Choosing a kernel embedding for a linear separator

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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The following is a slide from a presentation on machine learning, the context is using the kernel trick for non-linear separation. enter image description here



Does it make any difference that the mapping is $xmapsto (x,x^2)$ rather then $xmapsto (x^2,x)$ or will the data be separable under one mapping iff it is separable under the other? In general, in the context of embedding samples to some feature space, does the order of the coordinates matter? I may be missing something quite fundamental here but it would seem that this can have an effect on the separability of the embedded vectors.







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  • Do you see why the given diagram is separable by half-spaces? Can you construct a similar diagram for the map $x to (x^2,x)$?
    – Daniel Littlewood
    Jul 16 at 14:47











  • For the points in the picture, sure. But who's to say, a priori, that there does not exist a collection of points for which first map yields a separation while the second map does not?
    – D.M.
    Jul 16 at 14:55














up vote
1
down vote

favorite












The following is a slide from a presentation on machine learning, the context is using the kernel trick for non-linear separation. enter image description here



Does it make any difference that the mapping is $xmapsto (x,x^2)$ rather then $xmapsto (x^2,x)$ or will the data be separable under one mapping iff it is separable under the other? In general, in the context of embedding samples to some feature space, does the order of the coordinates matter? I may be missing something quite fundamental here but it would seem that this can have an effect on the separability of the embedded vectors.







share|cite|improve this question



















  • Do you see why the given diagram is separable by half-spaces? Can you construct a similar diagram for the map $x to (x^2,x)$?
    – Daniel Littlewood
    Jul 16 at 14:47











  • For the points in the picture, sure. But who's to say, a priori, that there does not exist a collection of points for which first map yields a separation while the second map does not?
    – D.M.
    Jul 16 at 14:55












up vote
1
down vote

favorite









up vote
1
down vote

favorite











The following is a slide from a presentation on machine learning, the context is using the kernel trick for non-linear separation. enter image description here



Does it make any difference that the mapping is $xmapsto (x,x^2)$ rather then $xmapsto (x^2,x)$ or will the data be separable under one mapping iff it is separable under the other? In general, in the context of embedding samples to some feature space, does the order of the coordinates matter? I may be missing something quite fundamental here but it would seem that this can have an effect on the separability of the embedded vectors.







share|cite|improve this question











The following is a slide from a presentation on machine learning, the context is using the kernel trick for non-linear separation. enter image description here



Does it make any difference that the mapping is $xmapsto (x,x^2)$ rather then $xmapsto (x^2,x)$ or will the data be separable under one mapping iff it is separable under the other? In general, in the context of embedding samples to some feature space, does the order of the coordinates matter? I may be missing something quite fundamental here but it would seem that this can have an effect on the separability of the embedded vectors.









share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 16 at 14:39









D.M.

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  • Do you see why the given diagram is separable by half-spaces? Can you construct a similar diagram for the map $x to (x^2,x)$?
    – Daniel Littlewood
    Jul 16 at 14:47











  • For the points in the picture, sure. But who's to say, a priori, that there does not exist a collection of points for which first map yields a separation while the second map does not?
    – D.M.
    Jul 16 at 14:55
















  • Do you see why the given diagram is separable by half-spaces? Can you construct a similar diagram for the map $x to (x^2,x)$?
    – Daniel Littlewood
    Jul 16 at 14:47











  • For the points in the picture, sure. But who's to say, a priori, that there does not exist a collection of points for which first map yields a separation while the second map does not?
    – D.M.
    Jul 16 at 14:55















Do you see why the given diagram is separable by half-spaces? Can you construct a similar diagram for the map $x to (x^2,x)$?
– Daniel Littlewood
Jul 16 at 14:47





Do you see why the given diagram is separable by half-spaces? Can you construct a similar diagram for the map $x to (x^2,x)$?
– Daniel Littlewood
Jul 16 at 14:47













For the points in the picture, sure. But who's to say, a priori, that there does not exist a collection of points for which first map yields a separation while the second map does not?
– D.M.
Jul 16 at 14:55




For the points in the picture, sure. But who's to say, a priori, that there does not exist a collection of points for which first map yields a separation while the second map does not?
– D.M.
Jul 16 at 14:55















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