How to find value of x?
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Find the value of x.
Trail: Let consider the point between B and C is D. So $angle ADB =120^circ$ and $angle DAB =15^circ$. I believe that $angle DAC =30^circ$. But I am not sure. Please help me. Thanks in advance.
geometry trigonometry triangle
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up vote
0
down vote
favorite
Find the value of x.
Trail: Let consider the point between B and C is D. So $angle ADB =120^circ$ and $angle DAB =15^circ$. I believe that $angle DAC =30^circ$. But I am not sure. Please help me. Thanks in advance.
geometry trigonometry triangle
1
Why do you believe that $angle DAC = 30^circ$?
– Babelfish
Jul 25 at 7:48
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Find the value of x.
Trail: Let consider the point between B and C is D. So $angle ADB =120^circ$ and $angle DAB =15^circ$. I believe that $angle DAC =30^circ$. But I am not sure. Please help me. Thanks in advance.
geometry trigonometry triangle
Find the value of x.
Trail: Let consider the point between B and C is D. So $angle ADB =120^circ$ and $angle DAB =15^circ$. I believe that $angle DAC =30^circ$. But I am not sure. Please help me. Thanks in advance.
geometry trigonometry triangle
edited Jul 25 at 7:51


Babelfish
408112
408112
asked Jul 25 at 7:25
R DE
415
415
1
Why do you believe that $angle DAC = 30^circ$?
– Babelfish
Jul 25 at 7:48
add a comment |Â
1
Why do you believe that $angle DAC = 30^circ$?
– Babelfish
Jul 25 at 7:48
1
1
Why do you believe that $angle DAC = 30^circ$?
– Babelfish
Jul 25 at 7:48
Why do you believe that $angle DAC = 30^circ$?
– Babelfish
Jul 25 at 7:48
add a comment |Â
2 Answers
2
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oldest
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up vote
0
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Apply the Sine Rule to $Delta ADB$ and $Delta ABC$ to find two expressions for $AB$. That lets you relate $sin x$ to $sin(x+45)$. Then solve for $tan x$.
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
add a comment |Â
up vote
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So from $triangle ADB$ using sine rule, we get
$$fracsin 15 1=fracsin 120 AB=fracsin 45 AD$$
Similarly from $triangle ABC$ using sine rule, we get
$$fracsin (135-x) 3=fracsin x AB=fracsin 45 AC$$
So equating $AB$ from this two equations we get
$$fracsin (135-x) sin x =frac3sin 15 sin 120$$
Then I'm stuck.
1
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
1
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Apply the Sine Rule to $Delta ADB$ and $Delta ABC$ to find two expressions for $AB$. That lets you relate $sin x$ to $sin(x+45)$. Then solve for $tan x$.
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
add a comment |Â
up vote
0
down vote
Apply the Sine Rule to $Delta ADB$ and $Delta ABC$ to find two expressions for $AB$. That lets you relate $sin x$ to $sin(x+45)$. Then solve for $tan x$.
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Apply the Sine Rule to $Delta ADB$ and $Delta ABC$ to find two expressions for $AB$. That lets you relate $sin x$ to $sin(x+45)$. Then solve for $tan x$.
Apply the Sine Rule to $Delta ADB$ and $Delta ABC$ to find two expressions for $AB$. That lets you relate $sin x$ to $sin(x+45)$. Then solve for $tan x$.
answered Jul 25 at 7:47
Empy2
31.8k12059
31.8k12059
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
add a comment |Â
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
I try to solve it but I'm stuck. please help see my answer
– R DE
Jul 25 at 9:49
add a comment |Â
up vote
0
down vote
So from $triangle ADB$ using sine rule, we get
$$fracsin 15 1=fracsin 120 AB=fracsin 45 AD$$
Similarly from $triangle ABC$ using sine rule, we get
$$fracsin (135-x) 3=fracsin x AB=fracsin 45 AC$$
So equating $AB$ from this two equations we get
$$fracsin (135-x) sin x =frac3sin 15 sin 120$$
Then I'm stuck.
1
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
1
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
add a comment |Â
up vote
0
down vote
So from $triangle ADB$ using sine rule, we get
$$fracsin 15 1=fracsin 120 AB=fracsin 45 AD$$
Similarly from $triangle ABC$ using sine rule, we get
$$fracsin (135-x) 3=fracsin x AB=fracsin 45 AC$$
So equating $AB$ from this two equations we get
$$fracsin (135-x) sin x =frac3sin 15 sin 120$$
Then I'm stuck.
1
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
1
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
add a comment |Â
up vote
0
down vote
up vote
0
down vote
So from $triangle ADB$ using sine rule, we get
$$fracsin 15 1=fracsin 120 AB=fracsin 45 AD$$
Similarly from $triangle ABC$ using sine rule, we get
$$fracsin (135-x) 3=fracsin x AB=fracsin 45 AC$$
So equating $AB$ from this two equations we get
$$fracsin (135-x) sin x =frac3sin 15 sin 120$$
Then I'm stuck.
So from $triangle ADB$ using sine rule, we get
$$fracsin 15 1=fracsin 120 AB=fracsin 45 AD$$
Similarly from $triangle ABC$ using sine rule, we get
$$fracsin (135-x) 3=fracsin x AB=fracsin 45 AC$$
So equating $AB$ from this two equations we get
$$fracsin (135-x) sin x =frac3sin 15 sin 120$$
Then I'm stuck.
answered Jul 25 at 9:48
R DE
415
415
1
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
1
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
add a comment |Â
1
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
1
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
1
1
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
Do you know $sin(x-y)=sin xcos y-cos xsin y$?
– Empy2
Jul 25 at 9:59
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
@Empy2 yes. how can I handle $#sin 15$?
– R DE
Jul 25 at 10:09
1
1
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
$sin15=sin(45-30)$
– Empy2
Jul 25 at 10:31
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
@RDE Were you able to finish the problem with Empy2's hint?
– Robert Howard
2 days ago
add a comment |Â
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1
Why do you believe that $angle DAC = 30^circ$?
– Babelfish
Jul 25 at 7:48