how to proof combinatorial identity of hypergeometric distribution [closed]
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hypergeometric-function
closed as off-topic by John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos Aug 1 at 22:58
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enter image description here
How?
hypergeometric-function
closed as off-topic by John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos Aug 1 at 22:58
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
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Jul 30 at 11:46
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down vote
favorite
up vote
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down vote
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enter image description here
How?
hypergeometric-function
enter image description here
How?
hypergeometric-function
asked Jul 30 at 11:41


Plerng X
6
6
closed as off-topic by John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos Aug 1 at 22:58
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos
closed as off-topic by John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos Aug 1 at 22:58
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Lord Shark the Unknown, Isaac Browne, Mostafa Ayaz, José Carlos Santos
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
– José Carlos Santos
Jul 30 at 11:46
add a comment |Â
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
– José Carlos Santos
Jul 30 at 11:46
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
– José Carlos Santos
Jul 30 at 11:46
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
– José Carlos Santos
Jul 30 at 11:46
add a comment |Â
1 Answer
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This is indeed described by the following problem:
let we have N pairwise different balls for which we have separated K among them. Then for choosing $n$ from all the $N$ balls the possible ways are to choose $k$ from the $K$ divergent balls and the rest ($n-k$ balls) from the other unseparated balls for $k=0,1,cdots, n$.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
This is indeed described by the following problem:
let we have N pairwise different balls for which we have separated K among them. Then for choosing $n$ from all the $N$ balls the possible ways are to choose $k$ from the $K$ divergent balls and the rest ($n-k$ balls) from the other unseparated balls for $k=0,1,cdots, n$.
add a comment |Â
up vote
0
down vote
This is indeed described by the following problem:
let we have N pairwise different balls for which we have separated K among them. Then for choosing $n$ from all the $N$ balls the possible ways are to choose $k$ from the $K$ divergent balls and the rest ($n-k$ balls) from the other unseparated balls for $k=0,1,cdots, n$.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
This is indeed described by the following problem:
let we have N pairwise different balls for which we have separated K among them. Then for choosing $n$ from all the $N$ balls the possible ways are to choose $k$ from the $K$ divergent balls and the rest ($n-k$ balls) from the other unseparated balls for $k=0,1,cdots, n$.
This is indeed described by the following problem:
let we have N pairwise different balls for which we have separated K among them. Then for choosing $n$ from all the $N$ balls the possible ways are to choose $k$ from the $K$ divergent balls and the rest ($n-k$ balls) from the other unseparated balls for $k=0,1,cdots, n$.
answered Aug 1 at 18:02


Mostafa Ayaz
8,5023630
8,5023630
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add a comment |Â
Welcome to MSE. It is in your best interest that you type your questions (using MathJax) instead of posting links to pictures.
– José Carlos Santos
Jul 30 at 11:46