On a certain topology on the set of continuous functions between topological spaces
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Let $A,X,Y$ be topological spaces. Given a function $g: A times X to Y$, we can make a corresponding function $bar g: A to Y^X$ as $bar g(a) (x)=g(a,x), forall a in A, x in X$, and vice-versa. The "exponential topology" on $C(X,Y)$ (the set of all continuous functions from $X$ to $Y$) is a topology on it such that for every topological space $A$, $g in C(Atimes X,Y) iff bar g in C(A,C(X,Y))$ .
I can show that if an exponential topology on $C(X,Y)$ exists then it is unique.
My question is: Does there exists an exponential topology on $C(X,Y)$ when $X=Y=[0,1]$ ?
general-topology continuity
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Let $A,X,Y$ be topological spaces. Given a function $g: A times X to Y$, we can make a corresponding function $bar g: A to Y^X$ as $bar g(a) (x)=g(a,x), forall a in A, x in X$, and vice-versa. The "exponential topology" on $C(X,Y)$ (the set of all continuous functions from $X$ to $Y$) is a topology on it such that for every topological space $A$, $g in C(Atimes X,Y) iff bar g in C(A,C(X,Y))$ .
I can show that if an exponential topology on $C(X,Y)$ exists then it is unique.
My question is: Does there exists an exponential topology on $C(X,Y)$ when $X=Y=[0,1]$ ?
general-topology continuity
add a comment |Â
up vote
2
down vote
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up vote
2
down vote
favorite
Let $A,X,Y$ be topological spaces. Given a function $g: A times X to Y$, we can make a corresponding function $bar g: A to Y^X$ as $bar g(a) (x)=g(a,x), forall a in A, x in X$, and vice-versa. The "exponential topology" on $C(X,Y)$ (the set of all continuous functions from $X$ to $Y$) is a topology on it such that for every topological space $A$, $g in C(Atimes X,Y) iff bar g in C(A,C(X,Y))$ .
I can show that if an exponential topology on $C(X,Y)$ exists then it is unique.
My question is: Does there exists an exponential topology on $C(X,Y)$ when $X=Y=[0,1]$ ?
general-topology continuity
Let $A,X,Y$ be topological spaces. Given a function $g: A times X to Y$, we can make a corresponding function $bar g: A to Y^X$ as $bar g(a) (x)=g(a,x), forall a in A, x in X$, and vice-versa. The "exponential topology" on $C(X,Y)$ (the set of all continuous functions from $X$ to $Y$) is a topology on it such that for every topological space $A$, $g in C(Atimes X,Y) iff bar g in C(A,C(X,Y))$ .
I can show that if an exponential topology on $C(X,Y)$ exists then it is unique.
My question is: Does there exists an exponential topology on $C(X,Y)$ when $X=Y=[0,1]$ ?
general-topology continuity
asked Jul 28 at 21:50
user521337
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1 Answer
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You should consult any book on general topology which covers function spaces, for example
Engelking, Ryszard. "General topology." (1989)
The correspondence $g mapsto overlineg$ is defined for all (not necessarily continuous) functions $g : A times X to Y$. It is called the exponential map $Lambda : mathcalF(A times X, Y) to mathcalF(A, mathcalF(X,Y))$. Here, $mathcalF(M,N)$ denotes the set of all functions $M to N$. If we restrict to continuous functions, we shall consider topologies $mathfrakT_X,Y$ on $C(X,Y)$. Let us define
(1) $mathfrakT_X,Y$ is proper if $Lambda(C(A times X,Y) subset C(A, (C(X,Y),mathfrakT_X,Y))$ for all $A$.
(2) $mathfrakT_X,Y$ is admissible if $Lambda^-1(C(A, (C(X,Y),mathfrakT_X,Y))) subset C(A times X,Y)$ for all $A$.
(3) $mathfrakT_X,Y$ is acceptable if it is both proper and admissible (this is what you call exponential topology).
It is a well-known fact that there exist at most one acceptable topology on $C(X,Y)$. Usually function spaces are endowed with the compact-open topology and it is well-known that the compact-open topology is
(a) proper for all spaces $X,Y$,
(b) admissible for all locally compact spaces $X$ and all spaces $Y$.
This answers your question in the affirmative.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
You should consult any book on general topology which covers function spaces, for example
Engelking, Ryszard. "General topology." (1989)
The correspondence $g mapsto overlineg$ is defined for all (not necessarily continuous) functions $g : A times X to Y$. It is called the exponential map $Lambda : mathcalF(A times X, Y) to mathcalF(A, mathcalF(X,Y))$. Here, $mathcalF(M,N)$ denotes the set of all functions $M to N$. If we restrict to continuous functions, we shall consider topologies $mathfrakT_X,Y$ on $C(X,Y)$. Let us define
(1) $mathfrakT_X,Y$ is proper if $Lambda(C(A times X,Y) subset C(A, (C(X,Y),mathfrakT_X,Y))$ for all $A$.
(2) $mathfrakT_X,Y$ is admissible if $Lambda^-1(C(A, (C(X,Y),mathfrakT_X,Y))) subset C(A times X,Y)$ for all $A$.
(3) $mathfrakT_X,Y$ is acceptable if it is both proper and admissible (this is what you call exponential topology).
It is a well-known fact that there exist at most one acceptable topology on $C(X,Y)$. Usually function spaces are endowed with the compact-open topology and it is well-known that the compact-open topology is
(a) proper for all spaces $X,Y$,
(b) admissible for all locally compact spaces $X$ and all spaces $Y$.
This answers your question in the affirmative.
add a comment |Â
up vote
1
down vote
You should consult any book on general topology which covers function spaces, for example
Engelking, Ryszard. "General topology." (1989)
The correspondence $g mapsto overlineg$ is defined for all (not necessarily continuous) functions $g : A times X to Y$. It is called the exponential map $Lambda : mathcalF(A times X, Y) to mathcalF(A, mathcalF(X,Y))$. Here, $mathcalF(M,N)$ denotes the set of all functions $M to N$. If we restrict to continuous functions, we shall consider topologies $mathfrakT_X,Y$ on $C(X,Y)$. Let us define
(1) $mathfrakT_X,Y$ is proper if $Lambda(C(A times X,Y) subset C(A, (C(X,Y),mathfrakT_X,Y))$ for all $A$.
(2) $mathfrakT_X,Y$ is admissible if $Lambda^-1(C(A, (C(X,Y),mathfrakT_X,Y))) subset C(A times X,Y)$ for all $A$.
(3) $mathfrakT_X,Y$ is acceptable if it is both proper and admissible (this is what you call exponential topology).
It is a well-known fact that there exist at most one acceptable topology on $C(X,Y)$. Usually function spaces are endowed with the compact-open topology and it is well-known that the compact-open topology is
(a) proper for all spaces $X,Y$,
(b) admissible for all locally compact spaces $X$ and all spaces $Y$.
This answers your question in the affirmative.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
You should consult any book on general topology which covers function spaces, for example
Engelking, Ryszard. "General topology." (1989)
The correspondence $g mapsto overlineg$ is defined for all (not necessarily continuous) functions $g : A times X to Y$. It is called the exponential map $Lambda : mathcalF(A times X, Y) to mathcalF(A, mathcalF(X,Y))$. Here, $mathcalF(M,N)$ denotes the set of all functions $M to N$. If we restrict to continuous functions, we shall consider topologies $mathfrakT_X,Y$ on $C(X,Y)$. Let us define
(1) $mathfrakT_X,Y$ is proper if $Lambda(C(A times X,Y) subset C(A, (C(X,Y),mathfrakT_X,Y))$ for all $A$.
(2) $mathfrakT_X,Y$ is admissible if $Lambda^-1(C(A, (C(X,Y),mathfrakT_X,Y))) subset C(A times X,Y)$ for all $A$.
(3) $mathfrakT_X,Y$ is acceptable if it is both proper and admissible (this is what you call exponential topology).
It is a well-known fact that there exist at most one acceptable topology on $C(X,Y)$. Usually function spaces are endowed with the compact-open topology and it is well-known that the compact-open topology is
(a) proper for all spaces $X,Y$,
(b) admissible for all locally compact spaces $X$ and all spaces $Y$.
This answers your question in the affirmative.
You should consult any book on general topology which covers function spaces, for example
Engelking, Ryszard. "General topology." (1989)
The correspondence $g mapsto overlineg$ is defined for all (not necessarily continuous) functions $g : A times X to Y$. It is called the exponential map $Lambda : mathcalF(A times X, Y) to mathcalF(A, mathcalF(X,Y))$. Here, $mathcalF(M,N)$ denotes the set of all functions $M to N$. If we restrict to continuous functions, we shall consider topologies $mathfrakT_X,Y$ on $C(X,Y)$. Let us define
(1) $mathfrakT_X,Y$ is proper if $Lambda(C(A times X,Y) subset C(A, (C(X,Y),mathfrakT_X,Y))$ for all $A$.
(2) $mathfrakT_X,Y$ is admissible if $Lambda^-1(C(A, (C(X,Y),mathfrakT_X,Y))) subset C(A times X,Y)$ for all $A$.
(3) $mathfrakT_X,Y$ is acceptable if it is both proper and admissible (this is what you call exponential topology).
It is a well-known fact that there exist at most one acceptable topology on $C(X,Y)$. Usually function spaces are endowed with the compact-open topology and it is well-known that the compact-open topology is
(a) proper for all spaces $X,Y$,
(b) admissible for all locally compact spaces $X$ and all spaces $Y$.
This answers your question in the affirmative.
answered Jul 29 at 0:07
Paul Frost
3,593420
3,593420
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