What is the meaning of $|f-g|_infty$? [closed]

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Let $I subseteq mathbbR$ be a bounded interval and let $f;g in C[I]$.



Is $|f-g|_infty:=rho (f;g):=undersetx in Imathrmmax |(f-g)(x)|$, the maximum distance between $f$ and $g$ on $I$?







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closed as off-topic by Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel Jul 17 at 3:11


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 3




    en.wikipedia.org/wiki/Function_space#Norm
    – Holo
    Jul 16 at 20:13










  • Is $I$ a closed interval? If not, then $maxxin I |(f-g)(x)|$ may not exist.
    – Xander Henderson
    Jul 16 at 20:16














up vote
0
down vote

favorite












Let $I subseteq mathbbR$ be a bounded interval and let $f;g in C[I]$.



Is $|f-g|_infty:=rho (f;g):=undersetx in Imathrmmax |(f-g)(x)|$, the maximum distance between $f$ and $g$ on $I$?







share|cite|improve this question













closed as off-topic by Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel Jul 17 at 3:11


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 3




    en.wikipedia.org/wiki/Function_space#Norm
    – Holo
    Jul 16 at 20:13










  • Is $I$ a closed interval? If not, then $maxxin I |(f-g)(x)|$ may not exist.
    – Xander Henderson
    Jul 16 at 20:16












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Let $I subseteq mathbbR$ be a bounded interval and let $f;g in C[I]$.



Is $|f-g|_infty:=rho (f;g):=undersetx in Imathrmmax |(f-g)(x)|$, the maximum distance between $f$ and $g$ on $I$?







share|cite|improve this question













Let $I subseteq mathbbR$ be a bounded interval and let $f;g in C[I]$.



Is $|f-g|_infty:=rho (f;g):=undersetx in Imathrmmax |(f-g)(x)|$, the maximum distance between $f$ and $g$ on $I$?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 16 at 20:14









Xander Henderson

13.1k83150




13.1k83150









asked Jul 16 at 20:10









Mario 04

6013




6013




closed as off-topic by Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel Jul 17 at 3:11


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel Jul 17 at 3:11


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Xander Henderson, José Carlos Santos, Adrian Keister, Trần Thúc Minh Trí, Parcly Taxel
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 3




    en.wikipedia.org/wiki/Function_space#Norm
    – Holo
    Jul 16 at 20:13










  • Is $I$ a closed interval? If not, then $maxxin I |(f-g)(x)|$ may not exist.
    – Xander Henderson
    Jul 16 at 20:16












  • 3




    en.wikipedia.org/wiki/Function_space#Norm
    – Holo
    Jul 16 at 20:13










  • Is $I$ a closed interval? If not, then $maxxin I |(f-g)(x)|$ may not exist.
    – Xander Henderson
    Jul 16 at 20:16







3




3




en.wikipedia.org/wiki/Function_space#Norm
– Holo
Jul 16 at 20:13




en.wikipedia.org/wiki/Function_space#Norm
– Holo
Jul 16 at 20:13












Is $I$ a closed interval? If not, then $maxxin I |(f-g)(x)|$ may not exist.
– Xander Henderson
Jul 16 at 20:16




Is $I$ a closed interval? If not, then $maxxin I |(f-g)(x)|$ may not exist.
– Xander Henderson
Jul 16 at 20:16










1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










It would be
$$
sup_xin I|f(x)-g(x)|
$$
Note that we take the $sup $ since we have no guarantee that the max will exist ($I$ may not be closed).






share|cite|improve this answer





















  • While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
    – Xander Henderson
    Jul 16 at 20:18











  • By "meaning" I meant the definition.
    – Mario 04
    Jul 16 at 20:44

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










It would be
$$
sup_xin I|f(x)-g(x)|
$$
Note that we take the $sup $ since we have no guarantee that the max will exist ($I$ may not be closed).






share|cite|improve this answer





















  • While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
    – Xander Henderson
    Jul 16 at 20:18











  • By "meaning" I meant the definition.
    – Mario 04
    Jul 16 at 20:44














up vote
2
down vote



accepted










It would be
$$
sup_xin I|f(x)-g(x)|
$$
Note that we take the $sup $ since we have no guarantee that the max will exist ($I$ may not be closed).






share|cite|improve this answer





















  • While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
    – Xander Henderson
    Jul 16 at 20:18











  • By "meaning" I meant the definition.
    – Mario 04
    Jul 16 at 20:44












up vote
2
down vote



accepted







up vote
2
down vote



accepted






It would be
$$
sup_xin I|f(x)-g(x)|
$$
Note that we take the $sup $ since we have no guarantee that the max will exist ($I$ may not be closed).






share|cite|improve this answer













It would be
$$
sup_xin I|f(x)-g(x)|
$$
Note that we take the $sup $ since we have no guarantee that the max will exist ($I$ may not be closed).







share|cite|improve this answer













share|cite|improve this answer



share|cite|improve this answer











answered Jul 16 at 20:14









Foobaz John

18.1k41245




18.1k41245











  • While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
    – Xander Henderson
    Jul 16 at 20:18











  • By "meaning" I meant the definition.
    – Mario 04
    Jul 16 at 20:44
















  • While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
    – Xander Henderson
    Jul 16 at 20:18











  • By "meaning" I meant the definition.
    – Mario 04
    Jul 16 at 20:44















While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
– Xander Henderson
Jul 16 at 20:18





While this is a correct statement, I don't see how this answers the question, which asks about the meaning of $|f-g|_infty$.
– Xander Henderson
Jul 16 at 20:18













By "meaning" I meant the definition.
– Mario 04
Jul 16 at 20:44




By "meaning" I meant the definition.
– Mario 04
Jul 16 at 20:44


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