Anti-derivative with velocity
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a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32
1-what does the velocity function?
2-what is the position function?
3-how long does it take for ball to return to the ground?
my answer is
1- $v(t)=-32t+c$
$96=-32(0)+c$ so $c=96$
2-$s(t)=-16t^2+96t+c$
3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?
Any help will be helpful?
calculus physics
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up vote
0
down vote
favorite
a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32
1-what does the velocity function?
2-what is the position function?
3-how long does it take for ball to return to the ground?
my answer is
1- $v(t)=-32t+c$
$96=-32(0)+c$ so $c=96$
2-$s(t)=-16t^2+96t+c$
3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?
Any help will be helpful?
calculus physics
It's correct...
– user 108128
Jul 31 at 5:04
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32
1-what does the velocity function?
2-what is the position function?
3-how long does it take for ball to return to the ground?
my answer is
1- $v(t)=-32t+c$
$96=-32(0)+c$ so $c=96$
2-$s(t)=-16t^2+96t+c$
3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?
Any help will be helpful?
calculus physics
a ball is thrown upward from the ground with speed of 96 ft/sec. Assuming that acceleration due to gravity is given by a(t)=-32
1-what does the velocity function?
2-what is the position function?
3-how long does it take for ball to return to the ground?
my answer is
1- $v(t)=-32t+c$
$96=-32(0)+c$ so $c=96$
2-$s(t)=-16t^2+96t+c$
3- when it returns to ground $s(t)=0$ Is this correct and how can I find C?
Any help will be helpful?
calculus physics
edited Jul 31 at 8:28
user 108128
18.9k41544
18.9k41544
asked Jul 31 at 4:53
gb2017
62
62
It's correct...
– user 108128
Jul 31 at 5:04
add a comment |Â
It's correct...
– user 108128
Jul 31 at 5:04
It's correct...
– user 108128
Jul 31 at 5:04
It's correct...
– user 108128
Jul 31 at 5:04
add a comment |Â
1 Answer
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Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$
add a comment |Â
up vote
3
down vote
Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$
add a comment |Â
up vote
3
down vote
up vote
3
down vote
Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$
Yes, it is correct that $s(t)=0$ when it returns to the ground (assuming you're defining zero to be the ground, which is the natural choice here). You are also assuming it is thrown from the ground, so that $s(0)=0.$ Plugging in $t=0$ gives $c=0.$ So to complete the problem, you just need to find the nonzero solution to $0=-16t^2+96t.$
answered Jul 31 at 5:00
spaceisdarkgreen
27.2k21546
27.2k21546
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add a comment |Â
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It's correct...
– user 108128
Jul 31 at 5:04