How to use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$ [closed]
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Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$
What are good strategies to figure out this question in Particular?
trigonometry
closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46
This question appears to be off-topic. The users who voted to close gave this specific reason:
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Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$
What are good strategies to figure out this question in Particular?
trigonometry
closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne
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Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25
Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50
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up vote
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down vote
favorite
Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$
What are good strategies to figure out this question in Particular?
trigonometry
Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$
What are good strategies to figure out this question in Particular?
trigonometry
edited Aug 6 at 4:28
Abhas Kumar Sinha
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asked Jul 30 at 8:21
laquishabonquiquithe3rd
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closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne
closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne
1
Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25
Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50
add a comment |Â
1
Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25
Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50
1
1
Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25
Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25
Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50
Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50
add a comment |Â
2 Answers
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Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$
Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$
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$$cos(2A)=1-2sin^2(A)$$
$$cos(pi /6)=1-2sin^2(pi /12)$$
$$1-2sin^2(pi /12)=frac sqrt 32$$
$$2sin^2(pi /12)=1-frac sqrt 32$$
$$
sin^2(pi /12)=frac 12-frac sqrt 34$$
$$sin(pi /12)=sqrt frac 12-frac sqrt 34$$
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2 Answers
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$
Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$
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Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$
Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$
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up vote
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up vote
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Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$
Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$
Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$
Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$
answered Jul 30 at 8:57
LJFan
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$$cos(2A)=1-2sin^2(A)$$
$$cos(pi /6)=1-2sin^2(pi /12)$$
$$1-2sin^2(pi /12)=frac sqrt 32$$
$$2sin^2(pi /12)=1-frac sqrt 32$$
$$
sin^2(pi /12)=frac 12-frac sqrt 34$$
$$sin(pi /12)=sqrt frac 12-frac sqrt 34$$
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up vote
0
down vote
$$cos(2A)=1-2sin^2(A)$$
$$cos(pi /6)=1-2sin^2(pi /12)$$
$$1-2sin^2(pi /12)=frac sqrt 32$$
$$2sin^2(pi /12)=1-frac sqrt 32$$
$$
sin^2(pi /12)=frac 12-frac sqrt 34$$
$$sin(pi /12)=sqrt frac 12-frac sqrt 34$$
add a comment |Â
up vote
0
down vote
up vote
0
down vote
$$cos(2A)=1-2sin^2(A)$$
$$cos(pi /6)=1-2sin^2(pi /12)$$
$$1-2sin^2(pi /12)=frac sqrt 32$$
$$2sin^2(pi /12)=1-frac sqrt 32$$
$$
sin^2(pi /12)=frac 12-frac sqrt 34$$
$$sin(pi /12)=sqrt frac 12-frac sqrt 34$$
$$cos(2A)=1-2sin^2(A)$$
$$cos(pi /6)=1-2sin^2(pi /12)$$
$$1-2sin^2(pi /12)=frac sqrt 32$$
$$2sin^2(pi /12)=1-frac sqrt 32$$
$$
sin^2(pi /12)=frac 12-frac sqrt 34$$
$$sin(pi /12)=sqrt frac 12-frac sqrt 34$$
answered Jul 30 at 10:04


Mohammad Riazi-Kermani
27.3k41851
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1
Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25
Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50