System of linear equations with constants appended [closed]

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How do you solve for $x$ and $y$, when there is a constant tagged on? $u, w, a, b, c, d$ are known.



$$
begincases
u = a x + b y + 1,\
w = c x + d y + 1.
endcases
$$







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closed as off-topic by Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone Jul 24 at 11:01


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    c,d as well? $$
    – Ian
    Jul 24 at 4:49






  • 1




    If $u$ and $w$ are known, then they’re also constants. Move all of the constant terms to one side and solve as usual.
    – amd
    Jul 24 at 5:27














up vote
-2
down vote

favorite












How do you solve for $x$ and $y$, when there is a constant tagged on? $u, w, a, b, c, d$ are known.



$$
begincases
u = a x + b y + 1,\
w = c x + d y + 1.
endcases
$$







share|cite|improve this question













closed as off-topic by Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone Jul 24 at 11:01


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    c,d as well? $$
    – Ian
    Jul 24 at 4:49






  • 1




    If $u$ and $w$ are known, then they’re also constants. Move all of the constant terms to one side and solve as usual.
    – amd
    Jul 24 at 5:27












up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











How do you solve for $x$ and $y$, when there is a constant tagged on? $u, w, a, b, c, d$ are known.



$$
begincases
u = a x + b y + 1,\
w = c x + d y + 1.
endcases
$$







share|cite|improve this question













How do you solve for $x$ and $y$, when there is a constant tagged on? $u, w, a, b, c, d$ are known.



$$
begincases
u = a x + b y + 1,\
w = c x + d y + 1.
endcases
$$









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 24 at 5:16









Anton Grudkin

2,111719




2,111719









asked Jul 24 at 4:48









ina

2501213




2501213




closed as off-topic by Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone Jul 24 at 11:01


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone Jul 24 at 11:01


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Parcly Taxel, Leucippus, Taroccoesbrocco, José Carlos Santos, Tyrone
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 2




    c,d as well? $$
    – Ian
    Jul 24 at 4:49






  • 1




    If $u$ and $w$ are known, then they’re also constants. Move all of the constant terms to one side and solve as usual.
    – amd
    Jul 24 at 5:27












  • 2




    c,d as well? $$
    – Ian
    Jul 24 at 4:49






  • 1




    If $u$ and $w$ are known, then they’re also constants. Move all of the constant terms to one side and solve as usual.
    – amd
    Jul 24 at 5:27







2




2




c,d as well? $$
– Ian
Jul 24 at 4:49




c,d as well? $$
– Ian
Jul 24 at 4:49




1




1




If $u$ and $w$ are known, then they’re also constants. Move all of the constant terms to one side and solve as usual.
– amd
Jul 24 at 5:27




If $u$ and $w$ are known, then they’re also constants. Move all of the constant terms to one side and solve as usual.
– amd
Jul 24 at 5:27










1 Answer
1






active

oldest

votes

















up vote
2
down vote













Why not the usual
$$
beginpmatrix
a & b\
c & d
endpmatrix^-1
beginpmatrixu-1 \ w-1endpmatrix
$$






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote













    Why not the usual
    $$
    beginpmatrix
    a & b\
    c & d
    endpmatrix^-1
    beginpmatrixu-1 \ w-1endpmatrix
    $$






    share|cite|improve this answer

























      up vote
      2
      down vote













      Why not the usual
      $$
      beginpmatrix
      a & b\
      c & d
      endpmatrix^-1
      beginpmatrixu-1 \ w-1endpmatrix
      $$






      share|cite|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        Why not the usual
        $$
        beginpmatrix
        a & b\
        c & d
        endpmatrix^-1
        beginpmatrixu-1 \ w-1endpmatrix
        $$






        share|cite|improve this answer













        Why not the usual
        $$
        beginpmatrix
        a & b\
        c & d
        endpmatrix^-1
        beginpmatrixu-1 \ w-1endpmatrix
        $$







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 24 at 4:59









        gt6989b

        30.3k22148




        30.3k22148












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