What is the spatial distance, according to G?

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Question




Suppose the events $E_1$ and $E_2$ have the coordinates $(1,0)$ and
$(2, 0)$ in R. What is the spatial distance between them,
according to R? What is the spatial distance, according to G?




My Attempt:-



I have drawn a space-time graph. I think in the question $x,y$ and $xi,eta$ cordinates are kept constant. Am I correct? $E_1$ and $E_2$ with respect to $R$ is given by $(t=1,z=0)$ and $(t=2, z=0)$. Hence the spacial distance between the events are $0$. $E_1$ and $E_2$ with respect to $G$ is given by $(tau=1,zeta=-v)$ and $(tau=2, zeta=-2v)$. Hence spacial distance between the events are $v$. Am I correct?
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Did I understand the concept correctly? I request you to verify my
understanding.





proof-verification classical-mechanics special-relativity




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  • Maybe you should try this on Physics SE…?
    – xbh
    Jul 30 at 14:47






  • 1




    I won't get any help. this question is seems to be homework problem for their site :(
    – N. Maneesh
    Jul 30 at 14:49










  • I really wanted to understand about th universe. I have just started relativity. I don't know whether my understandings are correct or not.
    – N. Maneesh
    Jul 30 at 14:50














up vote
0
down vote

favorite












enter image description here



Question




Suppose the events $E_1$ and $E_2$ have the coordinates $(1,0)$ and
$(2, 0)$ in R. What is the spatial distance between them,
according to R? What is the spatial distance, according to G?




My Attempt:-



I have drawn a space-time graph. I think in the question $x,y$ and $xi,eta$ cordinates are kept constant. Am I correct? $E_1$ and $E_2$ with respect to $R$ is given by $(t=1,z=0)$ and $(t=2, z=0)$. Hence the spacial distance between the events are $0$. $E_1$ and $E_2$ with respect to $G$ is given by $(tau=1,zeta=-v)$ and $(tau=2, zeta=-2v)$. Hence spacial distance between the events are $v$. Am I correct?
enter image description here




Did I understand the concept correctly? I request you to verify my
understanding.





proof-verification classical-mechanics special-relativity




share|cite|improve this question



















  • Maybe you should try this on Physics SE…?
    – xbh
    Jul 30 at 14:47






  • 1




    I won't get any help. this question is seems to be homework problem for their site :(
    – N. Maneesh
    Jul 30 at 14:49










  • I really wanted to understand about th universe. I have just started relativity. I don't know whether my understandings are correct or not.
    – N. Maneesh
    Jul 30 at 14:50












up vote
0
down vote

favorite









up vote
0
down vote

favorite











enter image description here



Question




Suppose the events $E_1$ and $E_2$ have the coordinates $(1,0)$ and
$(2, 0)$ in R. What is the spatial distance between them,
according to R? What is the spatial distance, according to G?




My Attempt:-



I have drawn a space-time graph. I think in the question $x,y$ and $xi,eta$ cordinates are kept constant. Am I correct? $E_1$ and $E_2$ with respect to $R$ is given by $(t=1,z=0)$ and $(t=2, z=0)$. Hence the spacial distance between the events are $0$. $E_1$ and $E_2$ with respect to $G$ is given by $(tau=1,zeta=-v)$ and $(tau=2, zeta=-2v)$. Hence spacial distance between the events are $v$. Am I correct?
enter image description here




Did I understand the concept correctly? I request you to verify my
understanding.





proof-verification classical-mechanics special-relativity




share|cite|improve this question











enter image description here



Question




Suppose the events $E_1$ and $E_2$ have the coordinates $(1,0)$ and
$(2, 0)$ in R. What is the spatial distance between them,
according to R? What is the spatial distance, according to G?




My Attempt:-



I have drawn a space-time graph. I think in the question $x,y$ and $xi,eta$ cordinates are kept constant. Am I correct? $E_1$ and $E_2$ with respect to $R$ is given by $(t=1,z=0)$ and $(t=2, z=0)$. Hence the spacial distance between the events are $0$. $E_1$ and $E_2$ with respect to $G$ is given by $(tau=1,zeta=-v)$ and $(tau=2, zeta=-2v)$. Hence spacial distance between the events are $v$. Am I correct?
enter image description here




Did I understand the concept correctly? I request you to verify my
understanding.






proof-verification classical-mechanics special-relativity





share|cite|improve this question










share|cite|improve this question




share|cite|improve this question









asked Jul 30 at 14:43









N. Maneesh

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  • Maybe you should try this on Physics SE…?
    – xbh
    Jul 30 at 14:47






  • 1




    I won't get any help. this question is seems to be homework problem for their site :(
    – N. Maneesh
    Jul 30 at 14:49










  • I really wanted to understand about th universe. I have just started relativity. I don't know whether my understandings are correct or not.
    – N. Maneesh
    Jul 30 at 14:50
















  • Maybe you should try this on Physics SE…?
    – xbh
    Jul 30 at 14:47






  • 1




    I won't get any help. this question is seems to be homework problem for their site :(
    – N. Maneesh
    Jul 30 at 14:49










  • I really wanted to understand about th universe. I have just started relativity. I don't know whether my understandings are correct or not.
    – N. Maneesh
    Jul 30 at 14:50















Maybe you should try this on Physics SE…?
– xbh
Jul 30 at 14:47




Maybe you should try this on Physics SE…?
– xbh
Jul 30 at 14:47




1




1




I won't get any help. this question is seems to be homework problem for their site :(
– N. Maneesh
Jul 30 at 14:49




I won't get any help. this question is seems to be homework problem for their site :(
– N. Maneesh
Jul 30 at 14:49












I really wanted to understand about th universe. I have just started relativity. I don't know whether my understandings are correct or not.
– N. Maneesh
Jul 30 at 14:50




I really wanted to understand about th universe. I have just started relativity. I don't know whether my understandings are correct or not.
– N. Maneesh
Jul 30 at 14:50















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