Is the solution to this Linear DE bounded?
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given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.
calculus differential-equations
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up vote
0
down vote
favorite
given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.
calculus differential-equations
This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
â user 108128
Jul 30 at 1:59
You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
â Juan Garcia
Jul 30 at 2:06
Yes It's unboud.
â user 108128
Jul 30 at 2:08
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.
calculus differential-equations
given $fracmathrmd^2 ymathrmd x^2 -xy=0$ , is the solution bounded when
$xtoinfty $
Well, I've been trying to solve this but I haven't been able so far, I got an implicit solution $yln - y=x^3/6+ct+d$ , where "c" and "d" are constant. Anyway, I am not sure how to do this and the I am asked to graph the solution too.
calculus differential-equations
asked Jul 30 at 1:54
Juan Garcia
82
82
This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
â user 108128
Jul 30 at 1:59
You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
â Juan Garcia
Jul 30 at 2:06
Yes It's unboud.
â user 108128
Jul 30 at 2:08
add a comment |Â
This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
â user 108128
Jul 30 at 1:59
You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
â Juan Garcia
Jul 30 at 2:06
Yes It's unboud.
â user 108128
Jul 30 at 2:08
This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
â user 108128
Jul 30 at 1:59
This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
â user 108128
Jul 30 at 1:59
You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
â Juan Garcia
Jul 30 at 2:06
You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
â Juan Garcia
Jul 30 at 2:06
Yes It's unboud.
â user 108128
Jul 30 at 2:08
Yes It's unboud.
â user 108128
Jul 30 at 2:08
add a comment |Â
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This is Airy DE. See mathworld.wolfram.com/AiryDifferentialEquation.html
â user 108128
Jul 30 at 1:59
You're right, I also tried with power series and I got the same result, if I just do the limit of "x" to infinite, it's infinite, so it's not bounded, right?
â Juan Garcia
Jul 30 at 2:06
Yes It's unboud.
â user 108128
Jul 30 at 2:08