Solving Complex Numbers Equation [on hold]

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I need to solve an equation of complex numbers, couldn't do it so I watched a video and couldn't understand how he got from this, Z is a complex number: $$(Z-1)^2-(overline Z-1)^2$$
to this : $$(Z-1+overline Z -1)(Z-1-overline Z+1)$$



It'll be really helpful if you can point me on how he did this, thank you.




complex-numbers




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put on hold as off-topic by user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 4




    Use identity $a^2-b^2=(a+b)(a-b)$
    – user 108128
    2 days ago










  • What's with the close votes?
    – Jack M
    2 days ago














up vote
0
down vote

favorite












]



I need to solve an equation of complex numbers, couldn't do it so I watched a video and couldn't understand how he got from this, Z is a complex number: $$(Z-1)^2-(overline Z-1)^2$$
to this : $$(Z-1+overline Z -1)(Z-1-overline Z+1)$$



It'll be really helpful if you can point me on how he did this, thank you.




complex-numbers




share|cite|improve this question











put on hold as off-topic by user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 4




    Use identity $a^2-b^2=(a+b)(a-b)$
    – user 108128
    2 days ago










  • What's with the close votes?
    – Jack M
    2 days ago












up vote
0
down vote

favorite









up vote
0
down vote

favorite











]



I need to solve an equation of complex numbers, couldn't do it so I watched a video and couldn't understand how he got from this, Z is a complex number: $$(Z-1)^2-(overline Z-1)^2$$
to this : $$(Z-1+overline Z -1)(Z-1-overline Z+1)$$



It'll be really helpful if you can point me on how he did this, thank you.




complex-numbers




share|cite|improve this question











]



I need to solve an equation of complex numbers, couldn't do it so I watched a video and couldn't understand how he got from this, Z is a complex number: $$(Z-1)^2-(overline Z-1)^2$$
to this : $$(Z-1+overline Z -1)(Z-1-overline Z+1)$$



It'll be really helpful if you can point me on how he did this, thank you.





complex-numbers





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share|cite|improve this question




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asked 2 days ago









AmitBL

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put on hold as off-topic by user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota
If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – user 108128, José Carlos Santos, Henrik, Claude Leibovici, farruhota
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 4




    Use identity $a^2-b^2=(a+b)(a-b)$
    – user 108128
    2 days ago










  • What's with the close votes?
    – Jack M
    2 days ago












  • 4




    Use identity $a^2-b^2=(a+b)(a-b)$
    – user 108128
    2 days ago










  • What's with the close votes?
    – Jack M
    2 days ago







4




4




Use identity $a^2-b^2=(a+b)(a-b)$
– user 108128
2 days ago




Use identity $a^2-b^2=(a+b)(a-b)$
– user 108128
2 days ago












What's with the close votes?
– Jack M
2 days ago




What's with the close votes?
– Jack M
2 days ago










1 Answer
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Use the identity $a^2-b^2=(a+b)(a-b)$.






share|cite|improve this answer




























    1 Answer
    1






    active

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    1 Answer
    1






    active

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    active

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    active

    oldest

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    up vote
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    down vote













    Use the identity $a^2-b^2=(a+b)(a-b)$.






    share|cite|improve this answer

























      up vote
      1
      down vote













      Use the identity $a^2-b^2=(a+b)(a-b)$.






      share|cite|improve this answer























        up vote
        1
        down vote










        up vote
        1
        down vote









        Use the identity $a^2-b^2=(a+b)(a-b)$.






        share|cite|improve this answer













        Use the identity $a^2-b^2=(a+b)(a-b)$.







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered 2 days ago









        Jack M

        16.9k33473




        16.9k33473












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