The solution of Abel's equation of the first kind

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Solving a problem I was faced with an Abel's equation of the first kind as



$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$ where $a,b$ and $k$ are nonzero constant and $W=b+asin kx$. I also know that $y(0)=1-b$.



I searched the Web and read some papers, however there are some solutions for some particular cases which do not contain my case.



Any ideas about finding either an analytical solution or numerical?







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  • sorry I forgot to write =0 :)
    – Majid
    Jul 17 at 13:44














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Solving a problem I was faced with an Abel's equation of the first kind as



$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$ where $a,b$ and $k$ are nonzero constant and $W=b+asin kx$. I also know that $y(0)=1-b$.



I searched the Web and read some papers, however there are some solutions for some particular cases which do not contain my case.



Any ideas about finding either an analytical solution or numerical?







share|cite|improve this question





















  • sorry I forgot to write =0 :)
    – Majid
    Jul 17 at 13:44












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Solving a problem I was faced with an Abel's equation of the first kind as



$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$ where $a,b$ and $k$ are nonzero constant and $W=b+asin kx$. I also know that $y(0)=1-b$.



I searched the Web and read some papers, however there are some solutions for some particular cases which do not contain my case.



Any ideas about finding either an analytical solution or numerical?







share|cite|improve this question













Solving a problem I was faced with an Abel's equation of the first kind as



$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$ where $a,b$ and $k$ are nonzero constant and $W=b+asin kx$. I also know that $y(0)=1-b$.



I searched the Web and read some papers, however there are some solutions for some particular cases which do not contain my case.



Any ideas about finding either an analytical solution or numerical?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 17 at 13:44
























asked Jul 16 at 20:53









Majid

1,8521923




1,8521923











  • sorry I forgot to write =0 :)
    – Majid
    Jul 17 at 13:44
















  • sorry I forgot to write =0 :)
    – Majid
    Jul 17 at 13:44















sorry I forgot to write =0 :)
– Majid
Jul 17 at 13:44




sorry I forgot to write =0 :)
– Majid
Jul 17 at 13:44










1 Answer
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$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$
$$y'-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$$
Change of variable: $quad t=asin(kx)+b-1,$



$fracdydx=fracdydtfracdtdx=akcos(kx)fracdydt$



$akcos(kx)fracdydt-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$
$$fracdydt-y^3-t=0$$



Of course, this is still an Abel's ODE, but much simpler than the original one : There is no parameter in it.



Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.






share|cite|improve this answer























  • JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
    – Majid
    Jul 17 at 14:00










  • @Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
    – JJacquelin
    Jul 17 at 14:55










  • Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
    – Majid
    Jul 17 at 19:47











  • Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
    – JJacquelin
    Jul 19 at 10:41










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$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$
$$y'-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$$
Change of variable: $quad t=asin(kx)+b-1,$



$fracdydx=fracdydtfracdtdx=akcos(kx)fracdydt$



$akcos(kx)fracdydt-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$
$$fracdydt-y^3-t=0$$



Of course, this is still an Abel's ODE, but much simpler than the original one : There is no parameter in it.



Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.






share|cite|improve this answer























  • JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
    – Majid
    Jul 17 at 14:00










  • @Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
    – JJacquelin
    Jul 17 at 14:55










  • Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
    – Majid
    Jul 17 at 19:47











  • Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
    – JJacquelin
    Jul 19 at 10:41














up vote
2
down vote













$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$
$$y'-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$$
Change of variable: $quad t=asin(kx)+b-1,$



$fracdydx=fracdydtfracdtdx=akcos(kx)fracdydt$



$akcos(kx)fracdydt-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$
$$fracdydt-y^3-t=0$$



Of course, this is still an Abel's ODE, but much simpler than the original one : There is no parameter in it.



Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.






share|cite|improve this answer























  • JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
    – Majid
    Jul 17 at 14:00










  • @Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
    – JJacquelin
    Jul 17 at 14:55










  • Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
    – Majid
    Jul 17 at 19:47











  • Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
    – JJacquelin
    Jul 19 at 10:41












up vote
2
down vote










up vote
2
down vote









$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$
$$y'-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$$
Change of variable: $quad t=asin(kx)+b-1,$



$fracdydx=fracdydtfracdtdx=akcos(kx)fracdydt$



$akcos(kx)fracdydt-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$
$$fracdydt-y^3-t=0$$



Of course, this is still an Abel's ODE, but much simpler than the original one : There is no parameter in it.



Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.






share|cite|improve this answer















$$y'-(akcos kx)y^3+(1-W)akcos kx=0,$$
$$y'-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$$
Change of variable: $quad t=asin(kx)+b-1,$



$fracdydx=fracdydtfracdtdx=akcos(kx)fracdydt$



$akcos(kx)fracdydt-akcos(kx)y^3+(1-b-asin(kx))akcos(kx)=0$
$$fracdydt-y^3-t=0$$



Of course, this is still an Abel's ODE, but much simpler than the original one : There is no parameter in it.



Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.







share|cite|improve this answer















share|cite|improve this answer



share|cite|improve this answer








edited Jul 17 at 13:49


























answered Jul 17 at 7:13









JJacquelin

40.1k21649




40.1k21649











  • JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
    – Majid
    Jul 17 at 14:00










  • @Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
    – JJacquelin
    Jul 17 at 14:55










  • Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
    – Majid
    Jul 17 at 19:47











  • Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
    – JJacquelin
    Jul 19 at 10:41
















  • JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
    – Majid
    Jul 17 at 14:00










  • @Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
    – JJacquelin
    Jul 17 at 14:55










  • Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
    – Majid
    Jul 17 at 19:47











  • Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
    – JJacquelin
    Jul 19 at 10:41















JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
– Majid
Jul 17 at 14:00




JJacquelin this is the canonical form of Abel. Right? There are some papers that gave some solutions for some cases of Abel. I am wondering if there is not anything related to this one. As you mentioned it is much simpler now
– Majid
Jul 17 at 14:00












@Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
– JJacquelin
Jul 17 at 14:55




@Majid.I suggest this paper : arxiv.org/ftp/arxiv/papers/1503/1503.05929.pdf . Sorry, I have not enough available time just now. Good luck.
– JJacquelin
Jul 17 at 14:55












Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
– Majid
Jul 17 at 19:47





Thank you for your time! In this paper a solution is suggested for a restricted first kind of Abel. Moreover I do not know how to write this equation as the Eq. (3) suggested in this paper. Any suggestion?
– Majid
Jul 17 at 19:47













Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
– JJacquelin
Jul 19 at 10:41




Apparently, this is not a solvable case in terms of standard special functions. So, it is suggested to continue thanks to numerical method.
– JJacquelin
Jul 19 at 10:41












 

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