms of $t$.
– Claude Leibovici
Jul 16 at 4:12
add a comment |Â
4
Being very lazy, I suppose that I should define $t=x-2$ and make the series in terms of $t$.
– Claude Leibovici
Jul 16 at 4:12
4
4
Being very lazy, I suppose that I should define $t=x-2$ and make the series in terms of $t$.
– Claude Leibovici
Jul 16 at 4:12
Being very lazy, I suppose that I should define $t=x-2$ and make the series in terms of $t$.
– Claude Leibovici
Jul 16 at 4:12
add a comment |Â
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4
Being very lazy, I suppose that I should define $t=x-2$ and make the series in terms of $t$.
– Claude Leibovici
Jul 16 at 4:12