What does it mean for an odd function to be odd about an end of an interval (at $x=L$)?

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What does it mean for an odd function to be odd about an end of an interval (at $x=L$, when the interval is $[0,L]$ or $[-L,L]$)?



E.g. the sine function is odd under reflection about $0$, but also about the end $L$ of the interval $[0,L]$.



What does this mean? Does it mean that it doesn't matter at which interval (containing $0$) one watches the sine, it will still be odd.







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  • "odd about an end of an interval" Please define!
    – herb steinberg
    Jul 24 at 21:15














up vote
0
down vote

favorite












What does it mean for an odd function to be odd about an end of an interval (at $x=L$, when the interval is $[0,L]$ or $[-L,L]$)?



E.g. the sine function is odd under reflection about $0$, but also about the end $L$ of the interval $[0,L]$.



What does this mean? Does it mean that it doesn't matter at which interval (containing $0$) one watches the sine, it will still be odd.







share|cite|improve this question





















  • "odd about an end of an interval" Please define!
    – herb steinberg
    Jul 24 at 21:15












up vote
0
down vote

favorite









up vote
0
down vote

favorite











What does it mean for an odd function to be odd about an end of an interval (at $x=L$, when the interval is $[0,L]$ or $[-L,L]$)?



E.g. the sine function is odd under reflection about $0$, but also about the end $L$ of the interval $[0,L]$.



What does this mean? Does it mean that it doesn't matter at which interval (containing $0$) one watches the sine, it will still be odd.







share|cite|improve this question













What does it mean for an odd function to be odd about an end of an interval (at $x=L$, when the interval is $[0,L]$ or $[-L,L]$)?



E.g. the sine function is odd under reflection about $0$, but also about the end $L$ of the interval $[0,L]$.



What does this mean? Does it mean that it doesn't matter at which interval (containing $0$) one watches the sine, it will still be odd.









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 24 at 21:28
























asked Jul 24 at 19:32









mavavilj

2,426729




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  • "odd about an end of an interval" Please define!
    – herb steinberg
    Jul 24 at 21:15
















  • "odd about an end of an interval" Please define!
    – herb steinberg
    Jul 24 at 21:15















"odd about an end of an interval" Please define!
– herb steinberg
Jul 24 at 21:15




"odd about an end of an interval" Please define!
– herb steinberg
Jul 24 at 21:15










1 Answer
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It means that $$f(L-x)=-f(L+x)$$






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  • Ah makes sense, if one puts $L=0$.
    – mavavilj
    Jul 24 at 21:28










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










It means that $$f(L-x)=-f(L+x)$$






share|cite|improve this answer





















  • Ah makes sense, if one puts $L=0$.
    – mavavilj
    Jul 24 at 21:28














up vote
2
down vote



accepted










It means that $$f(L-x)=-f(L+x)$$






share|cite|improve this answer





















  • Ah makes sense, if one puts $L=0$.
    – mavavilj
    Jul 24 at 21:28












up vote
2
down vote



accepted







up vote
2
down vote



accepted






It means that $$f(L-x)=-f(L+x)$$






share|cite|improve this answer













It means that $$f(L-x)=-f(L+x)$$







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered Jul 24 at 21:17









Empy2

31.8k12059




31.8k12059











  • Ah makes sense, if one puts $L=0$.
    – mavavilj
    Jul 24 at 21:28
















  • Ah makes sense, if one puts $L=0$.
    – mavavilj
    Jul 24 at 21:28















Ah makes sense, if one puts $L=0$.
– mavavilj
Jul 24 at 21:28




Ah makes sense, if one puts $L=0$.
– mavavilj
Jul 24 at 21:28












 

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