Open set in $C^1_0(overlineOmega)$

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Let $Omega$ be a bounded domain in $mathbbR^N$ with $partial Omega$ of class $C^2$ and denote $C^1_0(overlineOmega):=uin C^1(overlineOmega): u=0 text on partialOmega$. For $u,v:overlineOmegatomathbbR$ we write $ull v$ if $u(x)<v(x)$ for every $xin Omega$ and, if $u(x)=v(x)$ for some $xinpartial Omega$, then $fracpartial vpartial nu(x)<fracpartial upartial nu(x)$, where $nu=nu(x)$ denotes the unit outer normal to $Omega$ at $xinpartialOmega$.



I need a proof for the fact that the following set $S=uin C^1_0(overlineOmega): all ull b$ is open in $C^1_0(overlineOmega)$.



Above $a,bin C^1,0(overlineOmega)$ with $aleq 0$ on $partialOmega$ and
$bgeq 0$ on $partialOmega$.



Many thanks!







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    Let $Omega$ be a bounded domain in $mathbbR^N$ with $partial Omega$ of class $C^2$ and denote $C^1_0(overlineOmega):=uin C^1(overlineOmega): u=0 text on partialOmega$. For $u,v:overlineOmegatomathbbR$ we write $ull v$ if $u(x)<v(x)$ for every $xin Omega$ and, if $u(x)=v(x)$ for some $xinpartial Omega$, then $fracpartial vpartial nu(x)<fracpartial upartial nu(x)$, where $nu=nu(x)$ denotes the unit outer normal to $Omega$ at $xinpartialOmega$.



    I need a proof for the fact that the following set $S=uin C^1_0(overlineOmega): all ull b$ is open in $C^1_0(overlineOmega)$.



    Above $a,bin C^1,0(overlineOmega)$ with $aleq 0$ on $partialOmega$ and
    $bgeq 0$ on $partialOmega$.



    Many thanks!







    share|cite|improve this question





















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Let $Omega$ be a bounded domain in $mathbbR^N$ with $partial Omega$ of class $C^2$ and denote $C^1_0(overlineOmega):=uin C^1(overlineOmega): u=0 text on partialOmega$. For $u,v:overlineOmegatomathbbR$ we write $ull v$ if $u(x)<v(x)$ for every $xin Omega$ and, if $u(x)=v(x)$ for some $xinpartial Omega$, then $fracpartial vpartial nu(x)<fracpartial upartial nu(x)$, where $nu=nu(x)$ denotes the unit outer normal to $Omega$ at $xinpartialOmega$.



      I need a proof for the fact that the following set $S=uin C^1_0(overlineOmega): all ull b$ is open in $C^1_0(overlineOmega)$.



      Above $a,bin C^1,0(overlineOmega)$ with $aleq 0$ on $partialOmega$ and
      $bgeq 0$ on $partialOmega$.



      Many thanks!







      share|cite|improve this question











      Let $Omega$ be a bounded domain in $mathbbR^N$ with $partial Omega$ of class $C^2$ and denote $C^1_0(overlineOmega):=uin C^1(overlineOmega): u=0 text on partialOmega$. For $u,v:overlineOmegatomathbbR$ we write $ull v$ if $u(x)<v(x)$ for every $xin Omega$ and, if $u(x)=v(x)$ for some $xinpartial Omega$, then $fracpartial vpartial nu(x)<fracpartial upartial nu(x)$, where $nu=nu(x)$ denotes the unit outer normal to $Omega$ at $xinpartialOmega$.



      I need a proof for the fact that the following set $S=uin C^1_0(overlineOmega): all ull b$ is open in $C^1_0(overlineOmega)$.



      Above $a,bin C^1,0(overlineOmega)$ with $aleq 0$ on $partialOmega$ and
      $bgeq 0$ on $partialOmega$.



      Many thanks!









      share|cite|improve this question










      share|cite|improve this question




      share|cite|improve this question









      asked Jul 19 at 18:30









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