basis for subspace of dim $n-1$ in $mathbbR^n$ [closed]
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Assume we have subspace $T = w in mathbbR^n $ with $v$ a direction in $mathbbR^n$.
What is the most efficient way to construct a basis for $T$?
As $n$ is in general large, I want to avoid using gram-schmidt, since that is too costly.
kind regards,
Koen
linear-algebra
closed as unclear what you're asking by Batominovski, John Ma, Mostafa Ayaz, José Carlos Santos, ΘΣΦGenSan Jul 31 at 22:47
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
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Assume we have subspace $T = w in mathbbR^n $ with $v$ a direction in $mathbbR^n$.
What is the most efficient way to construct a basis for $T$?
As $n$ is in general large, I want to avoid using gram-schmidt, since that is too costly.
kind regards,
Koen
linear-algebra
closed as unclear what you're asking by Batominovski, John Ma, Mostafa Ayaz, José Carlos Santos, ΘΣΦGenSan Jul 31 at 22:47
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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Your definition of $T$ does not describe a vector space. Do you mean $[v]^perp subset mathbbR^n$?
– Babelfish
Jul 31 at 9:31
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up vote
-1
down vote
favorite
Assume we have subspace $T = w in mathbbR^n $ with $v$ a direction in $mathbbR^n$.
What is the most efficient way to construct a basis for $T$?
As $n$ is in general large, I want to avoid using gram-schmidt, since that is too costly.
kind regards,
Koen
linear-algebra
Assume we have subspace $T = w in mathbbR^n $ with $v$ a direction in $mathbbR^n$.
What is the most efficient way to construct a basis for $T$?
As $n$ is in general large, I want to avoid using gram-schmidt, since that is too costly.
kind regards,
Koen
linear-algebra
edited Aug 1 at 6:56
asked Jul 31 at 9:25
Koen
291113
291113
closed as unclear what you're asking by Batominovski, John Ma, Mostafa Ayaz, José Carlos Santos, ΘΣΦGenSan Jul 31 at 22:47
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by Batominovski, John Ma, Mostafa Ayaz, José Carlos Santos, ΘΣΦGenSan Jul 31 at 22:47
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
Your definition of $T$ does not describe a vector space. Do you mean $[v]^perp subset mathbbR^n$?
– Babelfish
Jul 31 at 9:31
add a comment |Â
2
Your definition of $T$ does not describe a vector space. Do you mean $[v]^perp subset mathbbR^n$?
– Babelfish
Jul 31 at 9:31
2
2
Your definition of $T$ does not describe a vector space. Do you mean $[v]^perp subset mathbbR^n$?
– Babelfish
Jul 31 at 9:31
Your definition of $T$ does not describe a vector space. Do you mean $[v]^perp subset mathbbR^n$?
– Babelfish
Jul 31 at 9:31
add a comment |Â
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$T$ is not a subspace. If you mean $span(v)^perp$ you can complete $v$ to an orthogonal basis $v, w_1, ..., w_n-1$ of $mathbbR^n$ using e.g. the Grahm-Schmidt process and remove $v$ afterwards.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
$T$ is not a subspace. If you mean $span(v)^perp$ you can complete $v$ to an orthogonal basis $v, w_1, ..., w_n-1$ of $mathbbR^n$ using e.g. the Grahm-Schmidt process and remove $v$ afterwards.
add a comment |Â
up vote
0
down vote
$T$ is not a subspace. If you mean $span(v)^perp$ you can complete $v$ to an orthogonal basis $v, w_1, ..., w_n-1$ of $mathbbR^n$ using e.g. the Grahm-Schmidt process and remove $v$ afterwards.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
$T$ is not a subspace. If you mean $span(v)^perp$ you can complete $v$ to an orthogonal basis $v, w_1, ..., w_n-1$ of $mathbbR^n$ using e.g. the Grahm-Schmidt process and remove $v$ afterwards.
$T$ is not a subspace. If you mean $span(v)^perp$ you can complete $v$ to an orthogonal basis $v, w_1, ..., w_n-1$ of $mathbbR^n$ using e.g. the Grahm-Schmidt process and remove $v$ afterwards.
answered Jul 31 at 15:57


til
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2
Your definition of $T$ does not describe a vector space. Do you mean $[v]^perp subset mathbbR^n$?
– Babelfish
Jul 31 at 9:31