How to use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$ [closed]

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Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$



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closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46


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    Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
    – Claude Leibovici
    Jul 30 at 8:25











  • Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
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    Jul 30 at 9:50














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Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$



What are good strategies to figure out this question in Particular?







share|cite|improve this question













closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
    – Claude Leibovici
    Jul 30 at 8:25











  • Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
    – N. F. Taussig
    Jul 30 at 9:50












up vote
0
down vote

favorite









up vote
0
down vote

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Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$



What are good strategies to figure out this question in Particular?







share|cite|improve this question













Question: Use the trigonometric identity $cos(2A)=1-2sin^2(A)$ to show that $$sinleft(fracpi12right)=sqrtfrac12 - fracsqrt34$$



What are good strategies to figure out this question in Particular?









share|cite|improve this question












share|cite|improve this question




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edited Aug 6 at 4:28









Abhas Kumar Sinha

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asked Jul 30 at 8:21









laquishabonquiquithe3rd

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closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne Jul 30 at 19:46


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Delta-u, amWhy, Rhys Steele, Mostafa Ayaz, Isaac Browne
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 1




    Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
    – Claude Leibovici
    Jul 30 at 8:25











  • Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
    – N. F. Taussig
    Jul 30 at 9:50












  • 1




    Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
    – Claude Leibovici
    Jul 30 at 8:25











  • Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
    – N. F. Taussig
    Jul 30 at 9:50







1




1




Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25





Make $2A=frac pi 6$ to compute $sin^2(A)$ and then ???
– Claude Leibovici
Jul 30 at 8:25













Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50




Welcome to MathSE. Please read this tutorial on how to typeset mathematics on this site.
– N. F. Taussig
Jul 30 at 9:50










2 Answers
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Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$



Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$






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    $$cos(2A)=1-2sin^2(A)$$



    $$cos(pi /6)=1-2sin^2(pi /12)$$



    $$1-2sin^2(pi /12)=frac sqrt 32$$



    $$2sin^2(pi /12)=1-frac sqrt 32$$
    $$
    sin^2(pi /12)=frac 12-frac sqrt 34$$
    $$sin(pi /12)=sqrt frac 12-frac sqrt 34$$






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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      1
      down vote













      Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$



      Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$






      share|cite|improve this answer

























        up vote
        1
        down vote













        Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$



        Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$






        share|cite|improve this answer























          up vote
          1
          down vote










          up vote
          1
          down vote









          Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$



          Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$






          share|cite|improve this answer













          Use the trigonemetric identity, we get $sinA=pmsqrtfrac1-cos2A2$



          Substitute $A=fracpi12$ in it, we can easily find that $sin A>0$. Therefore $sinfracpi12=sqrtfrac1-cosfracpi62=sqrtfrac1-fracsqrt322=sqrtfrac12-fracsqrt34$







          share|cite|improve this answer













          share|cite|improve this answer



          share|cite|improve this answer











          answered Jul 30 at 8:57









          LJFan

          112




          112




















              up vote
              0
              down vote













              $$cos(2A)=1-2sin^2(A)$$



              $$cos(pi /6)=1-2sin^2(pi /12)$$



              $$1-2sin^2(pi /12)=frac sqrt 32$$



              $$2sin^2(pi /12)=1-frac sqrt 32$$
              $$
              sin^2(pi /12)=frac 12-frac sqrt 34$$
              $$sin(pi /12)=sqrt frac 12-frac sqrt 34$$






              share|cite|improve this answer

























                up vote
                0
                down vote













                $$cos(2A)=1-2sin^2(A)$$



                $$cos(pi /6)=1-2sin^2(pi /12)$$



                $$1-2sin^2(pi /12)=frac sqrt 32$$



                $$2sin^2(pi /12)=1-frac sqrt 32$$
                $$
                sin^2(pi /12)=frac 12-frac sqrt 34$$
                $$sin(pi /12)=sqrt frac 12-frac sqrt 34$$






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  $$cos(2A)=1-2sin^2(A)$$



                  $$cos(pi /6)=1-2sin^2(pi /12)$$



                  $$1-2sin^2(pi /12)=frac sqrt 32$$



                  $$2sin^2(pi /12)=1-frac sqrt 32$$
                  $$
                  sin^2(pi /12)=frac 12-frac sqrt 34$$
                  $$sin(pi /12)=sqrt frac 12-frac sqrt 34$$






                  share|cite|improve this answer













                  $$cos(2A)=1-2sin^2(A)$$



                  $$cos(pi /6)=1-2sin^2(pi /12)$$



                  $$1-2sin^2(pi /12)=frac sqrt 32$$



                  $$2sin^2(pi /12)=1-frac sqrt 32$$
                  $$
                  sin^2(pi /12)=frac 12-frac sqrt 34$$
                  $$sin(pi /12)=sqrt frac 12-frac sqrt 34$$







                  share|cite|improve this answer













                  share|cite|improve this answer



                  share|cite|improve this answer











                  answered Jul 30 at 10:04









                  Mohammad Riazi-Kermani

                  27.3k41851




                  27.3k41851












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