Anti-derivative with velocity

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a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32



1-what does the velocity function?



2-what is the position function?



3-how long does it take for ball to return to the ground?



my answer is



1- $v(t)=-32t+c$



$96=-32(0)+c$ so $c=96$



2-$s(t)=-16t^2+96t+c$



3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?



Any help will be helpful?







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  • It's correct...
    – user 108128
    Jul 31 at 5:04














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down vote

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a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32



1-what does the velocity function?



2-what is the position function?



3-how long does it take for ball to return to the ground?



my answer is



1- $v(t)=-32t+c$



$96=-32(0)+c$ so $c=96$



2-$s(t)=-16t^2+96t+c$



3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?



Any help will be helpful?







share|cite|improve this question





















  • It's correct...
    – user 108128
    Jul 31 at 5:04












up vote
0
down vote

favorite









up vote
0
down vote

favorite











a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32



1-what does the velocity function?



2-what is the position function?



3-how long does it take for ball to return to the ground?



my answer is



1- $v(t)=-32t+c$



$96=-32(0)+c$ so $c=96$



2-$s(t)=-16t^2+96t+c$



3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?



Any help will be helpful?







share|cite|improve this question













a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32



1-what does the velocity function?



2-what is the position function?



3-how long does it take for ball to return to the ground?



my answer is



1- $v(t)=-32t+c$



$96=-32(0)+c$ so $c=96$



2-$s(t)=-16t^2+96t+c$



3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?



Any help will be helpful?









share|cite|improve this question












share|cite|improve this question




share|cite|improve this question








edited Jul 31 at 8:28









user 108128

18.9k41544




18.9k41544









asked Jul 31 at 4:53









gb2017

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62











  • It's correct...
    – user 108128
    Jul 31 at 5:04
















  • It's correct...
    – user 108128
    Jul 31 at 5:04















It's correct...
– user 108128
Jul 31 at 5:04




It's correct...
– user 108128
Jul 31 at 5:04










1 Answer
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Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$






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    1 Answer
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    Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$






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      up vote
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      down vote













      Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$






      share|cite|improve this answer























        up vote
        3
        down vote










        up vote
        3
        down vote









        Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$






        share|cite|improve this answer













        Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$







        share|cite|improve this answer













        share|cite|improve this answer



        share|cite|improve this answer











        answered Jul 31 at 5:00









        spaceisdarkgreen

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