Is the solution to this Linear DE bounded?

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given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.




calculus differential-equations




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  • This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
    – user 108128
    Jul 30 at 1:59











  • You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
    – Juan Garcia
    Jul 30 at 2:06











  • Yes It's unboud.
    – user 108128
    Jul 30 at 2:08















up vote
0
down vote

favorite












given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.




calculus differential-equations




share|cite|improve this question



















  • This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
    – user 108128
    Jul 30 at 1:59











  • You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
    – Juan Garcia
    Jul 30 at 2:06











  • Yes It's unboud.
    – user 108128
    Jul 30 at 2:08













up vote
0
down vote

favorite









up vote
0
down vote

favorite











given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.




calculus differential-equations




share|cite|improve this question











given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.





calculus differential-equations





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 30 at 1:54









Juan Garcia

82




82











  • This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
    – user 108128
    Jul 30 at 1:59











  • You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
    – Juan Garcia
    Jul 30 at 2:06











  • Yes It's unboud.
    – user 108128
    Jul 30 at 2:08

















  • This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
    – user 108128
    Jul 30 at 1:59











  • You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
    – Juan Garcia
    Jul 30 at 2:06











  • Yes It's unboud.
    – user 108128
    Jul 30 at 2:08
















This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
– user 108128
Jul 30 at 1:59





This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
– user 108128
Jul 30 at 1:59













You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
– Juan Garcia
Jul 30 at 2:06





You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
– Juan Garcia
Jul 30 at 2:06













Yes It's unboud.
– user 108128
Jul 30 at 2:08





Yes It's unboud.
– user 108128
Jul 30 at 2:08
















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